Which aqueous solution of KI freezes at the lowest temperature?(1) 1 mol of KI in 500. g of water
(2) 2 mol of KI in 500. g of water
(3) 1 mol of KI in 1000. g of water
(4) 2 mol of KI in 1000. g of water

Answers

Answer 1

Answer: The answer is (2) 2 mol of KI in 500. g of water.. This is a question of colligative properties. Boiling point elevation and freezing point depression depend on the concentration of dissolved solute. You would get the greatest concentration of KI with the largest moles of KI and smallest volume of water.

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Ayala is making salad dressing. She mixes oil and vinegar in a blender until a smooth consistency is formed. Explain whether this is a heterogeneous or a homogeneous mixture and why.

Answers

Answer: The mixture formed will be heterogeneous mixture.

Explanation: When we mix oil and vinegar and blend it together to form a smooth mixture, the final mixture will still be heterogeneous in nature.

As we know that vinegar is a solution of acetic acid in water, which is polar in nature and oil is non-polar in nature.

When, we mix polar compound with a non-polar one, the resulting mixture may mix for a certain time, but after a time, we will be able to see the two layers in a mixture.

And heterogeneous mixtures are defined as the mixtures in which there is a distinct physical boundary present between the solutions in a mixture.

Hence, the mixture of oil and vinegar is a heterogeneous mixture.

Sample Response: A homogeneous mixture can only form when one of the substances can dissolve the other one. Oil and water cannot dissolve each other, so they must form a heterogeneous mixture with small particles of vinegar dispersed throughout the oil, yet not dissolved.

Explanation: Hope this Helps!

What would the pressure be if the can were heated to 1270∘C?

Answers

According to Gay -Lussac's law, the pressure of the can if it is heated to 1270°C is 4295.53 mm Hg.

What is the Gay-Lussac's law?

It is defined as a gas law which states that the pressure which is exerted by the gas directly varies with its temperature and at a constant volume.The law was proposed by Joseph Gay-Lussac in the year 1808.

The pressure of the gas at constant volume reduces constantly as it is cooled till it undergoes condensation .If a graph of pressure versus temperature is plotted it is a straight line which passes through the origin .

The equation is given as, P₁/T₁=P₂/T₂

On substitution of values as ,P₁=760 mm Hg,T₁=273 K,T₂=1543 K

P₂=1543×760/273=4295.53 mm Hg.

Thus, the pressure of gas is 4295.53 mm Hg if it is heated up to 1270°C.

Learn more about Gay-Lussac's law,here:

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P1/T1=P2/T2
760/303=P2/1428
P2= 760*1428/303
P2=3,582mmHg

I need help please Which option is chemical change?

Answers

Answer:

Getting coated with tarnish

Explanation:

Silver, the original substance is combining with a new substance tarnish to make a whole new chemical.

Draw .. the structural formula ( using c and h ) for 2- pentyne

Answers

Answer : The structural formula of 2-pentyne is shown below.

Explanation :

Structural formula : In the structural formula, the bonding and type of bonds which holds the atoms in molecule together are shown.

The given name of compound is, 2-pentyne.

A suffix '-yne' present at the end of the name represent the alkyne group.

For the number of carbon atom, we use prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

In this compound, the parent chain is 5 membered and a triple bond is present at 2nd position of the parent chain.

Thus, the structural formula of 2-pentyne is shown below.

answer is below.........

What is the ph at the equivalence point when 0.10 m hno3 is used to titrate a volume of solution containing 0.30 g of koh?

Answers

Answer;

pH = 7

Explanation;

HNO3 is a strong acid. KOH is a strong base. At the equivalence point, the solution will be neutral.
Therefore; the pH at the equivalence point when 0.10 m HNO3 is used to titrate a volume of solution containing 0.30 g of KOH will be 7.
The neutralization of a strong base with a strong acid gives a salt solution at the equivalence point. The salt contains ions that do not change the pH of water.

Answer:

pH at equivalence point will be 7

Explanation:

$HNO_(3)$ is a strong acid and KOH is a strong base. Hence a neutral salt would appear from acid-base reaction between them.
Acid-base reaction: $HNO_(3)+KOH\rightarrow KNO_(3)+H_(2)O$
At equivalence point, $KNO_(3)$ and water exists in medium.
As $KNO_(3)$ is a neutral salt therefore pH of medium will be equal to 7 (neutral).
So, pH at equivalence point will be 7.

Use the mole concept to calculate the number of atoms that are in a 1.75-mol sample of CHCl3.

Answers

This is how I got to that answer. Since we don't know how many atoms there are in a mole, we use the number 6.02 x 10^-23. Now, just plug in what you have in the equation:

1.75 moles ChCl3 x (6.02 x 10 ^-23) / 1 mole = 1.0535 x 10^-22 atoms.

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