Sense or Nonsense?Penny wants to make a model of a beetle that is larger than life-size. Penny says she is going to use a scaling factor of 7/12. Does this make sense or is it nonsense? Explain.

Answers

Answer 1

Answer: Nonsense... The beetle in life size is 12/12 = 1
Therefore, to make a model bigger than this, it would have to be more than 12/12 (1). However, Penny is making it less than 1 whole meaning it would be smaller than life size.
Hope you understand this and it helps (-sorry, it's quite hard to explain!) :-)

Answer 2

Answer: If that's how it's displayed, 7/12, then no it doesn't make sense. Using that scale factor is the equivalent shrinking it by 5/12s. And that's not larger than life size. If the scale factor is 7:12, then it would make sense, as the beetle would be 5/19 bigger than the original. It's not much, but it's a start for Penny

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Complete the following item based on the given information.The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 325 cubic inches and a length of 13 inches, what is the constant of proportionality for the group of boxes?
k = ________

Answers

Answer:

The constant of proportionality for the group of boxes is 25.

Step-by-step explanation:

Given : The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 325 cubic inches and a length of 13 inches.

To find : What is the constant of proportionality for the group of boxes?

Solution :

The volume of a box(V) varies directly with its length(l).

Using k for the constant of proportionality.

We can express the relationship between V and l

If V varies directly with l.

V = kl

According to question,

If one of the boxes has a volume of 325 cubic inches and a length of 13 inches, then

$325=13k\n\n\Rightarrow\ k=(325)/(13)\n\n\Rightarrow\ k=25$

Therefore, The constant of proportionality for the group of boxes is 25.

k = 325/13
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When two faces of a three dimensional figure share a side they form this

Answers

Hi there! When two faces of a three dimensional figure they share a side they form a Edge. Not a square, it's a edge. A square isn't a three-dimensional figure. But on the other hand, a three dimensional figure would be an Edge.

Your answer is a Square.

Hope this helps.

A rectangle with an area of 24 square units has length x+1 and width 4x-6. find the value of x.

Answers

$area = length \cdot width \n \nA = 24 s^2 \n \n l=x+1 , \ \ w=4x-6 \n \n A=lw\n \n24 =(x+1)(4x-6)$

$24 =4x^2-6x+4x-6 \n \n4x^2-6x+4x-6 -24=0\n \n4x^2-2x-30=0 \ \ / :2\n \n2x^2-x-15=0 \n \na=2, \ b=-1 , c= -15$

$\Delta =b^2-4ac = (-1)^2 -4\cdot2\cdot (-15) = 1+120=121\n \nx_(1)=(-b-√(\Delta) )/(2a)=(1-√(121))/(2*2 )=( 1-11)/(4)=(-10)/(4)=- (5)/(2) \n \nx_(2)=(-b+√(\Delta) )/(2a)=(1+√(121))/(2*2 )=( 1+11)/(4)=(12)/(4)=3 \n \nUse \ positive \ value \ of \ x : \n \n x =3$

What polynomial identity should be used to prove that 16^2=(10+6)^2? (A. Difference of Cubes; B. Difference of Squares; C. Square of Binomial; D. Sum of Cubes)

Answers

Answer:

C. Square of Binomial

Step-by-step explanation:

To prove the identity you should use square of Binomial that states the following:

$(a+b)^(2)=a^(2)+2ab+b^(2)$

Lets prove it, so first take the equation to solve:

$(10+6)^(2)$

Then square the first term:

$(10+6)^(2)=10^(2)$

Then multiply by 2 the first and second terms:

$(10+6)^(2)=10^(2)+2(10)(6)$

Finally square the second term:

$(10+6)^(2)=10^(2)+2(10)(6)+6^(2)$

Solve the values:

$(10+6)^(2)=100+2(10)(6)+6^(2)$

$(10+6)^(2)=100+120+6^(2)$

$(10+6)^(2)=100+120+36$

$(10+6)^(2)=256$

And prove the polynomial identity:

$16^(2)=256$

not difference of cubes since it is 2nd degree
not difference of squares since it is plus
not sum of cubes because 2nd degreee

answer is square of binomial (why do we even need this property, oh well)

C

How do you graph or what are the points for x=-3

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Insert three rational numbers between -2/3 and 3/4

Answers

Answer:

1/4, 1/2 and 1/3

Step-by-step explanation:

Rational numbers are numbers that can be expressed in the form a/b

So for ease of answering, we can just select values closer to the extremes given

so we can have 1/4, 1/2 and 1/3

These three numbers are all greater than the minimum extreme (-2/3) and less than the maximum extreme

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