ohn and 3 friends are going out for pizza for lunch. They split one pizza and 4 large drinks. The pizza cost $13.00. After using a $6.00 gift certificate, they spend a total of $13.20. Write an equation to model this situation, and find the cost of one large drink.

Answers

Answer 1
Answer: 4 large drinks
The pizza cost $13.00
$6.00 gift certificate
d= cost of one drink

equation
4d + 13 - 6 = 13.20
4d + 7 = 13.2
4d = 6.2
d = 1.55

answer
the cost of one large drink is $1.55


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When y = x^2, which of the following expressions is
equivalent to –y ?

Answers

-y=-(x^2) because you multiply both sides by -1.

What is the value of 324?
a. 128
b. 18
c. 648
d. 1,048,576

Answers

The value of 324 is 1,048,576.

The answer is D) 1,048,576 ..... i took the pennfoster test and it was correct :))

ACTUALLY HELP LMFOAOAOAOA

Answers

Answers:

x = 141

y = 39

Explanation

Angle x and angle 141 are congruent because they are corresponding angles, and because the lines are parallel. Corresponding angles are in the same corner. In this case it's the northwest corner.

Angles x and y are supplementary. They glue together to get a straight line. Which means the angles add to 180.

x+y = 180

141+y = 180

y = 180-141

y = 39

Simplify sin(3x+13)=cos(4x)

Answers

Sin(3×+13)=sin(pi/2-4×)
3x+13 =pi/2 -4×          or 3×+13 =pi-pi/2 + 4×
7× = pi/2 - 13 +k2pi   or -× = pi/2 +k2pi
× = pi/14 - 13/7 k2pi/7   or X = -pi/2 + kpi

Suppose you need to know an equation of the tangent plane to a surface S at the point P(4, 1, 3). You don't have an equation for S but you know that the curves r₁(t) = 4 + 3t, 1 − t², 3 − 5t + t²r₂(u) = 3 + u², 2u³ − 1, 2u + 1 both lie on S. Find an equation of the tangent plane at P.

Answers

Answer:

30(x-4)-16(y-1)+18(z-3)

OR

30x-16y+18z=158

Step-by-step explanation:

In order to find the tangent plan equation at point P,you know that r₁(t) and r₂(u) lie on surface S, Find the vectors B₁(t)=(d)/(dt) \nr₁(t) and B₂(u)=(d)/(du)r₂(u)

B₁(t)=(d)/(dt)(4+3t, 1-t^(2),3-5t+t^(2)

B₁(t)=(3, -2t, -5+2t)

B₂(u)=(d)/(du)(3+u^(2), 2u^(3)-1, 2u+1)

B₂(u)=(2u, 6u^(2), 2)

Put t=0 in r₁(t), we will get:

r₁(t)=(4, 1, 3), it means it is on point P

Put u=1 in r₂(u), we will get:

r₂(u)=(4, 1, 3),  it means it is on point P

Put t=0 in B₁(t), we will get:

B₁(t)=(3,0,-5)

Put u=1 in B₂(u), we will get:

B₂(u)=(2,6,2)

So Plane Contains two vectors B₁(t) and B₂(u), For Normal Vectors to the plane Cross Product is:

B₁(t)xB₂(u)= (3,0,-5)x(2,6,2) [Cross Product]

B₁(t)xB₂(u)=(30,-16,18)

Equation will become:

30(x-4)-16(y-1)+18(z-3)

OR

30x-16y+18z=158

the measures of an exterior angle and the adjacent interior angle add p to 360 because they form a linear plane?

Answers

Sadly, I can't see the picture you're looking at as you make that statement.
But I'm pretty sure that when you combine an exterior angle with the interior
angle adjacent to it, you'll wind up with 180°, because they form a linear line.
There actually isn't any such thing as a linear plane.