Find the equation of the circle that satisfies the given conditions. Radius 2 and center (4, -7)?

Answers

Answer 1

Answer: $The\ equation\ of\ the\ circle:\n\n(x-a)^2+(y-b)^2=r^2\n\nwhere\n\ncenter:(a;\ b)\n\nradius:r$

$Center:(4;-7);\ radius:r=2\n\n(x-4)^2+(y+7)^2=2^2\n\n(x-4)^2+(y+7)^2=4$

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What is 94+60+2x, I need the answer like right now.

Answers

106x is the answer because you simply add x to the end total.

Answer:

2x+154 or 2(x+77)

Step-by-step explanation:

This is an expression as there is no equal sign. So you can't solve for x

Below is the graph of f9x0= 2in(x) how would you describe the graph of g(x) = 4in(x)?

Answers

Please, next time, please share the graph referred to in the problem statement.

You are comparing f(x)=2 ln x and g(x) = 4 ln x. The two graphs look the same, except that the amplitude (rise) in 4 ln x is exactly twice that in 2 ln x.

Thus, if 2 ln x = 3, 4 ln x = 2(3) = 6.

40,43,40,39,50,23 what is the median?

Answers

Median is the middle number, but since there is 6 numbers.
Put them in order first
23,39,40,40,43,50
Well in middle is 40 for both sides
So to solve median for this you'd add the two middle numbers together since there is even set of numbers.
40+40 =80 then divide by 2
80÷2=40
Median = 40
*Follow This Example for any other even sets of numbers for Median*

The median of this data set is 40. This is because when put in order from greatest to least the order is:
23, 39, 40, 40, 43, 50
So the middle number is 40.

What is the domain of the function f(x)=2x+5? A. all real numbers except 2
B. all real number
C. all real numbers except 5
D. all positive real numbers

Answers

the answer is all real numbers :)

Answer:

Step-by-step explanation:

All Real Numbers

William owns 57.2 acres of land. He plans to donate land so a nature reserve can be built, but still needs 35.2 acres for his farm. If the developer of the nature reserve wants to use 54% of the donated land for a botanical garden, how many acres will be used for the garden?

Answers

Answer: 11.88

Step-by-step explanation: Subtract 35.2 from 57.2. Take your answer from that and multiply it by 0.54.

A survey found that women’s heights are normally distributed with mean 63.8 in and a standard deviation 2.3 in. A branch of the military requires women’s heights to be between 58 in and 80 in.a. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too tall?
b. If this branch of the military changes the height requirements so that all women are eligible except the shortest 1% and the tallest 2%, what are the new height requirements?

The percentage of women who meet the height requirement is __%.

For the new height requirements, this branch of the military requires women’s heights to be at least __ in and at most __ in.

Answers

Answer:

a) 99.41% of women meeting the height requirement. There are not many women being denied the opportunity to join this branch of the military because they are too short or too tall.

b) The new requirement is between 58.441 in and 68.515 in.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 63.8, \sigma = 2.3$

A branch of the military requires women’s heights to be between 58 in and 80 in.

a. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too tall?

This probability is the pvalue of Z when X = 80 subtracted by the pvalue of Z when X = 58.

If the probability that a woman is accepted on the military is lower than 5%, we say that a woman being accepted into the military is unlikely.

X = 80

$Z = (X - \mu)/(\sigma)$

$Z = (80 - 63.8)/(2.3)$

$Z = 7.04$

$Z = 7.04$ has a pvalue of 1.

X = 58

$Z = (X - \mu)/(\sigma)$

$Z = (58 - 63.8)/(2.3)$

$Z = -2.52$

$Z = -2.52$ has a pvalue of 0.0059

So there is a 1-0.0059 = 0.9941 = 99.41% of women meeting the height requirement. There are not many women being denied the opportunity to join this branch of the military because they are too short or too tall.

b. If this branch of the military changes the height requirements so that all women are eligible except the shortest 1% and the tallest 2%, what are the new height requirements?

Tallest 2%: X when Z has a pvalue of 0.98. So X when $Z = 2.05$

$Z = (X - \mu)/(\sigma)$

$2.05 = (X - 63.8)/(2.3)$

$X - 63.8 = 2.3*2.05$

$X = 68.515$

Shortest 1%: X when Z has a pvalue of 0.01. So X when $Z = -2.33$

$Z = (X - \mu)/(\sigma)$

$-2.33 = (X - 63.8)/(2.3)$

$X - 63.8 = -2.33*2.3$

$X = 58.441$

The new requirement is between 58.441 in and 68.515 in.

Base on the questions, which is asking to many questions, ans the following would be the answers,
A. the women that fall between 58 and 80 inches tall would have a probability of 99.416%,
B. the new heights would 58,45 inches and 68,52 inches.

I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications

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