MATHEMATICS HIGH SCHOOL

The sum of a number and 18 times its reciprocal is 11. Find the number(s). Let x represent the unknown number. 
The Reciprocal of x is____?

Answers

Answer 1
Answer: i believe that n=-9?

sorry if im not right i just guessed based on an equation that i know for this stuff

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A character who changes during the course of the story is _____.flat
round
static
dynamic

Answers

A character who changes during the course of the story is a dynamic character.
Hope that helps! :) 

I would say dynamic is the answer.

What is the product of -9 and -15?
135
-135
-24
24

Answers

-9 * (-15) = 135
it's positive 135 because when you have negative time a negative it's always positive.

Answer:

Please mark me brainliest and I hope this helped!

135

Step-by-step explanation:

The product of something is what the outcome is when you multiply the numbers together. Since 9 and 15 are both negatives, they cancel each other out and become positives. Then we just multiply 9 and 15. That gives us 135.

What is the solution of the linear system of equations?


y=2x-3
y=2x+5

Answers

Hi Brainiac


y=2x-3

y= 2x+5


Ok we need to solve y=2x-3 for y

Now substitute 2x-3 for y in y=2x+5

y=2x+5

2x-3=2x+5

Add -2x

2x-3-2x=2x+5-2x

-3=5

Add 3

-3+3=5+3

0=8

No Solutions


I hope that's help:0

A triangle is placed in a semicircle with a radius of 4ftFind the area of the shaded region. Use the value 3.14 for π
, and do not round your answer. Be sure to include the correct unit in your answer.

Answers

I found 9.12 ft^(2)
I used the fact that the shaded area should be equal to the area of the semicircle minus the area of the triangle:

Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14 to decay to 10 percent of its original amount?

Answers

Answer:

Carbon-14 will take 19,035 years to decay to 10 percent.

Step-by-step explanation:

Exponential Decay Function

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

N(t)=N_(0)e^(-\lambda t)

Where:

No  = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

\lambda     = The decay constant.

One important parameter related to radioactive decay is the half-life:

\displaystyle t_(1/2)=\frac {\ln(2)}{\lambda }

If we know the value of the half-life, we can calculate the decay constant:

\displaystyle \lambda=\frac {\ln(2)}{ t_(1/2)}

Carbon-14 has a half-life of 5,730 years, thus:

\displaystyle \lambda=\frac {\ln(2)}{ 5,730}

\lambda=0.00012097

The equation of the remaining quantity of Carbon-14 is:

N(t)=N_(0)e^(-0.00012097\cdot t)

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

0.10N_o=N_(0)e^(-0.00012097\cdot t)

Simplifying:

0.10=e^(-0.00012097\cdot t)

Taking logarithms:

ln 0.10=-0.00012097\cdot t

Solving for t:

\displaystyle t=(log 0.10)/(-0.00012097)

t\approx 19,035\ years

Carbon-14 will take 19,035 years to decay to 10 percent.

Approximately 23,083 years will pass for carbon-14 to decay to 10 percent of its original amount.

To find out how long it will take for carbon-14 to decay to 10 percent of its original amount, we can use the concept of exponential decay. The formula for calculating the amount of a radioactive substance remaining after a certain time can be expressed as:

A(t) = A₀ * (1/2)ˣ/ₓ₂

Where:

A(t) is the amount of carbon-14 at time t

A₀ is the initial amount of carbon-14

t₁/₂ is the half-life of carbon-14 (5,730 years)

t is the time we want to find (in years)

We want to find t when A(t) is equal to 0.10 * A₀ (10 percent of the original amount). So, the equation becomes:

0.10 * A₀ = A₀ * (1/2)ˣ/₅₇₃₀

Now, we can cancel out A₀ on both sides of the equation:

0.10 = (1/2)ˣ/₅₇₃₀

To isolate t, we can take the logarithm of both sides (base 2) since the half-life is used in the equation:

log₂(0.10) = t / 5730

Now, we can solve for t:

t = 5730 * log₂(0.10)

To know more about decay here

brainly.com/question/2193799

#SPJ3

(9* 1010) - (4 * 1010) =
How to answer

Answers

For this you will utilize PEMDAS. So work what’s in the parenthesis first.

(9090) - (4040)

Then subtract both of them.

5050

Answer: 5050
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