what can go into 123 and 1000 evenly

Answers

Answer 1
Answer: Nothing can go into 123 and 1000 evenly. 3 can go into 123 evenly but not 1000. And other numbers won't go into 123 evenly.
Answer 2
Answer:

Answer:what the guy above this said

Step-by-step explanation:


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Help please! I have choral practice...

Answers

This polygon is composed of a right triangle and a parallelogram.

The area of right angle :
A_\Delta=(1)/(2)\cdot15\cdot8=(1)/(2)\cdot120=\boxed{60\ (cm^2)}

The area of the
parallelogram:
A_P=15\cdot(13-8)=15\cdot5=\boxed{75\ (cm^2)}

The area of the polygon is equal:A=A_\Delta+A_P

Therefore, the answer is:
\boxed{\boxed{A=60\ cm^2+75\ cm^2=135\ cm^2}}

Slice the picture in half, across the middle dotted line.

The top half is a triangle.  Its base is 15cm and its height is 8cm .
Area of a triangle is (1/2) (base x height) = (1/2) (120cm²) = 60 cm².

The bottom half is a parallelogram.  Its base is 15cm and its height is 5cm.
Area of a parallelogram is (base x height) = (15cm x 5cm) = 75 cm².

Add the two pieces together.  (60cm²) + (75 cm²) = 135 cm²

Breathe from the diaphragm, enunciate, and watch the conductor.


What does 2(x+3)+(4x-5) equal?

Answers

Answer:

6x+1

Step-by-step explanation:

Open parenthesis:

2x+6+4x-5

Combine like terms:

6x+1

0.65 is 10 times as much as _____ and 1/10 of _____

Answers

10 times as much as .065 and 1/10 of 6.5

3What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 5:1?
2
AK (7.2)
1
y =
m
m+
-)(x2 - wa) + v
2 3 4 5 6 7 8 9 10 11 x
-11
-2
-3
-4
-5
-8
0-5
0 0
O 6
ibd
-10
J (1,-10)

Answers

The y coordinate of the point that divides J to K in the ratio 5 : 1 is 0.

Distance

If a point O(x, y) divides the line segment AB with end points A(x₁, y₁) and B(x₂, y₂) in the ratio n:m, the coordinate of O is:

x=(n)/(n+m) (x_2-x_1)+x_1\n\ny=(n)/(n+m) (y_2-y_1)+y_1

Let O(x, y) represent the point dividing J to K in the ratio 5 : 1. K(7,2) and J(1, -10)Hence:

y=(5)/(5+1)(2-(-10)) + (-10)=0

The y coordinate of the point that divides J to K in the ratio 5 : 1 is 0.

Find out more on Distance at: brainly.com/question/17273444

Answer:

0

Step-by-step explanation:

Given the points J (1,-10) and K (7, 2)

From the section formula

(x,y)=\left((mx_2+nx_1)/(m+n), (my_2+ny_1)/(m+n)\right)

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

y=(my_2+ny_1)/(m+n)\nm=5, n=1, y_1=-10, y_2=2\nTherefore:\ny=(5*2+1*-10)/(5+1)\n=(10-10)/(6)\n=0

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.

What is the calculation for 15-(0.7×3)

Answers

The calculation to 15-(0.7x3) equals 12.9
PEMDAS

15 - (0.7*3)

0.7 * 3 = 2.1

15 - 2.1 = 12.9

Answer: 12.9

Line CD passes through points C(3, –5) and D(6, 0). What is the equation of line CD in standard form?

Answers

To answer the problem above, we can start with the formation of the point-slope form of a line. The slope is solved through,

                                    m = (y2 - y1)/(x2 - x1)
                                     m = (0 - -5)/ (6 - 3) = 5/3

The point - slope form of the equation of the line is,

                                    y - y2 = m(x - x2)

Substituting the known data, 

                                   y - 0 = (5/3)(x - 6)
This simplifies into, 

                                    y = 5x/3 - 10

Thus, the standard form of the equation is, 

                                      5x - 3y = 30

Answer: 5x-3y=30

Step-by-step explanation:

We know that the equation a line in point-slope form passing through points (a,b) and (c,d) is given by :-

(y-b)=(d-b)/(c-a)(x-a)

Then , the equation a line in point-slope form passing through points C(3, –5) and D(6, 0) is given by :-

(y-(0))=(0-(-5))/(6-3)(x-6)\n\n\Righarrow\ y=(5)/(3)(x-6)\n\n\Rightarrow\ 3y=5x-30\n\n\Rightarrow\ 5x-3y=30

Hence, the equation of line CD in standard form  : 5x-3y=30