CHEMISTRY HIGH SCHOOL

The spontaneous decay of an atom is called(1) ionization (3) combustion
(2) crystallization (4) transmutation

Answers

Answer 1
Answer:

The spontaneous decay of an atom is known as transmutation.  

• The conversion of one chemical element or an isotope into another chemical element is termed as nuclear transmutation.  

• It takes place in any process where the number of neutrons or protons in the nucleus of an atom is changed.  

• It is the spontaneous decay of an atom.  

• Transmutation can be attained either by radioactive decay or by nuclear reactions. In radioactive decay no external cause is required, while in nuclear reactions an external particle reacts with a nucleus.  

• One kind of natural transmutation is witnessed when some kind of radioactive elements found in nature spontaneously decay by a procedure that leads to transmutation like beta or alpha decay.  

Thus, the correct answer is option 4, that is, transmutation.

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Answer 2
Answer: Transmutation is the Spontaneous / sudden decay of an atom. 

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Which of the following carbohydrates is a polysaccharide and not a simple sugar?O A. Glucose
O B. Ribose
O C. Starch
O D. Fructose
O E. Galactose

Answers

Starch is a carbohydrate which is a polysaccharide and not a simple sugar like glucose, fructose,etc.

What are carbohydrates?

A carbohydrate is defined as a bio-molecule which consists of carbon,hydrogen and oxygen atoms which are usually in the ratio of 2:1 with the empirical formula C_n(H₂O)_n.

This term is most commonly used in biochemistry as a synonym of saccharide which is a group of sugars, starch and cellulose.

They perform various functions in living organisms. They serve as an energy source and as well as structural components . They are a key component in providing nutrition and are found in wide variety of natural as well as processed foods.

Carbohydrates occur as cellulose in the cell walls of plants and is one of the components of insoluble dietary fibers.

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Answer:

C

Explanation:

The polysaccharide is starch which contains many glucose molecules.

The rest are either monosaccharide or disaccharides.

Which process uses energy to combine inorganic molecules to synthesize organic molecules

Answers

Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that can be later released to fuel the organisms activities.

Compared with warm fronts, cold fronts are?

Answers

Warm fronts is the transition zone that marks where a warm air mass starts replacing a cold air mass. The movement is from southwest to southeast while Cold fronts is where a cold air mass is pushing into a warmer air mass. They move fast, up to twice as fast as a warm front.

What is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2,500 milliliters of solution?

Answers

Molarity is

mol
-----
Litre 

First you need to find how many moles 12.2 grams is 

To do this you need to find molecular weight of SrCl2
(87.62)+(35.45*2) = 158.52 g/mol

Now convert 12.2 g into moles
12.2 g * 1 mol / 158.52 g (12.2/158.52) = 0.0769618976 moles

Next convert 2500 mL into Litres
2500mL * 1L / 1000mL (2500/1000) = 2.5 Litres

Finally do moles / Litres

0.0769618976 / 2.5 = 0.0308 M

0.031 M is the molarity of an aqueous solution that contains 12.2 grams of SrCl2 dissolved in 2,500 milliliters of solution.

What makes an atom able to form a compound? * O different number of neutron than protons O unfilled outer electron shells O same number of protons as electrons O a positive ot negative charge of the nucleus​

Answers

Answer:

same number of protons as electrons

Explanation:

The addition of a neutron can make an atom radioactive. When you change the number of protons in an atom, you will change the atom from one element to a different element. ... If you change the number of electrons in an atom, you will get an ion of the element.

Determine the half-life of potassium if in 3460 years a 200 g sample decayed into 25 g

Answers

M=m_o*(1)/(2)^(t)/(T)\n M-mass\ aftter\ decay\n m-initial\ mass\n t-time\n T-period(half-life)\n 25=200*(1)/(2)^(3460)/(T)|:200\n (1)/(8)=((1)/(2))^(3460)/(T)\n ((1)/(2))^3=((1)/(2))^(3460)/(T)\n 3=(3460)/(T)\n T=1153(1)/(3)

or easiest way
200g ----->  100g -------> 50g -----> 25g
We can that there were three decays.
1 decay ----------- x years
3 decays---------- 3460
x=1153(1)/(3)
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