MATHEMATICS HIGH SCHOOL

Find the area of a circle circumscribed about an equilateral triangle whose side is 18 inches long.a. 81
b. 108
c. 243

Answers

Answer 1
Answer: The\ area\ of\ a\ circle:A_O=\pi r^2\ \ \ \ /r-a\ radius/\nThe\ length\ of\ a\ radius\ of\ a circle\ circumscribed\ about\ an\nequilateral\ triangle:r=(a\sqrt3)/(3)\ \ \ /a-a\ lenght\ of\ a\ side\ the\ triangle\n-------------------------------\nr=(18\sqrt3)/(3)=6\sqrt3\ (in)\n\nA_O=\pi\cdot\left(6\sqrt3\right)^2=\pi\cdot6^2\cdot\left(\sqrt3\right)^2=\pi\cdot36\cdot3=108\pi\ (in^2)\n\n\pi\approx3.14\n\ntherefore\n\nA_O\approx108\cdot3.14=339.12\ (in^2).....
Answer 2
Answer: See attached for work.
s=18\rightarrow r=6\sqrt3\rightarrow A_\odot=\pi(6\sqrt3)^2=\boxed{108\pi\ in^2}

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What are the domain and range of the relation {(–5, 5), (–3, 2), (0, 3), (3, 2)}?

Answers

domain is th set of number you input
range is the set of number you get from inputing the domain
normally domain is x and range is y
(x,y)

domain is all 1st number
range is all 2nd numbers

doman={-5,-3,0,3}
range={5,2,3} (if it repeats, don't list)

The two angles of a triangle are 78 ° and 82°. So what is the measure of the remaining third angle? a. 160° b. 20° c. 360° d. 180°​

Answers

Answer:

B. :))

Step-by-step explanation:

Triangles = 180°

78 + 82 + x = 180

160 + x = 180

x = 20

B.

During his tennis career in singles play, John won 3 fewer tournament A titles than tournament B titles, and 2 more tournament C titles than tournament B titles. If he won 17 of these titles total, how many times did he win each one? How many A titles
How many B titles
How many C titles

Answers

A = B - 3
C = B + 2
B = B

(B-3) + (B+ 2) + B = 17
3B - 1 = 17
B = (17+1)/3 =6
A = B-3 =6-3=3
C=B +2=6+2=8

Answer :
3 A titles
6 B titles
8 C titles

a carpenter buys $54.38 worth of parts from the supplier. If he pays for the parts with a $100 bill, how much change will he recieve?

Answers

100 - 54.38 = $45.62 change.
the man would receive 45.62$ back in change 

Suppose S and T are mutually exclusive events, P(S) = 5%, and P(T) = 11%. Find P(S or T).

Answers

P(S or T) for mutually exclusive events = P(S) + P(T).

Then P(S or T) = 5% + 11% = 16%.

The vertices of a right triangle are (6, 2), (–2, –4), and (–2, y). What is the value of y?



A.
–4


B.
–2


C.
2


D.
4

Answers

The answer should be C. 2
:P hope this helps you
The value of y is C. 2.

(6, 2), (-2, -4), (-2, 2)
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