Please explain your answer as well!

Answers

Answer 1

Answer: Class A     Class B
1 2 3 4 5 6 7 8       4     1 2
      2 3 4 9       5     9
      1 1 4 8       6 2 4 9
       1   7 1 5 7 8 8
      2 5   8 0 3 4 4 6 6 7
   0   9 2 2 5

Mode and Mean for Class A
Mode: 61
Mean: 57.8

Range and Median for Class B
Range: 54
Median: 78

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Please help! Super confused lol
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A school librarian can buy books at a 20% discount from the list price. One month she spent $72 for books. What was the list price value of the books? Is the answer $90?

Answers

Answer:

$\boxed{\sf \ \ YES \ \ }$

Step-by-step explanation:

Hello

let's say that the price of the book was x

the price after a 20% discount is x - 20%*x = x*(1-20%)=x*(1-.20)=0.8*x

and this is $72 so we can write that

0.8*x=72

and then divide by 0.8 both parts

x = 72/0.8=90

So the list price value of the book is $90

and we can verify as 90 - 20%*90 = 90 - 18 = 72

Hope this helps

I have a Triangle and I need to find the side BC?

Answers

Looking at this problem in the book, I'm guessing that you've been
introduced to a little bit of trigonometry. Or at least you've seen the
definitions of the trig functions of angles.

Do you remember the definition of either the sine or the cosine of an angle ?

In a right triangle, the sine of an acute angle is (opposite side) / (hypotenuse),
and the cosine of an acute angle is (adjacent side) / (hypotenuse).

Maybe you could use one of these to solve this problem, but first you'd need to
make sure that this is a right triangle.

Let's see . . . all three angles in any triangle always add up to 180 degrees.
We know two of the angles in this triangle ... 39 and 51 degrees.
How many degrees are left over for the third angle ?
180 - (39 + 51) = 180 - (90) = 90 degrees for the third angle.
It's a right triangle ! yay ! We can use sine or cosine if we want to.

Let's use the 51° angle.
The cosine of any angle is (adjacent side) / (hypotenuse) .
'BC' is the side adjacent to the 51° angle in the picture,
and the hypotenuse is 27 .

cosine(51°) = (side BC) / 27

Multiply each side of that equation by 27 :

Side-BC = (27) times cosine(51°)

Look up the cosine of 51° in a book or on your calculator.

Cosine(51°) = 0.62932 (rounded)

Side BC = (27) x (0.62932) = 16.992 (rounded)
============================================

You could just as easily have used the sine of 39° .
That would be (opposite side) / (hypotenuse) ... also (side-BC) / 27 .

20=8+v i dont know how to do this

Answers

20 = 8 + v equals v = 12.

First, subtract 8 from both sides. Your problem should look like: 20 - 8 = v
Second, simplify 20 - 8 to get 12. Your problem should look like: 12 = v.
Third, switch sides to get v = 12, which is the correct answer.

You subtract 8 from both sides so the answer is v=12

What is the volume of the square pyramid? Round to the nearest hundredth, if needed.5 in.
9 in.
9 in
0405 in 3
135 in. 3
675 in 3
75 in. 3

Answers

Answer:

The answer is 135 in 3.

Step-by-step explanation:

To find the volume of a square pyramid, first you need to find the base and height. In this case,

a = 9

h = 5

Now we use the formula (1/3 a^2 h) To find the volume.

I will use )( To show numbers being multiplied, example: 3)(4 = 12

=1/3)(9 cm^2)(5 cm

=1/3)(81 cm)( 5 cm

= 135 in. 3

Umm I think 0405 in 3?????

Solve for x.

3x - 5x + 8x + x = 42

A. 6
B. 7
C. 8

Answers

The answer would be "6" because you have to calculate the difference then calculate the sum, calculate the sum again, then divide both sides by 7 and that gives you 6.

Combine all alike x terms and you get 7x=42

Divide 7 on each side of equation

You get A.x=6

Hope I helpedd

Which of the following is a solution to the quadratic equation below? x^2+x-56=0

a.2
b.-55
c.-8
d.28

Answers

There are two solutions to that quadratic quation: -8 and 7, but as there is only one in answers, you need to pick C.