Josh believes the Spanish club students at his school have an unfair advantage in being assigned to the Spanish class they request. He asked 500 students at his school the following questions: "Are you in the Spanish club?" and "Did you get the Spanish class you requested?" The results are shown in the table below.
                                                   Spanish Club         Not in Spanish      ClubTotal
Received Spanish class requested 265                              100               365
Did not get Spanish class requested 70                               65                  135
Total                                                 335                              165                  500

Help Josh determine if all students at his school have an equal opportunity to get the Spanish class they requested. Show your work and explain your process for determining the fairness of the class assignment process.

Answers

Answer 1

Answer: 1. Josh requested for a Spanish club then asked his students how many got the Spanish class and how many did not.
So he asked 500 students for the questions:
The result was
=> got the Spanish class = 265 100 365
=> did not = 70 65 135
=> The total was 335 165 500
Thus, this show that only 335 students were able to get the Spanish class they requested and there are still 165 students do not received any Spanish class.
Thus, this is not fair to the other students.

Answer 2

Answer:

Answer:

We have the given the data of 500 students and it is required to see whether every student got an equal opportunity to get the Spanish class they requested.

Now, we have,

Number of students in the Spanish class who got the class they requested = 265

Number of students not in the Spanish class that got the class they requested = 100

Total number of students in Spanish class = 335

Total number of students not in Spanish class = 165

Therefore, we get that,

Probability of students in the Spanish class who got the class they requested = $(265)/(335)$ = 0.791

Probability of students not in the Spanish class who got the class they requested = $(100)/(165)$ = 0.606

This shows that all students do not get the equal chance of getting into the Spanish class they requested.

Related Questions

A student is trying to solve the set of two equations given below:Equation A: x + z = 6 Equation B: 2x + 4z = 1 Which of the following is a possible step used in eliminating the z-term? Multiply equation B by 4. Multiply equation A by 2. Multiply equation A by −4. Multiply equation B by 2.
When do decimal points move
Which of the following Platonic solids is also a pyramid? A. tetrahedron B. Hexahedron C. octahedron D. Icosahedron E. dodecahedron F. None of These
XZ=15 and the perimeter of XWZ is 50. what is the length of WZ?
All rectangles are _____.Multiple Chocieparallelograms rhombuses squares quadrilaterals

What does the remainder theorem conclude given that f(x)x+5 has a remainder of 17? Enter your answer by filling in the boxes.

Answers

The remainder theorem is an easy way of calculating the remainder from polynomial division.

The conclusion of remainder theorem, here is that: $f(-5) = 17$

We have:

$(f(x))/(x + 5)$ and a remainder of 17

The general rule of the remainder theorem is that:

For $(f(x))/(x + a)$ and a remainder of b

It means:

$f(-a) = b$

By comparing

$(f(x))/(x + a)$ and $(f(x))/(x + 5)$

It means:

$a = 5$ and $b = 17$

So:

$f(-a) = b$ becomes

$f(-5) = 17$

Hence, the conclusion is that:

$f(-5) = 17$

Read more about remainder theorems at:

brainly.com/question/13416073

Answer:

f(-5)=17

Step-by-step explanation:

Took the quiz.

A pizzeria makes brick-oven pizzas that are shaped like long rectangles with semi-circles at two ends. The pizzas come in three different sizes, which are measured by the longer side of each rectangle: 14 inches, 18 inches, and 29 inches. All of the pizzas are 10 inches wide, so the semi-circles at the ends have diameters of 10 inches, too. What is the area of each pizza? Use 3.14 for ? , and round your answers to the nearest tenth if necessary.

Answers

Answer:

Area of pizza whose longer side is of length is 14 inches = 218.5 $inches^(2)$

Area of pizza whose longer side of rectangle is 18 inches=258.5 $inches^(2)$

Area of pizza whose longer side is of length is 29 inches = 368.5 $inches^(2)$

Step-by-step explanation:

Given A pizzeria makes brick-oven pizzas that are shaped like long rectangles with semi-circles at two ends. The pizzas come in three different sizes, which are measured by the longer side of each rectangle: 14 inches, 18 inches, and 29 inches. All of the pizzas are 10 inches wide, so the semi-circles at the ends have diameters of 10 inches. we have to find the area of each pizza.

First, let us find the area of pizza whose longer side of rectangle is 14 inches

Area of 2 semicircles whose diameter is 10 inches

$=2((1)/(2)\pi r^(2))=\pi r^(2)=3.14* 5 * 5 = 78.5 inches^(2)$

Length = 14 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $14* 10=140 inches^(2)$

∴ Area of pizza whose longer side is of length is 14 inches = Area of rectangle + area of 2 semicircles

=140+78.5=218.5 $inches^(2)$

Now, let us find the area of pizza whose longer side of rectangle is 18 inches

Length = 18 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $18* 10=180 inches^(2)$

∴ Area of pizza whose longer side is of length is 18 inches = Area of rectangle + area of 2 semicircles

=180+78.5=258.5 $inches^(2)$

Now, let us find the area of pizza whose longer side of rectangle is 29 inches

Length =29 inches

Breadth = 10 inches

Area of rectangle = $length * breadth$

= $29* 10=290 inches^(2)$

∴ Area of pizza whose longer side is of length is 29 inches = Area of rectangle + area of 2 semicircles

=290+78.5=368.5 $inches^(2)$

Final answer:

To calculate the area of pizzas shaped like rectangles with semi-circular ends, we calculate the area of the rectangle and adjacent semi-circles separately then sum both. The rectangle's area is calculated as length times width while the semi-circle area is calculated as half of (pi*radius^2).

Explanation:

The area of a pizza that's shaped like a long rectangle with semi-circles at the ends can be calculated by first looking at the rectangle and then the semi-circles. For the rectangles, we use the formula for the area of a rectangle that is, length multiplied by width.

For the 14 inch pizza, the rectangle part:
Area = Length x Width = 14 x 10 = 140 square inches

The area of the semi-circle can be calculated as Area=1/2πr². The diameter is given as 10. So, the radius (r) will be half of the diameter, which is 5. Therefore, Area of each semi-circle = 1/2 x π x 5² = 1/2 x 3.14 x 25 = 39.25 square inches. The combined area of two such semi-circles will be = 39.25 x 2 = 78.5 square inches.

Adding the area for the rectangle and the semi-circles, the total area of each pizza will be 140 + 78.5 = 218.5 square inches.

Following these same steps, we can calculate the areas for the 18 inch and 29 inch pizzas.

Learn more about Area of a pizza here:

brainly.com/question/1329248

#SPJ3

Identify the solutions of the system of equations, if any
x+5y=6
6x-10y=12

Answers

$\left \{ {{x+5y=6} \ \ |2\atop {6x-10y=12}} \right. \n\n\n \left \{ {{2x+10y=12} \atop {6x-10y=12}} \right. \n ======== \n\n 8x=24 \ \ \ |:8 \n\n \boxed{x=3} \n\n x+5y=6 \n\n 5y=6-x \n\n y=(6-x)/(5) \n\n y=(6-3)/(5) \n\n \boxed{y=(3)/(5)}$

so assuming x and y remain constant, we can make one of the place holders negative and add the equations together to cancel each other out so

we can cancel out the y terms since 5 is close to 10
(x+5y=6) times 2=2x+10y=12
add this to 6x-10y=12
2x+6x+10y-10y=12+12
8x=24
divide both sides by 8
x=3
subsitute into first equation
x+5y=6
3+5y=6
5y=3
y=3/5
x=3

How do I expand
r(r-r2) the 2 is meant to be r squared