A sample of CO2(s) and a sample of CO2(g) differ in their1) chemical compositions
2) empirical formulas
3) molecular structures
4) physical properties

Answers

Answer 1

Answer: The correct answer is D.
CO2(s) is a solid.
CO2(g) means it is gas.

So they differ in their physical properties.
Physical propertiers means that they differ in their look.

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How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mass solution? Show all of the work needed to solve this problem.

Answers

M1m1 = M2m2

where M1 is the concentration of the stock solution, m1 is the mass of the stock solution, M2 is the concentration of the new solution and m2 is its new mass.

M1m1 = M2m2

.925(m1) = .35(250)

m1 = 94.59 g

Answer: 94.59 grams of 92.5 % $H_2SO_4$ by mass solution will be needed.

Explanation:

Mass of sulfuric acid is 250 grams of 35 % by mass solution:

$35=(x)/(250 g)* 100$

$x=87.5 g$

Mass of $H_2SO_4$ in 250 g of 35 % solution = 87.5 g

Mass of 92.5 % $H_2SO_4$ needed to make 35 % by mass solution.

$92.5=\frac{87.5 g}{\text{mass of the solution required}}* 100$

Mass of the solution required = 94.59 g

94.59 grams of 92.5 % $H_2SO_4$ by mass solution will be needed.

The superheated water vapor is at 15 MPa and 350°C. The gas constant, the critical pressure, and the critical temperature of water are R = 0.4615 kPa·m3/kg·K, Tcr = 647.1 K, and Pcr = 22.06 MPa. Determine the specific volume of superheated water based on the ideal-gas equation. (You must provide an answer before moving to the next part)

Answers

Answer:

0.01917 m^3/kg.

Explanation:

Given:

P = 15 MPa

= 1.5 × 10^4 kPa

T = 350 °C

= 350 + 273

= 623 K

Molar mass of water, m = (2 × 1) + 16

= 18 g/mol

= 0.018 kg/mol

R = 0.4615 kPa·m3/kg·K

Using ideal gas equation,

P × V = n × R × T

But n = mass/molar mass

V = (R × T)/P

V/M = (R × T)/P × m

= (0.4615 × 623)/1.5 × 10^4

= 0.01917 m^3/kg.

Final answer:

The specific volume of superheated water vapor under the conditions of 15 MPa pressure and 350°C temperature, using the ideal gas equation, is approximately 0.01919 cubic meter per kilogram.

Explanation:

The question is asking to calculate the specific volume of superheated water vapor using the ideal gas equation P = ρRT, where P is the pressure, ρ is the density (inverse of specific volume), R is the gas constant, and T is the temperature.

To find the specific volume (v), we need to rearrange the ideal gas equation to v = RT/P. Given that the pressure P = 15 MPa = 15000 kPa, the gas constant R = 0.4615 kPa.m³/kg.K, and the temperature T = 350°C = 623.15 K (adding 273 to convert °C to K), we can substitute these values into our rearranged equation balance to calculate for v.

The specific volume v = (0.4615 kPa.m³/kg.K * 623.15 K) / 15000 kPa = 0.01919 m³/kg. So, the specific volume of superheated water vapor under the given conditions is approximately 0.01919 cubic meter per kilogram.

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Thermal expansion or thermal contraction would be most noticeable in which of the following?A. Hot car seat
B. Concrete in a sidewalk
C. Air inside a balloon
D. Liquid in a drink

Answers

The answer is C. Air inside a balloon. This is because gases are much more affected by thermal expansion and contraction compared to liquids and solids. The reason behind this is that gas molecules are very loosely packed, so even the slightest changes in temperature have a big effect on its pressure and volume. If the air inside a balloon has a temperature rise, the tendency is for the balloon to expand and potentially explode.

Liquids are also affected by thermal expansion or contraction, but not as much as gases. Solids tend to maintain their shape under thermal expansion or contraction.

Is it possible for an object not to be in motion and still have force acting upon it?

Answers

yes,this is an example:
An apple is sitting on a desk he is not in motion but one of the forces acting upon it is gravitational pull because is not floating around, the earth gravitational pull is pulling it down to the earth's surface.

How do you find the IUPAC name for a compound like ZnO

Answers

To find the IUPAC name for compounds, you must memorize prefixes and suffixes and other terms in determining or naming a compound. The IUPAC name for compound ZnO is Oxozinc or Zinc Oxide. I hope this helps you on your assignment.

What is an isotope? Give an example of an element with isotopes.

Answers

Answer:

isotope. An isotope of a chemical element is an atom that has a different number of neutrons (that is, a greater or lesser atomic mass) than the standard for that element. The atomic number is the number of protons in an atom's nucleus.

Isotope Examples

Carbon 12 and Carbon 14 are both isotopes of carbon, one with 6 neutrons and one with 8 neutrons (both with 6 protons). Carbon-12 is a stable isotope, while carbon-14 is a radioactive isotope (radioisotope). Uranium-235 and uranium-238 occur naturally in the Earth's crust.

Answer: