The volume of a cube is 512 cm3. What would change if the volume of the cube were measured in cubic meters?

Answers

Answer 1

Answer: $1\ m=100\ cm\ \ \ \Rightarrow\ \ 1\ m^3=1,000,000\ cm^3\ \Rightarrow\ \ 1\ cm^3=0.000001\ m^3\n \n512\ cm^3=0.000512\ m^3$

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What's 7% of 24,678?

1) 3 - 7 x 5 + 2 x 4=2) 7 - 2 x 5 + 9 x 3=

3) 2 - 8x + 3x When x = 5

4) 4 - 2x + 5x when x= 4

5) z divided 2 - 4z + 3(z-3) when z =8

Answers

1) -24

2) 24

3) -23

4) 16

5) -8/15

Please give me brainliest answer. I need it to level up!

GEMDAS!

3 - 7 x 5 + 2 x 4

3 - 35 + 2 x 4

3 - 35 + 8

3 - 27

-24

7 - 2 x 5 + 9 x 3

7 - 10 + 9 x 3

7 - 10 + 27

7 + 17

2 - 8x + 3x When x = 5

2 - 8(5) + 3(5)

2 - 40 + 15

2 - 25

-23

4 - 2x + 5x when x= 4

4 - 2(4) + 5(4)

4 - 8 + 20

4 + 12

z ÷ 2 - 4z + 3(z - 3) when z = 8

8 ÷ 2 - 4(8) + 3(8 - 3)

8 ÷ 2 - 32 + 24 - 9

4 - 32 + 24 - 9

4 - 8 - 9

-13

I might've did #5 incorrect.... Really really sorry...

-5⁄2 a + 5 = 25 find a

Answers

Answer:

sub 5 25 - 5 = 20

-5/2a=20

mult 2 by each side to get rid of fraction

-5a=40

divide -5 from 40

a=-8

Answer:

The answer is 8

Step-by-step explanation:

-5/2 x 8= 20 and if you add 5 it is 25.

The ratio of X's to O's is 15 over 6. . Use the image below to determine another ratio for X's to O's:

Answers

you can reduce 15 over 6 to 5 over 2 if that helps

2 movie tickets and 1 popcorn cost $29. 4 movie tickets and 4 popcorns cost $68. And 1 movie ticket cost $12. Using the same information from the infomation above, how much would 3 movie tickets and 5 popcorns cost?A.$52
B.$58
C.$61
D.$67

Answers

Answer:

C - $61

Step-by-step explanation:

I did all the math on my paper tell me if you need evidence

Answer:

Step-by-step explanation:

1 movie ticket= $12

1 popcorn= $5

Write a fraction with a denominator of 4 to represent a distance that is less than 7/12 mile

Answers

So basically it's telling you to find a fraction with a denominator of 4 that is less than 7/12.

There are 2 possible answers, which are 2/4 (6/12) and 1/4 (3/12). Make sure to label 1/4 or 2/4 with mile, or it will probably be wrong.

Please help urgently!!! 2x(squared)+x-3=0 5x(squared)+3x=2
x(squared)-5x=0
5x(squared)= 4x
These are all separate equations, can somebody solve them?!

Answers

[Note: ^2 is squared. i just find it quicker to type out]

2x^2 + x - 3 = 0
First get rid of -3 by adding 3 to both sides.
2x^2 + x = +3
Then get rid of x by subtracting x from both sides
2x^2 = 3 - x
Now square root (√) both sides to get rid of the square (^2). This leaves 2x by itself.
2x = √(3 - x)
Finally, divide both sides by 2 so x can be by itself.
x = √(3 - x)/2

5x^2 + 3x =2
Similar to question the 1st question. Get rid of -3x because its smaller than 5x^2
5x^2 = 2 + 3x
Now get rid of the square by sq rooting both sides
5x = √(2 -3x)
This time you divide both sides by 5
x = √(2 - 3x)/5

x^2 - 5x = 0
+5x to both sides
x^2 = 5x
sq root both sides to remove ^2
x = √(5x)
I think this part is optional since you've already got x by itself, but you could divde both sidee by 5 so its not 5x
x/5 = √x

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