MATHEMATICS HIGH SCHOOL

(-7x²-7x-7)-[(7x³-9x²-20)+(4x-11)]]=?(5x⁴+8x²+2)+7(5x⁴-3x²)=?
Please explain the work behind the solution

Answers

Answer 1
Answer: (-7x^2-7x-7)-[(7x^3-9x^2-20)+(4x-11)]]=\n=-7x^2-7x-7-(7x^3-9x^2-20+4x-11)=\n=-7x^2-7x-7-7x^3+9x^2+20-4x+11=-7x^3+2x^2-11x+24\n\n (5x^4+8x^2+2)+7(5x^4-3x^2)=5x^4+8x^2+2+35x^4-21x^2=\n=39x^4-13x^2+2

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Find the area in square inches of a cell phone screen that measure 5 3/4 inches by 2 1/2 inches​
Estimate the product of 46 x 31 = ________. Select the equation that correctly represents how to round each factor. (2 points)50 x 30 = ________45 x 35 = ________50 x 35 = ________40 x 30 = ________

What is the geometric mean of 3and 6

Answers

Answer:

The mean is 4.5

Step-by-step explanation:

u add the numbers and divide by how many numbers there are

Which fraction is equivalent to the ratio 126 : 54​

Answers

Answer:

(7)/(3)

Step-by-step explanation:

Which fraction is equivalent to the ratio 126:54​

(126)/(54) = (63)/(27) = (21)/(9) = (7)/(3)

So, the answer is (7)/(3)

tim is excited because he thnks he got a higher score on a math test than his younger sister Lila.. Tim scored41 over 50 on his math test and Lila scored 21/25 on her most recent math test Tim thinks that because he got more questions correct that he got a better score. explain to Tim in your own words wisely the score is actually better than his you must convert both scores to fractions with 100 as denominators so you can think in terms of percentages

Answers

If Tim scored 41/50 and Lila scored 21/25, then if you were to convert both scores to fractions with 100, you would get that Tim made an 82/100 and Lila made an 84/100. This means that Lila actually scored 2% higher than Tim did.
Tim 41/50. Lila 21/25
To get the first fraction to ?/100 you need to divide the denominator (50) from 100, which you would get 2, so multiply the numerator by 2 to get 82%. Same with Lila, which would be 84%.  
"Tim, go get a calculator," is what I would say. 

What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1; } while (x < 2.5); System.out.print(i + " ");

Answers

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

 double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

\n\nx=1\ny=1\ny=1/2=0.5\nx=1+0.5=1.5\ni=1

The variable x is minor to 2.5 so the loop will continue computing.

b)   the second iteration, the values of y and x are shown below::

 y=0.5\nx=1.5\ny=(1.5)/(2)=0.75\n x=1.5+0.75=2.25\ni=2

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

y=0.75\nx=2.25\ny=(2.25)/(2) =1.1125\nx=2.25+1.125=3.375\ni=3

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

Therefore the number 3 is display.

Solve and describe the steps used to find x for the equation 2(x + 4) – 10 = 12

Answers

Well,  you want to find the value of x.  

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours. Assume the population standard deviation is the same. Which of the statement below best describes that there is a 95% confidence interval for the mean hours devoted to social networking in January? A. The 95% confidence interval ranges from 8 to 45 hours. B. The 95% confidence interval ranges from 40.13 to 45.78 hours. C. The 95% confidence interval ranges from 43.87 to 46.13 hours. D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Answers

Answer:

D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Step-by-step explanation:

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours.

Here,

n = sample size = 50,

μ = mean = 45,

σ = standard deviation = 8,

We know that, confidence interval will be,

=\mu\ \pm\ z(\sigma )/(√(n))

For a confidence interval of 95%, we use z = 1.96, putting the values

=45\ \pm\ 1.96(8)/(√(50))

=42.78,47.22
D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

To solve the interval, we used the upper and lower limit formulas wherein:
xbar = 45
z = 1.96
s = 8
n = 50
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