MATHEMATICS HIGH SCHOOL

1. What is the shortest distance from a point to a line?A) a perpendicular segment
B) a transversal
C) a parallel segment
D) an arc

Answers

Answer 1
Answer:

Answer:  The correct option is (A) a perpendicular segment.

Step-by-step explanation:  We are given to select the correct option that is the shortest distance from a point to a line.

We know that the shortest distance from a point to a line is equal to the length of the line segment drawn from the point to the line such that it is perpendicular to the line.

So, the shortest distance is a perpendicular line segment drawn from the point to the line.

A point P and its shortest distance PC to the line AB is shown in the attached figure. Definitely, PC will be perpendicular to AB.

Thus, the correct option is (A).
Answer 2
Answer: A would be the shortest distance because your going strait to the line.   

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Two sides of a triangle are 15 mm and 10 mm. The perimeter of the triangle is 35 mm. What's the third side?

Answers

35mm-10mm-15mm=10mm
The third side is therefore 10mm in length

What is the surface area of a rectangular prism with a length of 3 mm, a width of 5 mm, and a height of 8 mm?mm2

Answers

158, because to solve this question we first need to know the formula for finding the surface area of a rectangular prism which is A=2(wl+hl+hw) then you just need to input the numbers like so A=2(5*3+8*3+8*5) then when you simplify this down you get A=2(79) then distribute like so so A=158

Enjoy!=)

I need some help with sequences

Answers

Sequences are based off of the directions, if it is least to greatest it is the smallest number, if you can't figure it out it is the farthest on the left of a number line the the farthest on the tight. If it is greatest to least, it is the biggest number first and the smallest last, if you can't figure that out it is the farthest on the right to the farthest on the left.

1. It is adding 5 each time so the next two are 31,36

2. Same thing 28,33

All you have to do is find the sequence I between them. Hope this helps!

in 2004, 34.2 million accountants e-filed income tax returns. this was 114% of the number who filed in 2003. Find the number of accountants who e-filed income tax returns in 2003

Answers

Answer:

30 million accountabts

Step-by-step explanation:

To get the number of accountant that refilled in 2003, 100/114 X 34.2 = 30
Find one percent by dividing it by 100, then multiply it by 114 and theres your answer. 

Write
45%
as a fraction in simplest form.

Answers

9/20 because you would get it as a decimal first and it would be .45 then put 100 at the end and then reduce and you end up with 9/20 
As a fraction it would be 45/100 and in simplest form it is 9/20

Search results for "A shipment of 18 cars, some weighing 3,000 pounds, and the others weighing 5,000 pounds each. Together the shipment has a total weight of 30 tons. (60,000 lbs). Find the number of each kind of car."

Answers

The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:

 x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)

Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.

x=18-y

Then you have to plug that into the other equation to get:

3000(18-y)+5000y=60000

Simplify and solve for y:

54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3

Now that you know what y equals, you can put it into the equation we solved for x:

x=18-3
x=15

So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.

Answer:

The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:

 x+y=18 (because the problem tells you there were 18 cars in total)

3000x+5000y=60000 (because that is the total weight in the problem)

Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.

x=18-y

Then you have to plug that into the other equation to get:

3000(18-y)+5000y=60000

Simplify and solve for y:

54000-3000y+5000y=60000

54000+2000y=60000

2000y=6000

y=3

Now that you know what y equals, you can put it into the equation we solved for x:

x=18-3

x=15

So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.

Step-by-step explanation:
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