Which volume of 2.0M NaOH(aq) is need to completely neutralize 24 milliliters of 1.0M HCl(aq)?(1) 6.0mL (2) 12mL (3) 24mL (4) 48mL

Answers

Answer 1
Answer: The answer is (2) 12mL. The reaction equation is NaOH + HCl = NaCl + H2O. So the mol number of NaOH is equal to HCl. The concentration of NaOH is twice of HCl so the volume of HCl is twice of NaOH.

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What volume is occupied by 18.4 g oxygen at 28.0°C and a pressure of 0.998 torr? (round to sig figs)

Answers

Answer:

11.0 dm³

Explanation:

From the question,

Applying

PV= nRT............... Equation 1

Where P = pressure of oxygen gas, V = volume of oxygen gas, n = number of moles of oxygen, R = molar constant, T = Temperature.

make V the subeject of the equation

V = nRT/P............. Equation 2

But,

Number of mole (n) = Mass of oxygen(m)/Molar mass of oxygen(m')

n = m/m'....................... Equation 3

Substitute equation 3 into equation 2

V = mRT/Pm'............. Equation 4

Given: T = 28°C = (28+273) = 301 K, P = 0.998 torr = (0.998×0.00131579) = 1.3132 atm, m = 18.4 g

Constant: R = 0.082 atm.dm³/K.mol, m' = 32 g/mol.

Substitute these values into equation 4

V = (301×18.4×0.082)/(32×1.3132)

V = 454.1488/42.0224

V = 10.81 dm³

V = 11.0 dm³

What is the value for ΔSºreaction for the following reaction, given the standard entropy values? Al2O3(s) + 3H2(g) → 2Al(s) + 3H2O(g) –35 J/mol*K +35 J/mol*/K +179 J/mol*K –179 J/mol*K

Answers

Let me help you by giving the formula as it will be more useful for you. delta S = Sum(n) (Delta S(products)) - Sum(m)(Delta S(reactants)). There are m and n in formula that are coefficients of the reactants and products that are given in the equation.

The answer is C just got it right

Where do decomposers fit on the pyramid of trophic levels?

Answers

Answer:

we place the decomposers in a special place along the side of the pyramid

Explanation:

A vineyard has 145 acres of Chardonnay grapes. A particular soil supplement requires 5.50 g for every square meter of vineyard. How many kilograms of the soil supplement are required for the entire vineyard? (Recall that 1 km2 = 247 acres.) Express your answer in kilograms to three significant figures.

Answers

1.36.10 ^ 6 kg of supplements are required for the entire vineyard

Further explanation

7 main quantities have been determined based on international standards, namely:

  • 1. Length, meters (m)
  • 2. Time, second (s)
  • 3. Mass, kilograms (kg)
  • 4. Temperature, kelvin (K)
  • 5. Light intensity, candela (cd)
  • 6. Electric current, ampere (A)
  • 7. Amount of substance, mol (m)

Derivative magnitude is a quantity derived from one or more principal quantities. So in addition to 7 principal quantities, other quantities are derived quantities

An area with the formula length x width is a unit derived from the length of the principal. The international standard unit is square meters (m²).

other area units: Km², hm², dam², m², dm², cm², and mm²

Hectare is an SI unit

1 Hectare is equal to 100 a (Are) or 10000 m² (ten thousand square meters) or 100 x 100 m 1 Hectares = 2.47 acres

In the question , there is a 145 acres vineyard, with the supplement is given 5.5 gram / m² vineyard.

So for 1 km², a supplement  =

1 km² = 10⁶ m²

5.5 gram / m² = 5.5.10⁶ grams / km²

whereas 1 km² = 247 acres and vineyard = 145 acres so

5.5.10^6*(145)/(247)

= 3.2287.10⁶ grams

= 3.23.10³ kg (3 significant numbers: 3,2 and 3)

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Keywords: area, convert, acres

The soil supplement required for the entire vineyard is \boxed{3.23 * {{10}^3}{\text{ kg}}}.

Further Explanation:

There are two types of units. One is basic or fundamental while the other ones are derived units. Basic units cannot be further reduced and other quantities are expressed in these units. Derived units are those that can need basic units to express themselves. Area, density, volume and velocity are some examples of derived units.

Seven basic units are present in the SI system. These are as follows:

1. Meter (m)

2. Kilogram (kg)

3. Second (s)

4. Kelvin (K)

5. Ampere (A)

6. Mole (mol)

7. Candela (Cd)

Firstly, the area of vineyard has to be converted into {\text{K}}{{\text{m}}^2}. The conversion factor for this is,

1{\text{ acre}} = \left( {\frac{1}{{247}}} \right){\text{ K}}{{\text{m}}^2}

Therefore the area of vineyard can be calculated as follows:

 \begin{aligned}{\text{Area of vineyard}} &= \left( {145{\text{ acres}}} \right)\left( {\frac{{1/247{\text{ K}}{{\text{m}}^2}}}{{1{\text{ acre}}}}} \right)\n&= 0.587045{\text{ K}}{{\text{m}}^2}\n\end{aligned}  

The area is again converted into {{\text{m}}^{\text{2}}}. The conversion factor for this is,

 1{\text{ K}}{{\text{m}}^2} = {10^6}{\text{ }}{{\text{m}}^2}

So the area of vineyard can be calculated as follows:

\begin{aligned}{\text{Area of vineyard}}&= \left( {0.587045{\text{ K}}{{\text{m}}^2}}\right)\left( {\frac{{{{10}^6}{\text{ }}{{\text{m}}^2}}}{{1{\text{ K}}{{\text{m}}^2}}}}\right)\n&= 587045{\text{ }}{{\text{m}}^2}\n\end{aligned}  

The amount of supplement required for the entire vineyard can be calculated as follows:

 \begin{aligned}{\text{Amount of supplement required}}&= \left( {587045{\text{ }}{{\text{m}}^2}} \right)\left( {\frac{{5.50{\text{ g}}}}{{1{\text{ }}{{\text{m}}^2}}}} \right)\n&=3.2287475 * {10^6}{\text{ g}}\n\end{aligned}

The amount of supplement is to be converted into kg. The conversion factor for this is,

 1{\text{ g}} = {\text{1}}{{\text{0}}^( - 3)}{\text{ kg}}

Therefore the amount of supplement can be calculated as follows:

 \begin{aligned}{\text{Amount of supplement}}&= \left({3.2287475 * {{10}^6}{\text{ g}}} \right)\left( {\frac{{{{10}^( - 3)}{\text{ kg}}}}{{1{\text{ g}}}}} \right)\n&= 3.2287475 * {10^3}{\text{ kg}}\n&\approx 3.23 * {10^3}{\text{ kg}}\n\end{aligned}

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Basic concepts of chemistry

Keywords: supplement, vineyard, 5.50 g, 3.23*10^3 kg, conversion factor, basic units, fundamental units, derived units, area, volume, density, kg, m, Km, acre.

Can someone please take a look at this lab.? And show answers with work? Thanks! I tried it but I'm pretty sure I did it all wrong.

Answers

Answer: B

Explanation:

All of your answers look wrong

Which of the following is NOT a true statement about liquids?1. Liquids have no definite shape.
2. The boiling point of a liquid will increase with increasing atmospheric pressure.
3. The boiling point of a liquid will decrease with decreasing atmospheric pressure.
4. Liquids have no definite volume.

Answers

Answer:

4

Explanation:

1 is correct

Liquids have no definite shape as they take up the shape of the container. Thus, we can say a liquid has no shape of its own but rather has the shape of the container in which it is filled.

2 is correct

When the atmospheric temperature is increased, it also will increase the boiling point of the liquid

3 is correct

This is an extension of the statement 2. While we decrease the atmospheric pressure, we are also decreasing the boiling point

4 is incorrect

A liquid have a definite volume. When we say a volume is definite, it means the volume is fixed and does not change. The volume of liquids is definite for a particular mass of the liquid and does not change

Final answer:

The statement 'Liquids have no definite volume' is not true. Liquids do have a definite volume, but no definite shape. The boiling point of a liquid changes with atmospheric pressure.

Explanation:

The statement ' Liquids have no definite volume' is NOT a true statement about liquids. In fact, while they do not have a definite shape and take on the shape of their container, liquids do have a definite volume under given conditions.

Statements 2 and 3 accurately describe that the boiling point of a liquid varies with changes in atmospheric pressure. Specifically, the boiling point increases with increasing atmospheric pressure, and conversely decreases with decreasing atmospheric pressure.

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