Calculate freezing temperature of.5 M sodium chloride solution. Assume that the molality of each solution is .5 Ma. -.93 Celsius
b. -1.86 Celsius
c. -3.72 Celsius
d. -.538 Celsius

Answers

Answer 1

Answer: Given,
Molality = .5M

We know, Kf = 1.86

Now,
Δ T = M x Kf
= 1.86 * 0.5
= 0.93 °C

Now,
Freezing point = Initial freezing point - Δ T
= 0°C - 0.93°C
= -0.93°C
So, the answer is A

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A gas in a rigid container at 25°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 atm. What is the new temperature of the gas?a...–44.2°C

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Answers

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Question: A gas in a rigid container at 25Â°C has a pressure of 0.96 atm. A change in temperature causes the pressure to increase to 1.25 atm. What is the new temperature of the gas? a...â€“44.2Â°C b....32.6Â°C c....115Â°C d...388Â°C Answer: Answer is c....115Â°C.

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Answers

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Answers

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