Which of the following sets could be the sides of a right triangle?a. {2,3, sqrt of 13}
b. {2,2,4}
c. (1,2, sqrt of 3 wouldn't it be B because it has all even numbers?

Answers

Answer 1

Answer:

The only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.

The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Therefore, in order for a set of numbers to be the sides of a right triangle, the following equation must hold:

hypotenuse^2 = leg1^2 + leg2^2

Let's check each of the given sets:

(a) {2, 3, √13}

hypotenuse^2 = √13^2 = 13

leg1^2 = 2^2 = 4

leg2^2 = 3^2 = 9

13 ≠ 4 + 9

Therefore, {2, 3, √13} cannot be the sides of a right triangle.

(b) {2, 2, 4}

hypotenuse^2 = 4^2 = 16

leg1^2 = 2^2 = 4

leg2^2 = 2^2 = 4

16 = 4 + 4

Therefore, {2, 2, 4} can be the sides of a right triangle.

hypotenuse^2 = √3^2 = 3

leg1^2 = 1^2 = 1

leg2^2 = 2^2 = 4

3 ≠ 1 + 4

Therefore, {1, 2, √3} cannot be the sides of a right triangle.

Therefore, the only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.

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Answer 2

Answer:

Final answer:

The set of numbers that could be the sides of a right triangle is {2,3, sqrt of 13}.

Explanation:

To determine whether a set of numbers could be the sides of a right triangle, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Let's check each set of numbers:

a. {2,3,√13}

b. {2,2,4}

c. (1,2,√3)

For set a, the sum of the squares of 2 and 3 is 13, which is equal to the square of √13. Therefore, set a could be the sides of a right triangle.

For set b, the sum of the squares of 2 and 2 is 8, which is not equal to the square of 4. Therefore, set b could not be the sides of a right triangle.

For set c, the sum of the squares of 1 and 2 is 5, which is not equal to the square of √3. Therefore, set c could not be the sides of a right triangle.

Therefore, the set of numbers that could be the sides of a right triangle is a. {2,3,√13}.

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Can someone help me please I’ll mark u as brainliest

Answers

Answer:

It is a function because the dots are in a plot, with a similar line between the dots.

Identify the range of the function. A) (2, 8) B) [2, 8] C) (−5, 9) D) [−5, 9]

Answers

Answer:

The answer is "Option A"

Step-by-step explanation:

The domain is the collection of the value, which belongs to the separate variable (horizontal axis). So, to find a region with a graph, it must search for the function, which starts and end. And at all these levels we are searching at x-values.

Its starting point is (2,9) and the ending point is (8,3). Therefore, x= 2 to x=8 is the domain.

A right rectangular prism has base dimensions of 3 inches by 12 inches and a height of 5 inches. An oblique rectangular prism has base dimensions of 4 inches by 9 inches and a height of 5 inches. Are the volumes the same?

Answers

a rectangular right prism area=legnth times width times height or base area times height

base=3 b y12, area=3 times 12=36
height=5
36 times 5=180

an oblique rectangular prism volume is the same as the right rectangular prism formula so
4 times 9 times 5=180

180=180
the volumes are the same

A gallon of latex paint can cover 300 square feet. Felix has a pentagonal room in which all the sides have the same lenth of 10 feet thr room has a 8 foot celings how many gallon containers of paint does he need to buy to paint two coats on each wall

Answers

area of each wall is 10*8 = 80 square feet
there are 5 walls so total wall area is 5*80=400
he needs two coats on each wall so he needs to cover 2*400=800 square feet

so he needs to buy 3 galon containers

The equation of a circle is (x - 3)2 + (y + 2)2 = 25. The point (8, -2) is on the circle.What is the equation of the line that is tangent to the circle at (8, -2)?

Answers

Answer:

The equation of the line that is tangent to the circle at (8, -2) is:

$x=8$

Step-by-step explanation:

We know that the line which is tangent at a point on a circle is perpendicular to the line joining the center of the circle and that point.

Here we are given the equation of a circle as:

$(x-3)^2+(y+2)^2=25$

The center of the circle is at: (3,-2)

( Since, the standard form of a circle with center at (h,k) and radius r is given by:

$(x-h)^2+(y-k)^2=r^2$ )

Also, the equation of a line joining (3.-2) and (8,-2) is given by:

$y-(-2)=(-2-(-2))/(8-3)* (x-3)\n\ni.e.\n\ny+2=(-2+2)/(5)* (x-3)\n\ni.e.\n\ny+2=(0)/(5)* (x-3)\n\ni.e.\ y+2=0\n\ni.e.\ y=-2$

Also, we know that the slope of this line is zero.

Also, we know that if two lines are perpendicular with slope m and m' respectively then,

$m\cdot m'=-1\n\ni.e.\n\nm'=(-1)/(m)$

Hence, we get that the slope of the tangent line is:

$(-1)/(0)$

Also, we know that:

The equation of a line with given slope m' and a passing through point (a,b) is given by:

$y-b=m'(x-a)$

Here (a,b)=(8,-2)

and $m'=(-1)/(0)$

i.e. the equation of the tangent line is:

$y-(-2)=(-1)/(0)(x-8)\n\ni.e.\n\ny+2* 0=-1(x-8)\n\ni.e.\n\n-1* (x-8)=0\n\ni.e.\n\n(x-8)=0\n\ni.e.\n\nx=8$

Hello,

O=(3,-2) is the center of the circle and 5 its radius.

P=(8,-2)
The line OP is parallele to ox axis so then tangent is parallele to oy axis
Its equation is x=8.

The volumes of two similar solids are 1,728 m^3 and 343 m^3. The surface area of the larger solid is 576 m^2. What is the surface area of the smaller solid? a. 196 m^2 b. 76m^2 c. 1,372m^2 d. 392 m^2