What is the slope of any line parallel to the line 2x −3y = 7?

Answers

Answer 1

Answer:

Slope means which represents the steepness of a line and the slope of any line parallel to the line $2x-3y=7$ is $(2)/(3)$ .

What is the slope of the line?

The slope is used to describe the steepness and direction of lines.

Here the given lines are

$2x-3y=7$

Rearrange the equation into the form $y=mx+c$ where $m$ is the slope and $c$ is the y-intercept.

$y=mx+c\n-3y=-2x+7\n-(-3y)=-(-2x+7)\n3y=2x-7\ny=(2x)/(3)-(7)/(3)$

The slope of the equation is

$m=(2)/(3)$

Hence, the slope of any line parallel to the line $2x-3y=7$ is $(2)/(3)$ .

To know more about slope

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Answer 2

Answer: the slope of paralel lines are the same.

therefore to find the slope of a paralel line to 2x −3y = 7, you need to find the slope of this line :)

to do that, we just need to change this into the line equation format, which is y = mx + b (y is the y point, x is the x point, m is the slope, and b is the y intercept)

2x - 3y = 7

7 = 2x - 3y

7+ 3y = 2x

3y = 2x - 7

y = (2/3)x - (7/3)

so the slope is 2/3

any paralel line will have an equation of y = (2/3)x + b

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Caroline bought 20 shares of stock at 101/2, and after 10 months the value of the stocks was 111/4. If Caroline were to sell all her shares of this stock, how much profit would she make? A. $10 B. $15 C. $225 D. $210

Answers

Answer:

$15 profit would Caroline make .

Option (B) is correct .

Step-by-step explanation:

As given

$Caroline\ bought\ 20\ shares\ of\ stock\ at\ 10 (1)/(2).$

i.e

$Caroline\ bought\ 20\ shares\ of\ stock\ at\ (21)/(2).$

$After\ 10\ months\ the\ value\ of\ the\ stocks\ was\ 11 (1)/(4).$

i.e

$After\ 10\ months\ the\ value\ of\ the\ stocks\ was\ (45)/(4).$

Thus

Profit = (Cost of the 20 stock after 10 month - Cost of the 20 stock before 10 month ) × Total number of shares .

$Profit = ((45)/(4) - (21)/(2))* 20$

L.C.M of (4,2) = 4

$Profit = (45 - 21* 2)/(4)* 20$

$Profit = (45 - 42)/(4)* 20$

$Profit = (3)/(4)* 20$

Profit = 3 × 5

Profit = $15

Therefore the $15 profit would Caroline make .

Option (B) is correct .

Your answer will be $15.

How do u multiply x^2-4 over x^2-1 times x+1 over x^2+2x

Answers

$(x ^ 2-4 )/(x ^ 2-1)*( x + 1 )/(x ^ 2 +2 x)=(x ^ 2-2^2 )/(x ^ 2-1)*( x + 1 )/(x(x +2 )) =\n \n \n =((x -2)\not(x+2)^1 )/((x -1)\not(x+1)^1)*( \not(x + 1)^1 )/(x\not(x +2)^1 )= ( x-2 )/(x(x-1)) \n \n \n \na^2-b^2 =(a-b)(a+b)$

(X2-4)/(x2-1). * (x+1)/(x2+2x)
[(x-2)(x+2)]/[(x-1)(x+1)]. * (x+1)[x(x+2)]
(x-2)/(x-1) * 1/x
(x-2)/(x2-x)

4(8x + 1) − 3x = 2 − 3(4x + 2)
good luck!

Answers

Answer:

x= −8/41

Step-by-step explanation:

Long divide the coefficients to find:

−

Explanation:

I like to long divide the coefficients, not forgetting to include

for any missing power of

...

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The process is similar to long division of numbers.

For a more fully explained example, see:

What is the excluded value?a/b-2

1. a=0
2. b=2
3. b=-2
4. none of the above

Answers

Answer: The correct option is (2) $b=2.$

Step-by-step explanation: We are given to find the exclude value for the following algebraic expression:

$E=(a)/(b-2)~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

for a rational expression, we must exclude those values for which the denominator of the fraction becomes zero.

So, in equation (i), the excluded value will be given by

$b-2=0\n\n\Rightarrow b=2.$

Thus, the required excluded value is $b=2.$

Option (2) is CORRECT.

b - 2 = 0 since you cannot divide by 0
b = 2 solve for b. this is where the function is undefined

John needs to make a scale drawing of his school building for art class. If the building is 256.25 meters long, and John scales it down using a ratio of 25 meters to 1 inch, how long will the building be in the sketch?

Answers

So we want to know how long will the scale drowing of the building be if the building is 265.25m long and the scale is 1 inch on the drawing is equal to 25 meters of the building. To find the answer lets scale the building. If the real length of the building is 256.25 meters, then the number of inches will be: 256.25/25=10.25 inches.

The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how many centimeters long is the smaller leg please explain how you got it

Answers

$b=a+3\n c=a+6\n a^2+b^2=c^2\n\n a^2+(a+3)^2=(a+6)^2\n a^2+a^2+6a+9=a^2+12a+36\n a^2-6a-27=0\n a^2-9a+3a-27=0\n a(a-9)+3(a-9)=0\n (a+3)(a-9)=0\n a=-3 \vee a=9\n$

The length can't be negative, so the answer is 9 cm.

Let the smaller leg be x.

Thus, larger leg = 3 +x
Thus, hypotenuse = 6 + x

Applying pythagoras theorum ;

$(6+x)^2 = x^2 + (3+x)^2 \n \n or, 6^2 + 12x + x^2 = 3^2 + 6x + x^2 \n \n i.e., 36 + 12x = 9 + 6x \n \n =>6x = 45 \n \n => x = 9$

Thus, the length of smaller peg is 9 cm.

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