MATHEMATICS HIGH SCHOOL

The test scores for a group of students are shown. 87, 72, 98, 84, 72, 65, 72, 70, 58, 91, 81, 84


What is the mode of the scores?

A.
80

B.
77.8

C.
76.5

D.
72

Answers

Answer 1
Answer:
the mode is what occurs the most. 87 occurs once, 72 occurs 3 times, 98 occurs once,84 occurs twice,  65 occurs once, 70 occurs once, 58 occurs once , 91 occurs once and 84 occurs once.  72    occurs 3 times, which is the most, so 72  is the mode.

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You are challenged to a lucky draw game. If you draw a face card (K, Q, J) from a standard deck of cards, you earn 10 points. If you draw any other card, you lose 2 points. What is the expected value that you can get if you draw another card?

Answers

To problem wants to compute the probability of the expected value that could be earn if you would draw again another card. So base on the fact that if draw a face card of K,Q,J from a standard deck correctly you will earn 10 point in just one draw, but loose 2 points if you another card, the probability that you would draw correct card in just one draw is 30.77%, so the possible value earn you have 2 points only 

Answer:

A: 0.77

Step-by-step explanation:

Edg

What are the answers to all these questions?

Answers

For example exc. 4!

V = x(6 - 2x)(10 - 2x) = (6x - 2x^2)(10 -2x) = 60x - 12x^2 - 20x^2 + 4x^3 = 4x^3 - 32x^2 + 60x;

How i do this -> Log 5x10^-3/2x10?

Answers

log(5\cdot10^(-3))/(2\cdot10)}=log\left((5)/(2)\cdot(10^(-3))/(10)\right)=log(2.5\cdot10^(-3-1)})=log(2.5\cdot10^(-4))=(*)\n\nuse\ log(a\cdot b)=loga+logb\ and\ loga^b=b\cdot loga\n\n(*)=log2.5+log10^(-4)=log2.5-4log10=log2.5-4\n\vdots\nlog2.5=log(25)/(10)=log25-log10=log25-1=log5^2-1=2log5-1\n\ntherefore\n\n(*)=2log5-1-4=2log5-5

Factor
the expression 3x3 +
2x2y + 3xy2 + 2y3

Answers

3x^3 +2x^2y + 3xy^2 + 2y^3 =\n \n=x^2(3x+2y) +y^2(3x+2y)=\n \n=(3x+2y)(x^2+y^2)

Instructions: Find the value of the trigonometric ratio. Make sure to simplify the fraction if needed.

Answers

Answer:

30/34

Step-by-step explanation:

1.Read the complete problem before answering. Teresa bought gallons of chocolate milk at the dairy farm. Chocolate milk cost $4.50 a gallon. How much did Teresa spend on the milk?

A student solved the problem this way.

gallons = 2.5 gallons
Let n represent the amount Teresa spent on the milk.
n = 2.5 × $4.50
n = $11.25
Teresa spent $11.25.

Use a similar strategy to solve this problem.

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How much did Pedro spend on the sand? Read the complete problem before answering.

Gilles had gallon of paint. How many quarts of paint did Gilles have? 2. (1 gallon = 4 quarts)

A student solved the problem this way.

1 gallon = 4 quarts
Multiply the number of gallons by 4.
gallon = 2 quarts

Use a similar strategy to solve this problem.

Barbara made a punch by mixing quarts of ginger ale with quarts lemonade.

How many pints of punch did Barbara make? (1 quart = 2 pints) 3.Read the complete problem before answering.

Mark had a ribbon that measured yards. How many feet of ribbon did Mark have? (1 yard = 3 feet)

A student solved the problem this way.

1 yard = 3 feet
Multiply the number of yards by 3.
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How many feet of Velcro did Julie have? (1 yard = 3 feet) Read the complete problem before answering.

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Answers

o.o

I think it'll be better if you put one question at a time....

( I'm gonna go and follow it like the last problem we did, where we assume the amount bought or made in the 1st part of a problem will be the same amount in the second part of the problem. )


1. $4.6 * amount/pounds bought in total

( Since in part 1, Teresa bought 2.5 gallons... )

2.5 pounds of red sand and 2.5 pounds of brown sand = 5

$4.6 * 5 =$23


2.  ( Giles had 2 quarts in total )

2 quarts of ginger ale + 2 quarts of lemonade= 4 quarts, and 1 quart = 2 pints, so 8 pints

3. ( 4.33 yards since in the first part, Mark had 13 feet, and 13 feet= 4.33 yards )

So we assume Julie has 2 pieces of Velcro and each are worth 13 feet ( like Mark ). 13 * 2 = 26 feet

4. ( Patty had 9 quarts, and one gallon = 4 quarts, so she had 2.25 gallons ) 

So, we assume 8 in the morning and 9 during lunch, since the part 1's answer was 9. 9*2=18 hours, 18 hours = 1080 minutes


*Please tell me if I was correct or incorrect and why when you get the answers back*

Again, I state that there's a chance that these problems may be wrong, but you cannot blame me, since you insisted I come and help.
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