A motorboat travels directly east. During its trip, winds blow from directly north, directly south, and southwest. Which of the following statements is true? A. All of the winds do work on the boat. B. Only the north wind does work on the boat. C. Only the south wind does work on the boat. D. Only the southwest wind does work on the boat.

Answers

Answer 1

Answer: D. Only the southwest wind does work on the boat. This is because the North and South winds are opposite each other and hence cancel each other out so work is not done.

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A gas has an initial volume of 2.5 L at a temperature of 275 K and a pressure of 2.1 atm. The pressure of the gas increases to 2.7 atm, and the temperature of the gas increases to 298 K.The final volume of the gas, rounded to the nearest tenth, is.

Answers

The following information are given:
V1 = 2.5L
T1 = 275K
P1 = 2.1 atm
T2 = 298K
P2 = 2.7 atm
V2 = ?
The formular for solving the equation is: P1V1T1 = P2V2T2
V2 = P1V1T1/P2VT2
V2 = 2.5 * 275 * 2.7 * 298 = 1443.75/804.6 = 1.794
Therefore, V2 = 1.8L.

Its 2.1, I just took the test, the verified answer is wrong.

What best describe a sound wave

Answers

A sound wave can also be described as a longitudinal wave. In a longitudinal wave, a source vibrates back and forth, causing air molecules to move back and forth in the same (in other words, parallel) direction that the wave is transmitted.

Final answer:

Sound can be best described as a mechanical wave and a disturbance in matter that is transmitted from its source outward. This disturbance can move in the form of periodic waves or longitudinal waves. The speed, frequency, and wavelength of a sound are interconnected and sound requires a medium to propagate.

Explanation:

Sound is best described as a mechanical wave, a type of disturbance in matter that is transmitted from its source outward. This movement can be in the form of periodic or longitudinal waves, implying that they move matter back and forth in the direction of the wave's motion. The speed of sound, its frequency, and its wavelength are interconnected, and this is described mathematically by the relationship v = fλ. This relationship shows that the velocity of sound (v) equates to the frequency (f) multiplied by the wavelength (λ).

Sound waves can be both audible and inaudible, originating from various sources, ranging from musical instruments to vocal voices to explosive bangs like a sonic boom. Also, to note is that sound is interpreted through our sense of hearing, and different frequencies and intensities create different sounds. Sound also has the ability to travel through different mediums, including solids, liquids, and gases, with varying speeds.

On a microscopic level, sound can be seen as synchronized oscillation of atoms. This type of motion is more organized than the thermal motion of the atoms. The behavior of sound waves is significantly different from light waves, as sound requires a medium to propagate, while light can travel in a vacuum.

Learn more about Sound Waves here:

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Karen shouts across a canyon and hears an echo 7.5 s later. how wide is the canyon? the speed of sound is 343 m/s. answer in units of m.

Answers

After Karen shouts, the sound wave of her voice travels across the canyon, it hits the walls, and then it comes back to Karen in a total time of t=7.5 s. If we call L the distance between Karen and the other side of the canyon (so, L is the width of the canyon), it means that the sound wave covers a distance of S=2L in this time.
Since the wave moves by uniform motion, we can use the usual relationship between space, time and velocity:
$v= (S)/(t)= (2L)/(t)$
where v=343 m/s is the speed of sound. Using this number, we can find L from the previous equation:
$L= (vt)/(2)= ((343 m/s)(7.5 s))/(2)=1286 m$
So, the canyon is 1286 meters wide.

A piston exerts a force of 2,500 newtons on liquid in a cylindrical container. If the pressure on the top of the liquid is 12.5 kilopascals, find the area of the surface of the liquid, in square meters. ? please help

Answers

Here are the choices.

A. 200 m
B. 31.25 m
C. 0.2 m
D. 5 m

Pa = N/m²
m² = N/Pa

12.5 kPa = 12500 Pa

m² = N/Pa
m² = 2500 / 12500
m² = 0.2

C. 0.2 m²

So the correct answer is 0.2m^2

Suppose that now you want to make a scale model of the solar system using the same ball bearing to represent the sun. How far from it would you place a sphere representing the earth? (Center to center distance please.) The distance from the center of the sun to the center of the earth is 1.496×10111.496×1011 m and the radius of the sun is 6.96×1086.96×108 m.

Answers

In this exercise we have to use the knowledge in distance, in this way we will find that the proportional distance found is:

$d = 0.645 m$

So from the information given in the text we find that:

The distance from the center of the sun to the center of the earth is $1.496*10^(11) \ m$

The radius of the sun is $6.96*10^(8)m$

We need to assume a radius for the ball bearing, so suppose that the radius is $3 mm$

First, we need to find in what way or manner often the radius of the brightest star exist considerable respect to the range of the ball significance, that exist given apiece following equating:

$(r_a)/(r_b)= \frac{6.96*10^8}{3*10{-3}} =2.32*10^(11)$

Now, we can calculate the distance from the center of the sun to the center of the sphere representing the earth:

$d_(s) = (d_(e))/(r_(s)/r_(b)) = (1.496 \cdot 10^(11) m)/(2.32\cdot 10^(11)) = 0.645 m$

See more about distance at brainly.com/question/989117

Answer:

d = 0.645 m(assuming a radius of the ball bearing of 3 mm)

Explanation:

The given information is:

The distance from the center of the sun to the center of the earth is 1.496x10¹¹m = $d_(e)$
The radius of the sun is 6.96x10⁸m = $r_(s)$

We need to assume a radius for the ball bearing, so suppose that the radius is 3 mm = $r_(b)$ .

First, we need to find how many times the radius of the sun is bigger respect to the radius of the ball bearing, which is given by the following equation:

$(r_(s))/(r_(b)) = (6.96\cdot 10^(8)m)/(3\cdot 10^(-3)m) = 2.32\cdot 10^(11)$

Now, we can calculate the distance from the center of the sun to the center of the sphere representing the earth, $d_(s)$ :

[tex] d_{s} = \frac{d_{e}}{r_{s}/r_{b}} = \frac{1.496 \cdot 10^{11} m}{2.32\cdot 10^{11}} = 0.645 m

I hope it helps you!

The gravitational force between two objects is F. If masses of both the objects are halved without altering the distance between them, the gravitational force would become: Option a) F/4 Option b) F/2 Option c) 2F Option d) F^2

Answers

Answer:F/4

Explanation:

F1=G M1M2/R^2

F2=G M1M2/4R^2 (1/2*1/2)

F1/F2=G M1M2/R^2 *G M1M2/4R^2

NOW everything gets canceled and we are left with-

F1/F2=4

F1/4=F2

so Option a is right.

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Two objects are traveling on the same track. for 10 s, object x has an average acceleration of 3.0 m/s/s. if object y has an initial velocity of 0 m/s and a final velocity of 25 m/s after 10 s, how does it acceleration compared to object x's?