The zeros of the function f(x) = (x + 2)^2 - 25 are(1) -2 and 5 (3) -5 and 2
(2) -3 and 7 (4) -7 and 3

Answers

Answer 1
Answer: The\ zeros\ of\ a\ function\ f(x)\ is\ when\ f(x)=0.\n------------------------\nf(x)=(x+2)^2-25\nthe\ zeros,\ if\ f(x)=0\iff(x+2)^2-25=0\n\n(x+2)^2-5^2=0\ \ \ \ |use\ a^2-b^2=(a-b)(a+b)\n\n(x+2-5)(x+2+5)=0\n\n(x-3)(x+7)=0\iff x-3=0\ or\ x+7=0\n\nx-3=0\ \ \ |add\ 3\ to\ both\ sides\n\boxed{x=3}\nor\nx+7=0\ \ \ \ \ |subtract\ 7\ from\ both\ sides\n\boxed{x=-7}\n\nAnswer:\boxed{(4)\ -7\ and\ 3}
Answer 2
Answer: f(x) = 0

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1) 

İf    x=-2,

f(-2) =  ((-2) + 2 ) ^(2) -25 = 0-25 = -25

f(x) ≠ 0

If   x= 5

f(5) =  (5+2)^(2) - 25 = 49 - 25 = 24

f(x) ≠ 0
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2)  

If  x= -3

f(-3) =  ((-3) + 2) ^(2) - 25 = 1 -25 =-24

f(x) ≠ 0

If  x= 7

f(7) =  (7+2)^(2) - 25 = 81 - 25 = 56

f(x) ≠ 0

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3)

If  x= -5

f(-5) =  ((-5)+2)^(2) - 25 = 9-25 = -16

f(x) ≠ 0

If  x= 2

f(2) =  (2+2)^(2) - 25 = 16-25 = -9

f(x) ≠ 0
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4) 

If  x= -7

f(-7) =  ((-7) +2 )^(2)  - 25 = 25-25 =0

f(x) =0  ✔

If  x= 3

f(3) =  (3+2)^(2) - 25 = 25-25 =0

f(x) =0  ✔

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Answer: 4

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Answers

Measure of angle 3 should be 33! 180-123=57. Then 90-57=33

Guy decides to get in shape by running. The first day, he runs 1 mile in 12 minutes. Two months later he has decreased his mile time by 25%. What is his mile time now?

Answers

If you would like to know what is his mile time two months later, you can calculate this using the following steps:

25% of 12 minutes = 25% * 12 = 25/100 * 12 = 3 minutes

12 minutes - 3 minutes = 9 minutes

The correct answer would be 9 minutes.

Answer: 9 minutes.

Step-by-step explanation: 12-3=9.

3 x 4 = 12, 3 x 3 x 3=9, 3 x 3 x 3 x 3=12, 4+4+4=12. So if you think about it, three goes into twelve four times, just like a quarter goes into a dollar four times, or 25 goes into 100 four times. So, if you take twelve minus three and equal it, it is nine.

The sales tax in Bill's state is 6%. Bill bought a Scion having a sales tax of $820. What was the cost of the car? Round to the nearest dollar. A. $13,666 B. $13,668 C. $13,665 D. $13,667

Answers

tge answer is B I THINK

What is the rule for the function shown in the table? x|-1|0|1|2
y|-2|1|4|7

A. y = 1/3x + 1
B. y = 3x +1
C. y = 1/3x
D. y = 1/2x + 1

Answers

It's a linear function.
y=mx+b \n \nx_1=-1 \n y_1=-2 \n \n x_2=0 \n y_2=1 \n \nm=(y_2-y_1)/(x_2-x_1)=\fac{1-(-2)}{0-(-1)}=(1+2)/(0+1)=(3)/(1)=3 \n \ny=3x+b \n(0,1) \n1=3 * 0+b \n1=0+b \nb=1 \n \n\boxed{y=3x+1} \Leftarrow \hbox{answer C}

Answer:

The answer is B: y = 3x + 1

Step-by-step explanation:

Look at the response above this to see the explanation!

Find the value of x.

Answers

Answer:

x=17

Step-by-step explanation:

6x+33+45=180

6x+78=180

6x=102

x=17

x is equal to 17
x = 17

What is if g(x,y,z) = x + y and S is the first octant portion of the plane 2x + 3y + z = 6 ?

Answers

The question asks for the value of I=\int\int_Sx+y\textrm{ }dS where S=\{(x,y,z)\mid2x+3z+y=6,x\ge0,y\ge0,z\ge0\}.

First let's look at what that surface looks like.

Letting y=z=0 yields x=3
Letting x=z=0 yields y=2
Letting x=y=0 yields z=6

Therefore S is the area of the triangle defined by the three points (3,0,0),(0,2,0),(0,0,6).

We can thus reformulate the integral as I=\int_(z=0)^6\int_(x=0)^(6-z)x+ydxdz.

By definition on the plane y=\frac{6-2x-z}3 thus I=\int_(z=0)^6\int_(x=0)^(6-z)x+\frac{6-2x-z}3dxdz=\int_(z=0)^6\int_(x=0)^(6-z)2+\frac x3-\frac z3 dxdz

I=\int_(z=0)^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_(x=0)^(6-z)dz=\int_(z=0)^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz

I=\int_(z=0)^6\frac{z^2}2-6z+18=\left[\frac{z^ 3}6-3z^2+18z\right]_(z=0)^6=36-108+108

Hence \boxed{I=\int\int_Sx+y\textrm{ }dS=36}