Which mixture will not yield hydrogen gas? (A) sodium and water
(B) calcium and water
(C) zinc and hydrochloric acid
(D) zinc and concentrated nitric acid
(E) steam and red hot iron

Answers

Answer 1

Answer: E) Steam and red hot iron

Related Questions

Which type of bonding involves positive ions immersed in a sea of mobile electrons?
A car motor oil was measured and described using kelvin. Which characteristic of matter was measured
An atom of any element must contain(1) an equal number of protons and neutrons(2) an equal number of protons and electrons(3) more electrons than neutrons(4) more electrons than protons
What is the source of fuel that is most widely used today?a. Coal b. Crude oil c. Natural gas d. Nuclear energy
What is the % yield if 20 grams of hydrogen is reacted with 32 gramsof oxygen and produces 9 grams of water?H2 + O2 -> H2O

The factor that affects how easily an electron can be removed from an atom is the.

Answers

Atomic radius aka distance from the nucleus to the outermost energy level. The greater this distance, the less electrostatic attraction between these oppositely charged particles.

How many moles of C
O
2
COX
2

will be produced from
97.0
g
97.0 g97, point, 0, start text, space, g, end text of
C
3
H
8
CX
3

HX
8

, assuming
O
2
OX
2

is available in excess?

Answers

Final answer:

Given 97.0 g of propane (C3H8), about 6.6 moles of CO2 will be produced according to the balanced chemical equation for the combustion of propane.

Explanation:

The question asks how many moles of CO2 will be produced from 97.0 g of C3H8, assuming O2 is available in excess.

The balanced chemical equation for the combustion of propane (C3H8) is C3H8 + 5O2 → 3CO2 + 4H2O. This tells us that one mole of propane produces three moles of CO2.

First, we need to find the moles of propane. The molar mass of propane is approximately 44.09 g/mole. So, 97.0 g of propane corresponds to approximately 2.2 moles. Therefore, 2.2 moles of propane produce 2.2 * 3 = 6.6 moles of CO2.

Learn more about moles of CO2 produced here:

brainly.com/question/24684929

#SPJ12

All elements have a unique atomic emission spectrum. In which of the following scenarios would this fact be most useful?A. when trying to determine a star's chemical composition
B. when trying to determine how old an artifact is
C. when trying to measure the speed of sound

Answers

Optrion A: when trying to determine a star's chemical composition.

Because unique atomic emission spectrum, analyzing the emission spectrum you can tell the chemical composition.

Which statement best describes the conductivity of weak electrolytes, such as weak acids and bases?A) Weak electrolytes do not dissolve in water and can not conduct electricity.
B) Weak electrolytes dissolve and partially dissociate in water providing charged ions to conduct electricity.
C) Weak electrolytes dissolve and completely dissociate in water providing charged ions to conduct electricity.
D) Weak electrolytes dissolve and does not dissociate in water providing no charged ions to conduct electricity.

Answers

Answer: B) Weak electrolytes dissolve and partially dissociate in water providing charged ions to conduct electricity.

Explanation: Weak electrolytes are those substances which do not dissociate completely when dissolved in water. They dissociate but then associate back and thus their dissociation is shown by an equilibrium sign. Example: $CH_3COOH$

$CH_3COOH\rightarrow CH_3COO^-+H^+$

The charged species formed helps in the conduction of electricity.

Strong electrolytes are those substances which dissociate completely when dissolved in water. Their dissociation is shown by a forward arrow. Example: $NaOH$

$NaOH\rightarrow Na^++OH^-$

The charged species formed helps in the conduction of electricity.

B. Weak electrolytes are weak because they only partially dissociate into ions in water.

Discuss the phenomena of sunrise and sunset seen on Earth and describe how they will be different from the perspective of outer space. PLS REPLY ASAP AND EXPLAIN IM DESPEPERATE

Answers

Answer:

IM TO LATE SORRY

Explanation:

Hydrogen sulfide burns form sulfur dioxide:2H2S(g) +3O2(g) → 2SO2(g) + 2H2O(g) ΔH= -1036 kJ

Calculate the enthalpy change when burning 26.7 g of hydrogen sulfide in kJ

pls help