A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answers

Answer 1

Answer:

The specific heat of the unknown sample has been $\rm \bold{0.192\;\;J/g^\circ C}$ .

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat (c) for a substance can be given by:

$Q=mc\Delta T$ ......(i)

Where, the heat required by the substance, $Q=345.2\;\text J$

The mass of the substance has been, $m=89.5\;\text g$

The change in temperature of the system has been, $\Delta T$

The change in temperature has been given as:

$\Delta T=T_f-T_i$

The initial temperature of the substance, $T_i=285\;\text K$

The final temperature of the substance, $T_f=305\;\text K$

Substituting the values for the change in temperature, $\Delta T$ :

$\Delta T=305\;-\;285\;K\n\Delta T=20\;\text K$

Substituting the values in equation (i):

$345.2=89.5\;*\;c\;*\;20\n345.2=1,790c\nc=0.192\rm \;J/g^\circ C$

The specific heat of the unknown sample has been $\rm \bold{0.192\;\;J/g^\circ C}$ .

For more information about specific heat, refer to the link:

brainly.com/question/2094845

Answer 2

Answer: The specific heat is the heat needed per unit mass to raise the temperature by 1 degree celsius. So the specific heat = heat/(mass*ΔT) = 345.2/[89.5*(305-285)]=0.193 J/(g*℃). When using ΔT, the unit K and ℃ are the same.

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Answers

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hi myself thx for the answers

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