In which compound is the percent compositionby mass of chlorine equal to 42%?(1) HClO (gram-formula mass = 52 g/mol)
(2) HClO2 (gram-formula mass = 68 g/mol)
(3) HClO3 (gram-formula mass = 84 g/mol)
(4) HClO4 (gram-formula mass = 100. g/mol)

Answers

Answer 1
Answer:

The percentage mass composition of chlorine in HClO₃ is 42%.

What is the percentage mass composition of chlorine in each compound?

Percentage mas of chlorine is calculated as follows:

  • Percentage mass composition = mass of element * 100%/mass of compound

atomic mass of chlorine = 35.5

(1) In HClO (gram-formula mass = 52 g/mol)

Percentage mass composition = 35 * 100% / 52 = 67.3%

(2) In HClO2 (gram-formula mass = 68 g/mol)

Percentage mass composition = 35 * 100%/68 = 51.4%

(3) HClO3 (gram-formula mass = 84 g/mol)

Percentage mass composition = 35 * 100% / 84 = 42%

(4) HClO4 (gram-formula mass = 100. g/mol)

Percentage mass composition = 35 * 100% / 100 = 35.5%

Therefore, the percentage mass composition of chlorine in HClO₃ is 42%.

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Answer 2
Answer:

Final answer:

None of the compounds have a percent composition of chlorine equal to 42%.

Explanation:

To find the compound with a percent composition of chlorine equal to 42%, we calculate the mass of chlorine in each compound and calculate the percent composition. Let's go through each option:

  1. HClO: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (35.5/52) * 100% ≈ 68.3%. Not equal to 42%
  2. HClO2: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (2 * 35.5/68) * 100% ≈ 104.4%. Not equal to 42%.
  3. HClO3: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (3 * 35.5/84) * 100% ≈ 150%. Not equal to 42%.
  4. HClO4: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (4 * 35.5/100) * 100% = 142%. Not equal to 42%.

None of the compounds have a percent composition of chlorine equal to 42%. The correct answer is none of the above.

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How many moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 0.98 atm and a temperature of 373 K?

Answers

Answer:

There are 1, 13 moles of chlorine gas.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 0,98 atm x 35,5 L /0,082 l atm / K mol x 373 K

n= 1,137448506 mol

A _____ change occurs when a substance changes phase

Answers

when a substance changes phase it is called a PHYSICAL change

Answer:

It undergoes a physical change.

Explanation:

For strontium chloride, the light released when electrons transition between energy levels has a wavelength of 630 nm. Calculate:the wavelength in meters
the frequency in Hertz
the Energy in Joules

Answers

The energy in joules

What is the molarity of a 0.30 liter solution containing 0.50 mo les of NaCI

Answers

Number of moles NaCl = 0.50

Volume = 0.30 L

M = n / V

M = 0.50 / 0.30

= 1.667 M

hope this helps!

Which substance increases in solubility as the temperature decreases? 1) KClO3
2) NH3
3) KNO3
4) NaCl

Answers

Answer:

The correct answer is 2.

Explanation:

The NH3 solubility curve shows that when the temperature increases, the solubility of the compound decreases. The molecule is not flat but has a tetrahedral shape with a vacant vertex, and this is due to the formation of hybrid sp³ orbitals. Unlike other compounds, the NH3 solubility curve has been experimentally tested and is attached for better understanding.

Have a nice day!

NH₃ would.  This is because of the fact that ammonia is a molecular gas while the other options are ionic crystals.  Crystals increase in solubility when the temperature increases while gases increase in solubility while temperatures deceases.

I hope this helps.  Let me know in the comments if anything is unclear or if you want me to explain anything is more detail.

Glucose is an important sugar in many biochemical reactions what is the molarity of a solution that contains 500 grams of glucose (molecular weight= 180.16 g/mol) in 7.02 liters of solutiona. .56M
b. .78 M
c. 3.85 M
b. 4.98 M

Answers

Answer:

The correct answer is c.

Explanation:

First, look for the same problem to verify that the correct volume is 0.702 L.

Now we must calculate the amount of glucose moles (n) in the 500g:

n = (500 g)/(180 (g)/(mol) )

n = 2,7 mol

Molarity is given by moles of compound per liter. In this way, we calculate the molarity (M) as:

M = (2,7 mol)/(0,702 L)

M = 3,85(mol)/(L)

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Number of moles :

500 / 180.16 => 2.775 moles

Volume = 0.72 L

M = n / V

M = 2.775 / 0.72

M = 3.85 M

hope this helps!