Identify the elements and the number of atoms of each element in BO2

Answers

Answer 1

Answer: The B stands for Boron which is 5 on the periodic table.
The O stands for Oxygen which is 8 on the periodic table.

There is 1 Boron, It's only 1 because there is only on B which doesn't have coefficent
There is 2 Oxygen, The 2 is from the 2 next to the O

Answer 2

Answer:

A fundamental object that is difficult to divide into smaller bits is known as an element. An element is a substance that cannot be broken down by non-nuclear reactions in chemistry and physics. The elements are boron and oxygen, and their numbers are 1 and 2.

A pure material known as an element is made up of just one type of atom and cannot be divided into two or more different substances. A compound is a pure substance that is created when two or more substances are mixed in a specific mass ratio.

Chemistry's fundamental building block is an atom. It is the smallest fraction of matter into which electrically charged particles cannot be released. It is also the smallest piece of substance with chemical element-like characteristics.

To know more about elements, visit;

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What is 0.001012, 123, & 1.52 in scientific notation
Ca(OH)2 is added to a large beaker of water. How is the solution different from the original water?A...The solution turns blue litmus to red. B...The solution turns phenolphthalein pink. C...The solution has more hydrogen ions. D....The solution has fewer hydroxide ions.
Subatomic particle that has mass nearly equal to that of a proton, but carries no electrical charge
Need to lose one electron to form a stable octetb. alkali metals c. alkaline earth metals d. noble gases e. lanthanides
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A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.This emitted energy can be used to determine theA) mass of the sample
B) volume of the sample
C) identity of the element
D) number of moles of the element

Answers

The answer is C. The specific amount of energy emitted when electrons jump from excited states to the ground state refers to emission spectrum. The energy is emitted in the form of photons, and the photons have very specific wavelengths (energy) that correspond to the energy gaps between the excited states and the ground state. The specific wavelengths of light emitted are referred to as the "emission spectrum," and each element produces a different emission spectrum. Thus, this emitted energy can be used to identify the element from which your sample was taken.

Answer:

Explanation:

What is the scale factor used to create a model of an animal from the actual animal? 1) 1:10 2) 1:20 3) 1:30 4) 1:40

Answers

The scale factor used to create a model of an animal from the actual animal depends on the size and details required for the model. However, among the options provided, the most commonly used scale factor for creating detailed animal models is 1:40.

What other forms of radiation may come from the stars?

Answers

Other forms of radiation may come from the stars. These radiations include x-ray radiation, ultraviolet radiation, electromagnetic radiation, infrared radiation, alpha ray, beta ray & gamma ray, visible light radiation, radio frequencies radiation and magnet waves.

Find the empirical formula of a compound which contains 54.93% potassium, 38.73% boron and 6.34% hydrogen.A.
KBH
B.
KB2H4
C.
KB3H9
D.
K2B5H9

Answers

Use the percent as mass in g
Mass g) --> g/mol
K, B and H molar mass from periodic table

54.93 g K x (1 mol K/ 39.10 g K) = 1.405 mol K
38.73 g B x (1 mol B/ 10.81 g B) = 3.583 mol B
6.34 g H x (1 mol H/ 1.008 g H) = 6.290 mol H

Divide all three answers by the smallest value and you will get
1.000 mol K
2.550 mol B
4.477 mol H
now multiply these three answers by a number that will make all a whole number or (a number with a 9 as the first decimal point)
so multiply by 2
2 mol k
5 mol B
and 9 mol H
E.F. = K2B5H9
Answer is D
Sorry for bad explanation!!!!!!

Hello!

Find the empirical formula of a compound which contains 54.93% potassium, 38.73% boron and 6.34% hydrogen.

A. KBH

B. KB2H4

C. KB3H9

D. K2B5H9

We have the following data:

Potassium (K) ≈ 39 a.m.u (g/mol)

Boron (B) ≈ 11 a.m.u (g/mol)

Hydrogen (H) ≈ 1 a.m.u (g/mol)

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)

K: 54.93 % = 54.93 g

B: 38.73 % = 38.73 g

H: 6.34 % = 6.34 g

The values (in g) will be converted into quantity of substance (number of mols), dividing by molecular weight (g / mol) each of the values, we will see:

$K: (54.93\:\diagup\!\!\!\!\!g)/(39\:\diagup\!\!\!\!\!g/mol) \approx 1.408\:mol$

$B: (38.73\:\diagup\!\!\!\!\!g)/(11\:\diagup\!\!\!\!\!g/mol) \approx 3.521\:mol$

$H: (6.34\:\diagup\!\!\!\!\!g)/(1\:\diagup\!\!\!\!\!g/mol) = 6.34\:mol$

We realize that the values found above are not integers, so we divide these values by the smallest of them, so that the proportion does not change, let us see:

$K: (1.408)/(1.408)\to\:\:\boxed{K = 1}$

$B: (3.521)/(1.408)\to\:\:\boxed{B \approx 2.5}$

$H: (6.34)/(1.408)\to\:\:\boxed{H \approx 4.5}$

convert number of atomic radio into whole number

2 * (1 : 2.5 : 4.5)

= 2 : 5 : 9 ← whole number of atomic radio

K = 2

B = 5

H = 9

Thus, the minimum or empirical formula found for the compound will be:

$\boxed{\boxed{K_2B_5H_9}}\Longleftarrow(Empirical\:Formula)\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

D. K2B5H9

________________________

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What type of chemical reaction is happening here? 8Fe + S8 --> 8FeS

Answers

This is a synthesis reaction since you are taking two elements and creating one (opposite of decomposition). I think this might also classify as a redox reaction as well since it appears as if iron is being oxidized and sulfur is being reduced (iron is loosing electrons while sulfur is gaining electrons).

I hope this helps. Let me know if anything is unclear.

Consider the following reversible, exothermic chemical reaction: 2C2H2(g) + 5O2(g) ↔4CO2(g) + 2H2O(g) All BUT one of the conditions will cause equilibrium to shift right and produce more of the products. Which change will cause the reaction to shift to the left?
A) adding oxygen
B) adding CO2
C) increasing the pressure
D) decreasing the temperature

Answers

Answer : The correct option is, (B) adding $CO_2$

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Option A : adding oxygen

If the concentration of $O_2$ is increased on reactant side then the equilibrium will shift in the direction where decrease of concentration of $O_2$ takes place. Therefore, the equilibrium will shift in the right direction.

Option B : adding $CO_2$

If the concentration of $CO_2$ is increased on product side then the equilibrium will shift in the direction where decrease of concentration of $CO_2$ takes place. Therefore, the equilibrium will shift in the left direction.

Option C : increasing the pressure

If the pressure of the container is increased then the equilibrium will shift in the direction where the less number of moles of gas molecules is taking place. As the number of moles of gas molecules is greater at the product reactant side and less at product side. So, the equilibrium will shift in the right direction.

Option D : decreasing the temperature

As the given reaction is an exothermic reaction in which the heat is released during a chemical reaction. That means the temperature is decreased on the reactant side. If the temperature is decreased in the equilibrium then the equilibrium will shift in the direction where, temperature is getting increased. Thus, the reaction will shift to the right direction i.e, towards the product.

Adding CO2 increases Q and makes Q > K (K being the equilibrium constant for this reaction). As a result, the reaction will favor reactants until Q=K, so adding CO2 causes the reaction to proceed to the left. B is the correct answer.

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