Answer: The acceleration of the object will be 4000
Explanation:
According to second law of motion:
Unit of the force:
According to question we have :
Force = 20 N
Mass of the object = 5 g = 0.005 kg (1 kg =1000 g)
Acceleration = ?
By using the second law of motion = F= ma
The acceleration of the object will be 4000
Air from the equator moves toward the poles slower than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator faster than the ground below it, so friction causes it to veer to the west.
B.
Air from the equator moves toward the poles faster than the ground below it, so friction causes the air to veer west. In contrast, air from the poles moves toward the equator slower than the ground below it, so friction causes it to veer to the east.
C.
Air from the equator moves toward the poles faster than the ground below it, so friction causes the air to veer east. In contrast, air from the poles moves toward the equator slower than the ground below it, so friction causes it to veer to the west.
D.
Air from the poles moves toward the equator faster than the ground below it, so friction causes the air to veer east. In contrast, air from the equator moves toward the poles slower than the ground below it, so friction causes it to veer to the west.
Answer:
The answer to your question is A. Hope this helped
B. The wavelength travels at the same speed but with an increased wavelength
C. The wave travels at the same speed and with the same wave length
D. The wave travels slower and with an increased wavelength
E. The wave travels faster and with an increased wavelength
Answer:
final velocity will be
Explanation:
As we know that initial speed of the car will be
acceleration of the car is
time taken is
now we know that
Answer: Waves in compressed string
Explanation:
Longitudinal waves are waves in which the vibration of the medium is going parallel to the direction of the waves produced by the medium.
Longitudinal wave can occur in compressed string. A compressed string displaced horizontally will transmit wave in the same horizontal direction. That's why they are longitudinal waves.
Answer:
It is sound waves
(I did USAtestprep)
Explanation:
transmission electron microscope
b.
scanning electron microscope
c.
compound light microscope
d.
dissecting microscope
Answer;
-Compound light microscope
Explanation;
-A compound microscope is a microscope that uses multiple lenses to enlarge the image of a sample. It is commonly used for viewing samples at high magnification (40 - 1000x), which is achieved by the combined effect of two sets of lenses: the ocular lens and the objective lenses.
-Compound microscopes usually include exchangeable objective lenses with different magnifications (e.g 4x, 10x, 40x and 60x), mounted on a turret, to adjust the magnification. These microscopes also include a condenser lens and iris diaphragm, which are important for regulating how light hits the sample.
Answer:
294 J
Explanation:
To find the kinetic energy (KE) of a 3.00 kg toy falling from a height of 10.0 m, we'll use the kinetic energy formula: KE = 0.5 * m * v^2, where 'm' is the mass of the toy, and 'v' is its velocity.
We'll also apply the conservation of energy principle, which states that the total energy of an isolated system remains constant. This means that the gravitational potential energy (PE) of the toy at the initial height is equal to its kinetic energy just before hitting the ground.
The formula for gravitational potential energy is PE = m * g * h, where 'm' is the mass of the object, 'g' is the acceleration due to gravity, and 'h' is the height of the object.
So, we can equate these two expressions and solve for 'v':
0.5 * m * v^2 = m * g * h
v^2 = 2 * g * h
v = √(2 * g * h)
Plugging in the given values:
v = √(2 * 9.8 m/s² * 10.0 m)
v ≈ 14.0 m/s
Now that we have the velocity of the toy, we can calculate its kinetic energy using the KE formula:
KE = 0.5 * m * v^2
KE = 0.5 * 3.00 kg * (14.0 m/s)^2
KE ≈ 294 J
So, just before hitting the ground, the kinetic energy of the toy is approximately 294 joules.