A stuntman jumps from the roof of a building to the safety net below. How far has the stuntman fallen after 1.6 seconds?
Answers
The distance covered by the stuntman in 1.6 meters after he jumps form the roof of a building is 12.544 meters.
What is acceleration?
Acceleration is the rate of change of the velocity of an object with respect to the time taken to travel. Acceleration is a vector quantity. The orientation of an object's acceleration can be given by the orientation of the net force which is acting on that object.
The stuntman fallen after 1.6 meters after he jumps from the roof, the distance covered by the stuntman is:
s = ut + 1/2 at²
s = distance or displacement,
u = initial velocity,
t = time taken,
a = acceleration of the object
s = 0 × 1.6 + 1/2 × 9.8 × (1.6)²
s = 0 + 4.9 × 2.56
s = 12.544m
Therefore, the distance covered by the stuntman is 12.544 meters.
Learn more about Acceleration here:
#SPJ2
Given,
Time = 1.6 seconds
We know,
initial velocity = 0 m/s²
acceleration (due to gravity) = 9.8 m/s²
Now,
We know,
So, the stuntman has fallen 12.544 meters.
Related Questions
Name three devices that can store electric potential energy
What if the bird sitting on tansmission wire touches both terminal's wire ?why
Compare the sounds produce by wave A and wave B. The human ear would hearA) wave A as a louder sound than wave B. B) wave A as a higher pitched sound than wave B. C) wave A and B with the same pitch, but wave A as louder. D) wave B as a louder and higher pitched sound than wave A.
A 25-gram paper cup falls from rest off the edgeof a tabletop 0.90 meter above the floor. If thecup has 0.20 joule of kinetic energy when it hitsthe floor, what is the total amount of energyconverted into internal (thermal) energy duringthe cup’s fall?(1) 0.02 J (3) 2.2 J(2) 0.22 J (4) 220 J
Planck's constant (h) = 6.63 × 10⁻³⁴ Js
Frequency (f) = c ÷ λ
c = speed light in vacuum = 3.00 × 10⁸ms⁻¹
Ekmax = hf - Φ
Wavelength must be in metres, so it'll be 590×10⁻⁹
I've worked this out and gotten two different answers so I thought I'd check to see which one is right.
Answers
Put that into the equations:
f = c/λ = 3.0 x10^8/5.2 ×10^-7 = 5.77 x10^14 (3 s.f.)
(5.77 x10^14) x (6.63 x10^-34) - (1.1 x10^-19) =
2.73 x10^-19 J
Answers
Answer:
120
Explanation:
KE = (mv^2)/2
= ((0.15)(40)^2)/2
= ((0.15)(1600))/2
= 240/2
False
Answers
Answer:
This expression is True
Since the Ohm's Law "states that the current )I) through a material between two points is proportional to the voltage across the two points." and i defined by this formula:
Where V represent the voltage and it's a value related to the emf and the potential
I represent the current
R represent the resistance.
And for this case we have an expression for this case relating the emf , potential, current and resistance
Explanation:
This expression is True
Since the Ohm's Law "states that the current )I) through a material between two points is proportional to the voltage across the two points." and i defined by this formula:
Where V represent the voltage and it's a value related to the emf and the potential
I represent the current
R represent the resistance.
And for this case we have an expression for this case relating the emf , potential, current and resistance
V = IR The relationship between electrical resistance, current, and voltage is defined by the mathematical relationship V= IR and is referred to as Ohm's law. In this equation "V" stands for voltage, measured in volts, "I" stands for current, measured in amperes, and "R" stands for resistance, measured in Ohms (Ω ).Common sources of voltage in circuits may be chemical cells (a battery is a combinations of cells) and generators. Sources of electrical resistance in circuits may include resistors, light bulb filaments, wire conductors and other electric devices. When solving Ohm's law problems you are expected to solve for any unknown variable.
Example: Determine the voltage of the circuit shown below in diagram "A".Diagram A In this circuit we are given the current from the ammeter .2A. We also can determine the resistance. Since this is a series circuit the total resistance is the sum of the resistances of L1 and L2, 70Ω . We set the problem up and solve it like this.
V=IR
V=.2A 70Ω
V= 14VThe answer is 14V
2. What can you say about the total momentum before and after the collision?
3. What do you think would happen to the velocity of each ball after the collision if the masses and initial velocities of each ball were the same?
4. The mass of ball A is 10 kilograms and the mass of ball B is 5 kilograms. If the initial velocity is set to 3 meters per second for each ball, what is the final velocity of ball B if the final velocity of ball A is 2 meters per second? Use the elastic collision equation to find the final velocity of ball B. Assume ball A initially moves from right to left and ball B moves in the opposite direction. Identify each mass, velocity, and unknown. Show your work, including units, and indicate the direction of ball B in your answer.
5. If the mass of each ball were the same, but the velocity of ball A were twice as much as ball B, what do you think would happen to the final velocity of each ball after the collision? To answer this question, create a hypothesis in the form of an if-then statement. The “if” is the independent variable, or the thing that is being changed. The “then” is the dependent variable, or what you will measure as the outcome.
(Please show your work if you can)
Answers
2. The total momentum is conserved.
3. The same thing would happen if the collision is totally elastic.
For 4 and 5.
Using the conservation of momentum equation
m1v1 + m2v2 = m1'v1' + m2'v2'
Answers
potental energy(PE) =0
kinetic energy(KE) = 0.5mv^2 = 0.5(1)(30^2) = 450
at the highest point the ball does not moved, v=0
potential energy at its maximum
kinetic energy = 0
Energy is conserved then
total energy before = after
PE1 + KE1 = PE2 + KE2
0 + 450 = PE2 + 0
conservation of energy is fun fact
g=10m/s^2 (assuming)
u=30m/s
height(h)=u^2/2g
=900/20=45m
P.E.=mgh
=1×10×45=450 joules
Answers
t = 2 s
v = 10 m/s
v = v o + a t
a t = v - v o
a = ( v - v o ) / t
a = ( 10 m/s - 6 m/s ) / 2 s = 4 m/s / 2 s = 2 m/s²
Answer:
The runner`s acceleration is 2 m/s².