Find the solution of this system of equations. Separate the x- and y- values with a comma.X= -8+y
-11x+9y=4

Answers

Answer 1
Answer: \begin{cases}x= -8+y \n -11x+9y=4 \end{cases}\n \n\begin{cases}x= -8+y \n -11 \cdot (-8+y)+9y=4 \end{cases}\n \n\begin{cases}x= -8+y \n 88-11y+9y =4 \end{cases}\n \n\begin{cases}x= -8+y \n -2y=4 -88\end{cases}\n \n

\begin{cases}x= -8+y \n -2y=-84 \ \ / :(-2)\end{cases}\n \n\begin{cases}x= -8+y \n y=(-84)/(-2) \end{cases}\n \n\begin{cases}x= -8+42 \n y=42 \end{cases}\n \n\begin{cases}x= 34 \n y=42 \end{cases}\n \n



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If triangle DEF has a 90° angle at vertex E, which statements are true? Check all that apply.Triangle DEF is an obtuse triangle.
The angle at vertex D is acute.
The angle at vertex F is obtuse.
Triangle DEF is a right triangle.
The angle at vertex D is obtuse.

Answers

draw a diagram (shown below as attachment)

check each option

1st one: obtuse triangle
osbuse means that the triangle has an angle more than 90 degrees
remember that all angles add to 180
90 is one
90+D+F=180
D+F=90
so those 2 mystery angles both have to be less than 90 so therefor none of them can be obtuse
not 1st option


2nd: angle at D is acute
acute means less than 90
so we remember that
D+F=90
no angle can be 0 so let's say F is a very small number like 0.0001
then D would be 89.9999
still less than 90, it is acute
this 2nd optin is right

3rd: angle at F is obtuse
wrong, from 1st one,  no obtuse angles
3rd option is wrong

4th: right triangle
duh, a right triangle has a right angle in it
90 degrees is a right angle
yes
4th optin is right

5th: D is obtuse
naw, fam. no obtuse angles here



the right answers are 2nd and 4th or
The angle at vertex D is acute and
Triangle DEF is a right triangle

Answer:

In other words, A, D.

Step-by-step explanation:

Solve for
a. 7a-2b = 5a+b

Answers

Answer:  The required value of a is(3)/(2)b.

Step-by-step explanation:  We are given to solve the following equation for variable a :

7a-2b=5a+b~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To solve the above equation for a, we need to take terms involving a on one side of equality that that involving b on the other side.

So, from equation (i), we get

7a-2b=5a+b\n\n\Rightarrow 7a-5a=b+2b\n\n\Rightarrow 2a=3b\n\n\Rightarrow a=(3)/(2)b.

Thus, the required value of a is (3)/(2)b.

7a-2b = 5a + b
2a=3b
a = 3b/2

1. Given two parallel lines cut by a transversal, which sets of angles created are congruent?A. alternate interior angles
B. adjacent angles
C. interior angles on the same side of the transversal
D. supplementary angles
2. In the given figure, line p is parallel to line q. Which of the following describes the relationship between angles 8 and 6?
A. complementary angles
B. alternate interior angles
C. corresponding angles
D. vertical angles
3. In the given figure, line p is parallel to line q. Which of the following describes the relationship between angles 3 and 7?
A. complementary angles
B. alternate interior angles
C. corresponding angles
D. vertical angles
4. Which of the following is a characteristic of corresponding angles formed by two parallel lines and a transversal? (1 point)
A. Their measures are equal.
B. They are complementary.
C. Their measures are different.
D. They are supplementary.
5. Which of the following is a characteristic of alternate interior angles formed by two parallel lines and a transversal?
A. Their measures are different.
B. Their are complementary.
C. They are always supplementary.
D. Their measures are equal.

Answers

Answer:

Step-by-step explanation:

D supplementary angles

If Saturn's mass is 5.685 · 10^26 kilograms and Mercury's is 3.302 · 10^23 kilograms Approximate how many times greater Saturn's mass is than Mercury's.?

Answers

do the division
(5.685 * 10^26) / (3.302*10^23)

=  1.722 * 10^3

or 1722 times greater

Jim uses ribbon for bookmarks. Jim has 9 feet of ribbon. He uses 1/3 foot of ribbon to make each bookmark. What is the total number of ribbons Jim can make from 9 feet of ribbon?

Answers

Answer with explanation:

Total Length of Ribbon = 9 feet

Length of Ribbon used to make bookmark =(1)/(3)foot

Total number of ribbons Jim can make from 9 feet of ribbon

   =\frac{\text{Total Length of Ribbon}}{\text{Length of ribbon used to make bookmark}}\n\n=(9)/((1)/(3))\n\n=9 * 3=27

=27 Ribbons              


there is 12 inches in a foot.  1/3 of a foot would be 4 inches

take 9 x 12 (Inches in a foot) = 108 and divide by four

the answer is 27.  so he can get 27 ribbons out of 9 ft. of ribbon

Can someone show me how to factor this? 5k-35

Answers

Sure.
Can you find a number that goes into both terms, 5k and 35 ?
How about 5 ?

(5k - 35) = 5 times (k - 7) .
5k-35=5(k-7)