How many milliliters of 0.02 M HCl are needed to react completely with 100 mL of 0.01 M NaOH?A) 200 mL
B) 100 mL
C) 75 mL
D) 50 mL
E) 25 mL

Answers

Answer 1

Answer:

Answer: Option (D) is the correct answer.

Explanation:

Molarity is number of moles divided by volume of the solution.

Mathematically, Molarity = $(no. of moles)/(Volume)$

Also, in the given situation number of moles of both HCl and NaOH are equal. Therefore, volume of HCl will be calculated as follows.

$M_(HCl)V_(HCl)$ = $M_(NaOH)V_(NaOH)$

$0.02 M * V_(HCl)$ = $0.01 M * 100 mL$

$V_(HCl)$ = $(0.01 M * 100mL)/(0.02)$

= 50 mL

Thus, we can conclude that volume of HCl is 50 mL.

Answer 2

Answer: The reaction of HCl and NaOH is HCl + NaOH = NaCl + H2O. So the mole number of HCl and NaOH is equal. So the volume of HCl =0.01*0.1/0.02=0.05 L =50 ml. So the answer is D).

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How many moles of aluminum oxide can be made if 5.23 mol Al completely react

Answers

Answer:

2..615moles of Aluminium oxide

Explanation:

4Al + 3O2 -------> 2Al2O3

(5.23mol Al)×(2molaAl2O3) /(4molAl)

2.615moles of Aluminium oxide

4Al + 3O2 --> 2Al2O3

(5.23mol Al)(2mol Al2O3/4mol Al) = 2.62mol Al2O3

Identify the number of neutrons in one atom of sulfur with an isotopic mass number of 34 Amu

Answers

Mass number = number of neutrons + number of protons

In a periodic table, or other tables, you find that the atomic number of sulfur is 16. That means it has 16 protons.

Then the number of neutrons = 34 - 16 = 18.

Which is true about the temperature of a gas?At a higher temperature, the particles have a higher average kinetic energy.
At a higher temperature, the volume of the gas is smaller.
At a lower temperature, there are more particles in the gas.
At a lower temperature, the particles in the gas move faster.

Answers

The statement that true about the temperature of a gas is at a higher temperature, the particles have a higher average kinetic energy. The rest of the choices do not answer the question above.

Answer:

Explanation:

Took the test Got it right

Which pair of atoms has the most polar bond?(1) H−Br
(2) H−Cl
(3) I−Br
(4) I−Cl

Answers

For the question given above, option 2 which is H-Cl pair of atoms has the most polar bond among the four of them.

The larger the value of the electronegativity, the greater the atom’s strength to attract a bonding pair of electrons. Hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. The electron pair that is bonding HCl together shifts toward the chlorine atom because it has a larger electronegativity value.

Among the presented bonds, the most polar is H-Cl.

What is polarity?

Polarity is a separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment.

The higher the difference in electronegativity, the more polar the bond.

We will calculate the difference in electronegativity for each bond.

(1) H−Br

ΔEN = |EN(H)-EN(Br)| = |2.2-3.0| = 0.8

(2) H−Cl

ΔEN = |EN(H)-EN(Cl)| = |2.2-3.2| = 1.0

(3) I−Br

ΔEN = |EN(I)-EN(Br)| = |2.7-3.0| = 0.3

(4) I−Cl

ΔEN = |EN(I)-EN(Cl)| = |2.7-3.2| = 0.5

Among the presented bonds, the most polar is H-Cl.

Learn more about polarity here: brainly.com/question/8857494

Which two formulas represent Arrhenius acids?(1) CH3COOH and CH3CH2OH
(2) HC2H3O2 and H3PO4
(3) KHCO3 and KHSO4
(4) NaSCN and Na2S2O3

Answers

Answer : The correct option is, (2) $HC_2H_3O_2\text{ and }H_3PO_4$

Explanation :

Arrhenius theory : It sates that an acid is a type of substance that ionizes in the water to give the hydronium ion or hydrogen ion $(H^+)$ and a bases is a type of substance that ionizes in the water to give hydroxide ion $(OH^-)$ .

Or we can say that,

Arrhenius acid are those which can easily gives the hydrogen ion in a solution and Arrhenius base are those which can easily gives the hydroxide ion in a solution.

In option 1, $CH_3COOH$ can easily gives the hydrogen ion but $CH_3CH_2OH$ can not gives the hydrogen ion due to stronger O-H bonding. So, these formulas does not represent Arrhenius acids.

In option 2, $CH_3COOH$ and $H_3PO_4$ can easily gives the hydrogen ion. So, these formulas represent Arrhenius acids.

In option 3, $KHCO_3$ and $KHSO_4$ can not gives the hydrogen ion because both are the salts. So, these formulas does not represent Arrhenius acids.

In option 4, $NaSCN$ and $Na_2S_2O_3$ can not gives the hydrogen ion because no hydrogen present in the compound. So, these formulas does not represent Arrhenius acids.