What is 5.36201 rounded to 1 decimal place

Answers

Answer 1

Answer: 5.36201 rounded to the first decimal place will be 5.4

this is because there is a general rule that numbers from 5 to 9 are rounded up to the next highest number. thus we need to look at the first 2 decimal places, 5.36

6 is higher than five, so it will be rounded up to 10. you cannot have a double digit number in a single decimal place, so you carry it over to the next one to the left, in this case being 3. 3 + 1 = 4, and hence we attain 5.4

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Simplify -1/3 divided by 2/-6 −4 −22 4
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T - 4+2 +2+3What is the degree of the polynomial?

Is this correct the highlighted is the one i think.

Answers

so that is correct because we notice that the line passes through the points 5,-5 and -5,5
we notice that y is negative x so therefor D is the correct answer

IT IS! You are absolutely Right!
Now that (0,0) is the origin, it is also a point where the line lies. (-1, 1) is also a point where the line lies(in Quadrant II). And (1, -1) is the total opposite of (-1, 1).
It is in Quadrant IIII, but it is also on where the line lies

I/5+9=17
two step equations

Answers

Answer:

i = 40

Step-by-step explanation:

i/5 + 9 = 17

i/5 = 8

i = 40

So, the answer is i = 40

I = 40
This is the answer

Convert z = 9cos200° + 9isin200° from polar form to rectangular form.-8.46 - 3.08i
-2.09 – 6.84i
8.46 + 3.08i
2.09 + 6.84i

Answers

Answer:

z = -8.46 - 3.08i.

Step-by-step explanation:

cos 200 = -0.93969 so 9 * cos 200 = -8.46 to the nearest hundredth.

sin 200 = -0.3420 so 9 * sin 200 = -3.08 to nearest hundredth.

What is 8 2/7 - 7 1/3

Answers

.95238 in decimal form or 20/21 in fraction form

58/7 - 22/3

20/21 Fraction form

20/21= 0.95 ( decimal )

I hope that's help and have a great night

Find the y-intercept of y=4(1/3)^x+1+2

Answers

y intercept is where the line crosses the y axis, that only happens when x=0
so set x=0 and find what y intercet is

y=4(1/3)^0+1+2
y=4(1)+1+2
y=4+1+2
y=5+2
y=7

y intercept is y=7 aka the point (0,7)

Determine how many points the parabola has in common with the x-axis and whether it's vertex lies above, on, or below the x-axis.

Answers

Points "in common with the x-axis" are also known as the roots of the quadratic equation $x^2-12x+12=0$ . You can apply the quadratic root formula to determine the roots, and also to determine how many such roots there are. With a quadratic (whose graph is a parabola), there can be maximum of 2 roots. But under certain circumstances, there may be only one or no such root.

The root formula for a generic quadratic $ax^2+bx+c$ is as follows:

$x_(1,2)=(-b\pm√(b^2-4ac))/(2a)$

The expression $b^2-4ac$ under the square root is called the determinant. It is called so because it determines the number of real roots. If the determinant value is > 0, there will be 2 roots (and so the parabola will cross the x-axis in 2 points), if its value is =0, there will be only a single root (the the parabola will touch the x-axis in exactly one point), and, finally, if its value is < 0, the quadratic has no real root (andthe parabola will not have any x-intercepts).

So, let's take a look:

$b^2-4ac= (-12)^2-4\cdot 1\cdot12=96$

This means the parabola will intercept the x-axis at 2 points, two real roots.

Since the coefficient of the quadratic term is positive (a=1), the parabola is oriented "open-up." But since we already know the parabola intercepts in two points, the fact that it is open-up implies now that the vertex must lie below the x-axis (otherwise it could not intercept it).

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