What's 32 to the power of negative 2/5

Answers

Answer 1
Answer: 32^{-(2)/(5)}=\sqrt[5]{32}^(-2)=2^(-2)=((1)/(2))^2=(1)/(4)

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The original price of an electric scooter was $187.50. The scooter was on sale for $165. What was the discount rate?

Answers

so the origiinal price is 187.50 and the sale price was 165, so the discount is 187.50 - 165 = 22.5.

if we take 187.50 to be the 100%, what is 22.5 off of it in percentage?


\bf \begin{array}{ccll} amount&\%\n \cline{1-2} 187.5&100\n 22.5&x \end{array}\implies \cfrac{187.5}{22.5}=\cfrac{100}{x}\implies 187.5x=2250 \n\n\n x=\cfrac{2250}{187.5}\implies x=12

Answer: I got 12% after trial an error from 15% down to 12% when i got 165$


I know that y=20 and x=50 but will someone explain how to get them. Thanks!

Answers

given that A and B are parallel, you can conclude that 30 = x - y since they are corresponding angles. Also you can conclude that 5y = 2x since they are alternate interior angles. At this point, there is a solvable system of equations set up

30 = x - y

5y = 2x


Now, you must isolate a variable so let's isolate x from the 1st equation. so u just need to add y to both sides, getting x = 30 + y. Now you plug that into the 2nd equation and solve for y. 5y = 60 + 2y. Subtract 2y from both sides. 3y = 60. Divide by 3, y = 20.

Now with your y value, just plug back into original equation (the 1st one). 30 = x - 20. Solve for x by adding 20. X = 50

V= Bh/3 solve for h.

Answers

The equation \(h = (3V)/(B)\) gives the value of h in terms of V (volume) and B (base area) for the given equation \(V = (Bh)/(3)\).

Given equation: \(V = (Bh)/(3)\)

Step 1: Multiply both sides of the equation by 3 to isolate Bh:

\[3V = Bh\]

Step 2: Divide both sides of the equation by B to solve for h:

\[h = (3V)/(B)\]

So, the equation solved for h is:

\[h = (3V)/(B)\]

This gives you the value of h in terms of V (volume) and B (base area) for the given equation \(V = (Bh)/(3)\).

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Answer:

h=3v/b

Step-by-step explanation:

A catering service offers appetizers, main courses, and desserts. A banquet chairperson is to select appetizers, main courses, and desserts for a banquet. In how many ways can this be done?

Answers

(Number of appetizers) x (number of main courses) x (number of desserts)

Find the polynomial f(x) of degree 3 has the following zeros
9, 0, -7

Answers

Answer:

x³ - 2x² - 63x

Step-by-step explanation:

Zeroes = 9 , 0 , -7

Factors = (x - 9) x (x + 7)

Polynomial = x (x - 9)(x + 7)

Polynomial = x (x² -2x - 63)

= x³ - 2x² - 63x

Final answer:

To find the polynomial f(x) of degree 3 with zeros 9, 0, and -7, we can use the zero-product property. The polynomial can be written as f(x) = (x-9)(x-0)(x+7), which simplifies to f(x) = (x-9)(x)(x+7). Expanding the expression and multiplying the remaining factors, we obtain f(x) = x^3 - 2x^2 - 63x.

Explanation:

To find the polynomial f(x) of degree 3 with the given zeros 9, 0, and -7, we can use the zero-product property. This property states that if a polynomial has a zero a, then (x-a) is a factor of the polynomial. Therefore, the polynomial can be written as:

f(x) = (x-9)(x-0)(x+7)

Simplifying further, we get:

f(x) = (x-9)(x)(x+7)

Expanding this expression, we have:

f(x) = (x^2 - 9x)(x+7)

Finally, multiplying the remaining factors, we obtain the polynomial:

f(x) = x^3 + 7x^2 - 9x^2 - 63x

= x^3 - 2x^2 - 63x

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2x-y=4 find the slope of the graph

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The\ slope-intercept\ form:y=mx+b\n\nm-slope\nb-y-intercept\n\n2x-y=4\ \ \ \ /-2x\n\n-y=-2x+4\ \ \ \ \ /\cdot(-1)\n\ny=2x-4\n\nSlope:m=2
Change it to the form of y=mx+b where m = slope and b is the intercept. So to do this just move the x over, then you divide each side by -1, because the y is negative. So you finally get y=2x-4, the slope is 2!