what is 14b+3a=91?
I need to find the values of a and b please

Answers

Answer 1

Answer: $14b+3a=91\ \ \ \Rightarrow\ \ \ \ 14b=-3a+91\ /:14\n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ b=- (3)/(14)a +6 (1)/(2) \n \n \n14b+3a=91\ \ \ \Rightarrow\ \ \ \ 3a=-14b+91\ /:3\n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ a=-4 (2)/(3)b +30 (1)/(3)$

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Miguel and three of his friends went to the movies. They originally had $40. Each boy sent a total of $7.50 on a ticket. How much money did each boy have left after buying his ticket?
What is the value of the coefficient 2x^3+18x^2-18x-162=2(x+k)(x-k)(x+9)
What is the greatest common factor (GCF) of 3,9=
The improper fraction 11/8 is equivalent to?

Put these fractions in order from least to greatest:\frac{5}{10} , \frac{3}{16} , \frac{3}{4} , \frac{5}{48} PLEASE HELP !!!

Answers

The best thing to do is turn it to a percent.

5/10= 50% 3/16=18.75% 3/4= 75% 5/48= 10.41%

so its

5/48 3/16 5/10 3/4

Action movies make up 85% of Devon's movie collection. If he has 20 movies,how many action movies are in Devon's collection?

Answers

Method 1

We can find the number of Devon's movie collection by multiplying its percentage by the number of Action movies. That is;

Number of Devon's movie collection $= (85)/(100) * 20=(85)/(5) =17$

Method 2

We can also use ratio and proportion. According to the question, out of every 100 Action movies 85 are Devon's Movie collection. This means,

Action movies Devon's collection

100 85

20 $x$

If 100 corresponds to 85, then 20 will correspond to a less value than 85. If less more divides,Hence,

$x=(85 * 20)/(100)=17$ .

Therefore he has 17 movies that are in Devon's collection.

The answer is 17, because you know it’s going to be most of it, so you do 20 times .85 on your calculator, and you have your answer! :)

Which ratio is equivalent to 4 : 13? A.8 : 17 B.16 : 52 C.12 : 33 D.20 : 55

Answers

Your answer would be option B

Because multiplied by 4 the ratio would be 16:52

16: 52
Because you can multiply 4 by 4 to give 16 and 13 by 4 to give 52

How can 563*10 to the 3rd power be scientific notation.(Use the photo above please)

Answers

563*(10*10*10) that's you scientific notation

The angles of an equilateral triangle are congruent. If x represents the measure of one angle of an equilateral triangle, which equation represents the sum of the angle measures of the triangle ?1. x + x= 90%
2.x + x + x = 90%
3.x + x = 180%
4.x + x + x = 180%

Answers

4) x + x + x = 180°

An equilateral triangle has three sides of equal length. Its interior angles are also equal. Since interior angles of a triangle should sum up to 180°, then each angle is 60°, making each angle congruent with one another.

So if x is equal to one angle and triangles have three angles then,

x + x + x = 180°

or 3x = 180°

The equation represents the sum of the angle measures of the triangle is

x + x + x = 180%.

Option 4 is the correct answer.

We have,

The sum of the angle measures in any triangle, including an equilateral triangle, is always 180 degrees.

Since an equilateraltriangle has three congruent angles, each angle in the triangle is x degrees.

Therefore,

The equation that represents the sum of the angle measures of the equilateraltriangle is:

x + x + x = 180 degrees

Thus,

The correctequation is x + x + x = 180%.

Learn more about triangles here:

brainly.com/question/25950519

#SPJ6

The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formulaL(x) = 8(x - 2) + 1.

Which of the following statements are true? Select all that apply.
A. The functions are approximately equal on the interval 1.9 smaller than or equal to x larger than or equal to 2.1.
B. The functions have the same y-intercept.
C. The slope of the line equals g'(0).
D. The functions are approximately equal on the interval 0.5 smaller than or equal to x larger than or equal 1.0.
E. The graphs intersect at the point (2,1).
F. The slope of the line equals g'(2).
G. None of the above are true.

Answers

Using function concepts, it is found that the correct options are:

A. The functions are approximately equal on the interval 1.9 smaller than or equal to x larger than or equal to 2.1.
E. The graphs intersect at the point (2,1).
F. The slope of the line equals g'(2).

-------------------------------------------

The value of x we are interested is x = 2, thus, considering a margin, the functions are approximately equal between x = 1.9 and x = 2.1, which means that option A is correct, while option D is not.
The y-interceptof g is $g(0) = 0^3 - 4(0) + 1 = 1$ , while the y-intercept of L is $L(0) = 8(0 - 2) + 1 = -16 + 1 = - 15$ . Not the same, thus, option B is not correct.
The slope of the tangent line to g at x = 2 is the derivative of g at x = 2, that is, g'(2), thus option F is correct while option C is not.
At (2,1), the g(x) and L(x) intersect, thus, option E is correct.

A similar problem is given at brainly.com/question/22426360

well, about A and D, I just plugged the values on the slope formula of

$\bf \begin{array}{llll} g(x)=x^3-4x+1\n L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\n x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}$

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. $\textit{\huge \checkmark}$

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. $\textit{\huge \checkmark}$

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)? well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. $\textit{\huge \checkmark}$

for F, we know the slope of the line L(x) is 8, is g'(2) = 8? let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. $\textit{\huge \checkmark}$

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