Using newton's second law of motion, if the force on an object is 20n, and its mass is 5g, what is the acceleration? Can someone explain to me in a simple way how to do this? I have tried but the formulas I see are confusing. Thank you :)

Answers

Answer 1
Answer:

Answer: The acceleration of the object will be 4000 m/s^2

Explanation:

According to second law of motion:

Force(F)=mass(m)* acceleration(a)

Unit of the force: N=kg* m/s^2

According to question we have :

Force = 20 N

Mass of the object = 5 g = 0.005 kg (1 kg =1000 g)

Acceleration = ?

By using the second law of motion = F= ma

20 N= 0.005 kg* a

a=(Force)/(mass)=(20 N)/(0.005 kg)=4000 m/s^2

The acceleration of the object will be 4000 m/s^2

Answer 2
Answer: Do 20 divided by 5 and you'll get 4! All you have to do is take the net force (20n) and divide it by the mass (5g) and you'll have the answer! :)

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Which explains how the Coriolis effect causes air circulation? A.
Air from the equator moves toward the poles slower than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator faster than the ground below it, so friction causes it to veer to the west.

B.
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C.
Air from the equator moves toward the poles faster than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator slower than the ground below it, so friction causes it to veer to the west.

D.
Air from the poles moves toward the equator faster than the ground below it, so friction causes the air to veer east. In contrast, air from the equator moves toward the poles slower than the ground below it, so friction causes it to veer to the west.

Answers

The Coriolis effect causes air circulation when Air from the equator moves toward the poles slower than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator faster than the ground below it, so friction causes it to veer to the west. The answer is letter A

Answer:

The answer to your question is A. Hope this helped

Which statement is true for a sound wave entering an era of a warmer air ?A. The wave travels faster and with the same wavelength
B. The wavelength travels at the same speed but with an increased wavelength
C. The wave travels at the same speed and with the same wave length
D. The wave travels slower and with an increased wavelength
E. The wave travels faster and with an increased wavelength

Answers

Answer:E
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a car accelerates for 5 seconds at 2.1 m/s squared if the car intentionally has a speed of 10 m/s what is its new speed

Answers

Answer:

final velocity will be

v_f = 20.5 m/s

Explanation:

As we know that initial speed of the car will be

v_i = 10 m/s

acceleration of the car is

a = 2.1 m/s^2

time taken is

t = 5 s

now we know that

v_f = v_i + at

v_f = 10 + (2.1* 5)

v_f = 10 + 10.5 = 20.5 m/s

Hey - for this problem you will find out your new velocity (similar to speed)

You take your Initial Velocity and add to it all the gained velocity you get during this process (which is the Acceleration multiplied by the amount of Time you are accelerating for)

So we get (Final Velocity) = (Initial Velocity) + (Time)(Acceleration)

In your equations, thats (Final Velocity) = (10 meters/second) + (5 seconds)(2.1 meters/second/second)

Which is 10 + 10.2 = 20.2 meters/second

Longitudinal waves compress the medium they travel though. One example of a longitudinal wave is a

Answers

Answer: Waves in compressed string

Explanation:

Longitudinal waves are waves in which the vibration of the medium is going parallel to the direction of the waves produced by the medium.

Longitudinal wave can occur in compressed string. A compressed string displaced horizontally will transmit wave in the same horizontal direction. That's why they are longitudinal waves.

Answer:

It is sound waves

(I did USAtestprep)

Explanation:

Scientists use different types of microscopes to observe objects that are not visible to the naked eye. A scientist is reviewing various samples of pond water to determine what species of microorganisms live in the pond. The scientist wishes to make drawings of the structure of each microorganism and study each one's method of movement. Which of the following microscopes would be best for the scientist to use?a.

transmission electron microscope

b.

scanning electron microscope

c.

compound light microscope

d.

dissecting microscope

Answers

A compound light microscope is the correct answer. Compound light microscopes provide a clear picture of many microorganisms, such as protozoans, and are used to view their structures and movements. Often, in the field of Microbiology, compound light microscopes are used for observing living microorganisms.

Answer;

-Compound light microscope

Explanation;

-A compound microscope is a microscope that uses multiple lenses to enlarge the image of a sample. It is commonly used for viewing samples at high magnification (40 - 1000x), which is achieved by the combined effect of two sets of lenses: the ocular lens and the objective lenses.

-Compound microscopes usually include exchangeable objective lenses with different magnifications (e.g 4x, 10x, 40x and 60x), mounted on a turret, to adjust the magnification. These microscopes also include a condenser lens and iris diaphragm, which are important for regulating how light hits the sample.

A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be?

Answers

Answer:

294 J

Explanation:

To find the kinetic energy (KE) of a 3.00 kg toy falling from a height of 10.0 m, we'll use the kinetic energy formula: KE = 0.5 * m * v^2, where 'm' is the mass of the toy, and 'v' is its velocity.

We'll also apply the conservation of energy principle, which states that the total energy of an isolated system remains constant. This means that the gravitational potential energy (PE) of the toy at the initial height is equal to its kinetic energy just before hitting the ground.

The formula for gravitational potential energy is PE = m * g * h, where 'm' is the mass of the object, 'g' is the acceleration due to gravity, and 'h' is the height of the object.

So, we can equate these two expressions and solve for 'v':

0.5 * m * v^2 = m * g * h

v^2 = 2 * g * h

v = √(2 * g * h)

Plugging in the given values:

v = √(2 * 9.8 m/s² * 10.0 m)

v ≈ 14.0 m/s

Now that we have the velocity of the toy, we can calculate its kinetic energy using the KE formula:

KE = 0.5 * m * v^2

KE = 0.5 * 3.00 kg * (14.0 m/s)^2

KE ≈ 294 J

So, just before hitting the ground, the kinetic energy of the toy is approximately 294 joules.