Which of the following is true? A Tangent is positive in Quadrant I. B Sine is negative in Quadrant II. C Cosine is positive in Quadrant III. D Sine is positive in Quadrant IV.

Answers

Answer 1
Answer:

Answer:  The correct option is (A) Tangent is positive in Quadrant I.

Step-by-step explanation:  We are given to select the correct statement from the options provided.

The rule of signs for the trigonometric ratios in the four quadrants are as follows :

Quadrant I :    All the three ratios, tangent, sine and cosine are positive.

Quadrant II :   Only sine is positive, cosine and tangent are negative.

Quadrant III :  Only tangent is positive, sine and cosine are negative.

Quadrant IV :  Only cosine is positive, sine and tangent are negative.

Therefore, using the above rules, we can say that the options (B), (C) and (D) are incorrect.

Option (A) is correct because all the ratios are positive in Quadrant I and so is tangent.

Answer 2
Answer: The true statement in that a tangent is positive in quadrant I.

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If you triple 4 and subtract 2 each day, how many days until you have zero

Answers

Triple 4 and subtract 2 each day
Find the number of days to be able to reach zero
1st day = 3(4) – 2
=> 12 - 2
=> 10
2nd day
=> 10 - 2
=> 8
3rd day
=> 8 – 2
=> 6
4th day
=> 6 – 2
=> 4
5th day
=> 4 – 2
=> 2
6th day
=> 2 – 2
=0

In 6th day, you’ll be able to get the amount of zero by subtracting 3(4) by 2.




What is the surface area of this cylinder?Use a * 3.14 and round your answer to the nearest hundredth.
28 ft
-----------
15 ft
square feet
Submit

Answers

the answer is 2550 square feet

If I get a 63 on a test and it takes 20% of my grade, and I have five 100% in the class what would be my grade after the test

Answers

multiply your percentage score on the test by the percentage it is worth of the final grade.

Answer:

92.6 (A-)

Step-by-step explanation:

i used a grade calculator

Which is f(5) for the function –2x2 + 2x – 3?

Answers

Given:
f(5) for the function -2x² + 2x - 3

usually the value enclosed in a parenthesis in a function is the value of x.

f(x) = -2x² + 2x - 3

So if x = 5 ; then, we simply substitute x by its value

f(5) = -2(5²) + 2(5) - 3
f(5) = -2(25) + 10 - 3
f(5) = -50 + 10 - 3
f(5) = 10 - 50 - 3
f(5) = 10 - 53
f(5) = -43

To find f(5) for the function –2x^2 + 2x – 3, substitute 5 in place of x and evaluate the expression. The value of f(5) is -43.

To find f(5) for the function –2x2 + 2x – 3, simply substitute 5 in place of x in the function.

So, f(5) = –2(5)2 + 2(5) – 3.

Calculating further, f(5) = –2(25) + 10 – 3 = –50 + 10 – 3 = –40 – 3 = -43.

Learn more about Evaluating Functions here:

brainly.com/question/18543961

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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend? The choices are: A. 6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8 B. 6d5 – 4c3d2 + 3c2d3 – 4cd4 + 8 C. 6d5 – 4c3d2 + 5c2d3 – 12cd4 + 8 D. 6d5 – 2c3d2 – 3c2d3 – 4cd4 + 8

Answers

Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

x=6d^5-2c^3d^2+5c^2d^3-12cd^4+8

Hence, the correct option is A.

Answer:

6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8

Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a man that is heterozygous for both traits, what is the probability that they will have a child with a widow's peak and attached earlobes?

Answers

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445