CHEMISTRY HIGH SCHOOL

If 4.00 g of NaCl react with 10.00 g of AgNO3, what is the excess reactant?

Answers

Answer 1

Answer:

Answer : The excess reagent is, $NaCl$

Explanation :

First we have to calculate the moles of $NaCl$ and $AgNO_3$ .

$\text{Moles of }NaCl=\frac{\text{Mass of }NaCl}{\text{Molar mass of }NaCl}=(4g)/(58.4g/mole)=0.068moles$

$\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=(10g)/(169.9g/mole)=0.058moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$NaCl+AgNO_3\rightarrow AgCl+NaNO_3$

From the balanced reaction we conclude that

As, 1 mole of $NaCl$ react with 1 mole of $AgNO_3$

So, 0.068 moles of $NaCl$ react with 0.068 moles of $AgNO_3$

From this we conclude that, the moles of $AgNO_3$ are less than the NaCl. So, $AgNO_3$ is a limiting reagent because it limits the formation of products and $NaCl$ is an excess reagent.

Hence, the excess reagent is, $NaCl$

Answer 2

Answer: The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.

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Consider the dissolution of 2.50 grams of salt XY in 75.0 mL of water within a calorimeter. The temperature of the water decreased by 0.93 oC. The heat capacity of the calorimeter is 42.2 J/oC. The density of the water (and the solution) is 1.00 g/mL. The specific heat capacity of the solution is 4.184 J/goC. Calculate the enthalpy change for dissolving this salt on a energy per mass basis (units of J/g).

Answers

The enthalpy change for dissolving this salt on a energy per mass is 136.32 J/g

How to determine the mass of the water

Density of water = 1 g/mL
Volume of water = 75 mL
Mass of water =?

Mass = Density × Volume

Mass of water = 1 × 75

Mass of water = 75 g

How to determine the heat absorbed by the solution

Mass of water = 75 g
Mass of salt = 2.50 g
Mass of solution (M) = 75 + 2.5 = 77.5 g
Temperature change (ΔT) = 0.93 °C
Specific heat capacity of the solution = 4.184 J/gºC
Heat of solution (Q) =?

Q = MCΔT

Q = 77.5 × 4.184 × 0.93

Q = 301.5618 J

How to determine the heat consumed by the calorimeter

Heat capacity of the calorimeter (C) = 42.2 J/ºC
Temperature change (ΔT) = 0.93 °C

Heat by calorimeter (H) =?

H = CΔT

H = 42.2 × 0.93

H = 39.246 J

How to determine the total heat released

Heat of solution (Q) = 301.5618 J
Heat by calorimeter (H) = 39.246 J

Total heat =?

Total heat = 301.5618 + 39.246

Total heat = 340.8078 J

How to determine the enthalpy change

Total heat = 340.8078 J
Mass of salt = 2.5 g

Enthalpy change (ΔH) =?

ΔH = Total heat / mass

ΔH = 340.8078 / 2.5

ΔH = 136.32 J/g

Learn more about heat transfer:

brainly.com/question/6363778

Answer : The enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1* \Delta T+m_2* c_2* \Delta T]$

where,

q = heat released by the reaction

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $42.2J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = $Density* Volume=1/mL* 75.0mL=75.0g$

$\Delta T$ = change in temperature = $0.93^oC$

Now put all the given values in the above formula, we get:

$q=[(42.2J/^oC* 0.93^oC)+(75.0g* 4.184J/g^oC* 0.93^oC)]$

$q=331.08J$

Now we have to calculate the enthalpy change for dissolving this salt on a energy per mass basis.

$\Delta H=(q)/(m)$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 331.08 J

m = mass of salt = 2.50 g

$\Delta H=(331.08J)/(2.50g)=132.4J/g$

Therefore, the enthalpy change for dissolving this salt on a energy per mass basis is 132.4 J/g

A veterinarian picks up a small dog from the floor and places it on the operating table. if the dog weighs 80N and the operating table is 1.25m high, how much work does the veterinarian do?

Answers

The amount of work can be measured by multiplying the force done to the distance it is subjected to. In this problem the dog weighs 80N. Newton is a unit of force. The operating table is 1.25m high. This is the distance. Then work is equal to 100J.

What mass of K2SO4 would you need to prepare 1500g of 5.0% K2SO4 (m/m) solution?

Answers

To solve this we must be knowing each and every concept related to mass. Therefore, mass of K $_2$ SO $_4$ would you need to prepare 1500g of 5.0% K $_2$ SO $_4$ (m/m) solution is 75 g.

What is mass?

Mass defines the quantity of a substance. It is measured in gram or kilogram. Average mass is the mass of atoms of an element that are isotopes. It can be calculated by multiplying mass of a isotope to natural abundance of that isotope.

Mass of solution = 1500 g

5.0 % = 5.0 / 100 = 0.05

mass percentage = mass of solute / mass of solution

substituting all the given values in the above equation, we get

0.05 = mass of solute / 1500

mass of solute = 0.05 x 1500

mass of solute = 75 g of solute

Therefore, mass of K $_2$ SO $_4$ would you need to prepare 1500g of 5.0% K $_2$ SO $_4$ (m/m) solution is 75 g.

To learn more about mass, here:

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#SPJ2

Mass of solute = ?

Mass of solution = 1500 g

5.0 % = 5.0 / 100 = 0.05

w = mass of solute / mass of solution

0.05 = ? / 1500

w = 0.05 x 1500

w = 75 g of solute

hope this helps!

Is this a good scientific question? “Is the lifespan of snowshoe hares, which are white in the winter and brown in the summer, affected by levels of winter snowfall?” A) Yes, because the question is specific. B) No, because the question cannot be tested in a laboratory. C) Yes, because the question has already been answered. D) No, because the question does not lead to a hypothesis.

Answers

The answer is: A) Yes, because the question is specific.

The scientific method is a process for experimentation that is used to explore observations (in this example color of snowshoe hares).

Steps of the scientific method:

1) ask a question about something that is observed.

2) do background research.

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested.

4) test of hypothesis.

5) analyze collected data and draw a conclusion.

The two main variables in an experiment are the independent and dependent variable.

Dependent variable is the variable being tested and measured in a scientific experiment, in this example lifespan of snowshoe hares.

Dependent variables depend on the values of independent variables. The dependent variables represent the output or outcome whose variation is being studied.

A) Yes, because the question is specific.

What is a covalent bond?

Answers

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding. (hope this helps.)

Answer:

Explanation:

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Do you think that there is a high correlation between proficiency in mathematics and proficiency in chemistry? Explain why or why not. Use details about the components of each field to support your answer.

Answers

According to the fact that they both include the reaction change of elements through different processes, there should be a nice connection between them. In math, numbers pose as an element, and in chem - elements are physical things. Both of them can change due to reaction or a formula.

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