What are the values of x in the equation x(x-6)=4(x+6)

Answers

Answer 1

Answer: $x(x-6)=4(x+6)\ \ \ |use\ distributive\ property\ a(b+c)=ab+ac\n\nx(x)+x(-6)=4(x)+4(6)\n\nx^2-6x=4x+24\ \ \ \ |subtract\ 4x\ and\ 24\ from\ both\ sides\n\nx^2-10x-24=0\n\nx^2-12x+2x-24=0\n\nx(x-12)+2(x-12)=0\iff(x-12)(x+2)=0\n\ntherefore\n\nx-12=0\ or\ x+2=0\n\nAnswer:\boxed{x=12\ or\ x=-2}$

Answer 2

Answer:         x(x - 6) = 4(x + 6)
    x(x) - x(6) = 4(x) + 4(6)
     x² - 6x = 4x + 24
         - 4x - 4x
     x² - 10x = 24
x² - 10x - 24 = 24 - 24
x² - 10x - 24 = 0
x = -(-10) +/- √((-10) - 4(1)(-24))
   2(1)
x = 10 +/- √(100 + 96)
   2
x = 10 +/- √(196)
2
x = 10 +/- 14
2
x = 5 + 7
x = 5 + 7 U x = 5 - 7
x = 12    x = -2
The values of x in the equation is either equal to 12 or -2.

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What is the solution to the system of equations? y = 1/2x-6 and x=-4

Answers

All you have to do is plug -4 for x

y = 1/2 * -4 - 6

y = -8

Solution: (-4, -8)

A farmer is planting a straight row of crops with 3 feet between each plant is 23 are planted what is the distance between the first and last plant

Answers

The distance between the first and last plant is $\fbox{\bf{\text{66 feet}}}$ .

Further explanation:

Given:

A farmer is planting a straight row of crops with 3 feet between each plant.

Calculation:

Consider the number of plant as $x$ .

The number of spaces $S$ between the plants is calculated as follows:

$S=x-1$ ……(1).

Since, the number of plants are 23, Substitute 23 for $x$ in equation (1) to obtain the number of spaces between the plants.

$\begin{aligned}S&=23-1\n&=22\n\end{aligned}$

Since, the distance between each plant is 3 feet, the distance $D$ between the first and last plant is calculated as follows:

$D=3S$ ……(2)

Substitute 22 for $S$ in equation (2) to obtain distance $D$ between the first and last plant.

$\begin{aligned}D&=3\left({22}\right)\n&=66\,\,{\text{feet}}\n\end{aligned}$

Thus, the distance between the first and last plant is $\fbox{\bf{\text{66 feet}}}$ .

Learn more:

1. Which function has an inverse that is also a function? {(–1, –2), (0, 4), (1, 3), (5, 14), (7, 4)} {(–1, 2), (0, 4), (1, 5), (5, 4), (7, 2)} {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)} {(–1, 4), (0, 4), (1, 2), (5, 3), (7, 1)}

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2. A given line has the equation 10x + 2y = −2. what is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)? y = ( )x + 12

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3. what are the domain and range of the function f(x) = 3x + 5?

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Answer Details :

Grade: Middle School

Subject: Mathematics

Chapter: linear equation

Keywords:Plant, farmer, crops, feet, A farmer is planting, space between the plant is 3 feet, linear equation, straight lines, function, number of spaces.

Final answer:

The distance between the first and last plant in a straight row of 23 crops with a spacing of 3 feet each is 66 feet. This is calculated using the formula: (Number of plants - 1) * Distance between plants.

Explanation:

The problem requires you to find the total distance from the first to the last plant in a row of crops considering that each plant is planted 3 feet apart. This type of problem can be solved by simple arithmetic calculations.

You might think you should simply multiply the number of plants by the distance between them, but this would not provide the correct answer. The reason is that the distance between the plants is not the same as the distance from the first to last plant.

For example, if the farmer only planted two crops, there would only be 3 feet between them, not 6. Therefore, we need to use the formula: (Number of plants - 1) * Distance between plants.

To solve for our question, we’d get: (23 plants - 1) * 3 feet = 66 feet. Thus, the distance between the first and last plant is 66 feet.

Learn more about Plant Spacing Calculation here:

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In a certain year an art exhibition was held for three days february 27,28,29 what year was it?

Answers

Answer:

1929

1829

1729

1629

it can be any year accept.

The original value of a car is $18,000, and it depreciates (loses value) by 15% each year. what is the value of the car after three years?

Answers

If the original value of a car is $18,000, and it loses value by 15% each year, then you can calculate the new value of the car after n years using following formula:

$P=\$18,000\cdot (1-0.15)^n.$