Which nuclear emission has no charge and no mass?(1) alpha particle (3) gamma ray
(2) beta particle (4) positron

Answers

Answer 1
Answer:

Answer:  Gamma ray

Explanation:  Nuclear Emission explains the release of energy stored in the nucleus of an atom in the form of particles like alpha particles, beta particles, gamma ray etc.

Alpha particles are the helium atom having +2 charge.

Beta particles have -1 charge thus beta particle and the electron are same.

Positron has a charge of +1 electron having 1/2 spin.

Gamma rays are the rays which are neutral and have no mass.

Answer 2
Answer:

Final answer:

A gamma ray is a nuclear emission that has no charge and no mass.

Explanation:

Nuclear radiation refers to the emission of particles or electromagnetic waves from atomic nuclei undergoing decay. Types include alpha, beta, and gamma radiation, each with varying properties and effects. It is a fundamental concept in nuclear physics and has applications in medicine, energy production, and weaponry.

The nuclear emission that has no charge and no mass is the gamma ray. Unlike the other options listed, which are particles, gamma rays are electromagnetic radiation and do not have mass or charge. They are highly penetrating and can pass through many materials without being deflected.

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Iron has a density of 7.86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.01 kg . Note that the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm3 = 1 mL) before calculating the volume for the piece of iron.

Answers

510.17 cm³ is the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg.

What is density?

Density is the amount of mass of a substance present per volume of the cubic centimeter and it is the ratio of the mass of a substance to the volume of the substance with a unit centimeter cube.

The Iron has a density of 7.86 g/cm³ and mass of 4.01 kg so,

mass in gram = 4.10 / 1000 = 0.041

Density = mass/volume

Substituting the value in the equation,

volume =  0.041 /7.86 g/cm³

volume = 510.17 cm³

Therefore, the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg is 510.17 cm³.

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4.01 kg in grams :

4.01 x 1000 = 4010 g

Density = mass / volume

7.86 = 4010 / volume

Volume = 4010 / 7.86

Volume = 510.17 cm³ 

hope this helps!


Ammonia, NH3, can be classified as a base because in a chemical reaction with an acid, ammonia will (1 point)produce hydroxide ions in solution. produce hydronium ions in solution. donate a proton and become NH2–. accept a proton and become NH4+.

Answers

Answer: Option (d) is the correct answer.

Explanation:

Bases are the electron rich species which readily accept a proton. Therefore, when ammonia is classified as a base in a chemical reaction with an acid, it readily accepts a proton to give ammonium cation.

For example, the reaction of ammonia with hydrochloric acid will be as follows.

          NH_(3) + HCl \rightarrow NH^(+)_(4) + Cl^(-)

Thus, we can conclude that ammonia, NH_(3), will accept a proton and become NH^(+)_(4).

NH will accept a proton and become NH4+

Bases follow
B^-+H^+=BH, with B^-=NH_3 in our case.

What's the electron configuration of Zr (AN 40)​

Answers

The electron configuration of Zr (AN 40) is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d2 5s2

How many different sets of equivalent protons are there for para-xylene (1,4-dimethylbenzene)? only 1 two three four?

Answers

Answer:

Two  

Step-by-step explanation:

There are two ways to determine the number sets of equivalent protons in a compound.  

(a) By substitution

Replace each H with a different group and see if you get a different compound

For example, the six CH₃ H atoms are an equivalent set, because, if I replace any one of them, I will always get the same compound: 1-chloromethyl-4-methylbenzene (Fig. 1).

Similarly, the four aromatic H atoms are an equivalent set. If I replace any one of them, I will always get the same compound: 2-chloro-1,4-dimethylbenzene (Fig. 2).

Thus, there are two sets of equivalent protons in p-xylene.

(b) By symmetry

Two atoms are equivalent if one can be converted into the other by a symmetry operation on the molecule.

The methyl hydrogens can be interconverted by a combination of reflections about the AB and CD mirror planes and byrotations about the C-C bonds to the ring (Fig. 3).

Similarly, the four aromatic H atoms can be interconverted by a combination of reflections about the AB and CD mirror planes.

Again, we find two sets of equivalent protons.

Which balanced equation represents a fusion reaction?

Answers

 Fusion reaction is a type of nuclear reaction where two or more nuclei combine or collide to form an element with a higher atomic number. This happens when the collision is in a very high speed. In this process, some of the matter of the fusing nuclei is converted to energy.

What is the mass/volume percent of a solution with 75g of Na2CO3 dissolved in 20.0 g of water?11%

9.3 %

30%

7.5%

Answers

Answer:

percent by mass = 79%

Explanation:

Data Given:

mass of solute (Na₂CO₃) = 75 g

mass of solvent ( water ) = 20 g

mass percent of solution = ?

Solution:

Formula used to find percent by mass

                          mass of solute / mass of solution x 100 . . . . . . (1)

first we have to find mass of solution

              mass of solution = mass of solute + mass of Solvent . . . . (2)

put values in equation 2

             mass of solution = 75 g + 20 g

             mass of solution = 95 g

Now,

put values in equation 1

 Percent by mass = mass of solute / mass of solution x 100

 Percent by mass = 75 g / 95 g x 100

 Percent by mass = 79 %

so,

The percent of the solution by mass = 79%

***Note:

The same work can be used for the other values too i.e. if you have 20 g of solute and 75 g solvent.

Answer:

The answer is 78.9%

Explanation:

The percentage weight in volume indicates the mass of solute per volume. We will use the% weight/volume formula to calculate what the exercise asks for, as follows:%weight/volume=(solute weight)/(solution volume)x100%= (75 g)/(75+20)= 78.9%

percent Weight/volume=(solute weight)/(solution volume)x100=(75 g)/(75+20)x100=78.9%