Find the length of Line ED Round to the nearest hundredth.A.
7.32 m
B.
9.48 m
C.
9.56 m
D.
33.80 m
Find the length of Line ED Round to the nearest - 1

Answers

Answer 1
Answer:

Answer:

The correct option is C. 9.56 meter

Step-by-step explanation:

∠D = 54° , ∠F = 32°

Now, Using angles sum property of a triangle

∠D + ∠F + ∠E = 180°

⇒ 54° + 32° + ∠E = 180°

⇒ ∠E = 180 - 86

⇒ ∠E = 94°

Now, Using sine rule in the triangle DEF

(FD)/(\sin 94)=(ED)/(\sin 32)\n\n\implies (18)/(\sin 94)=(ED)/(\sin 32)\n\n\implies ED = (18 * \sin 32)/(\sin 94)\approx 9.56\text{ meter}

Hence, The correct option is C. 9.56 meter

Answer 2
Answer: The angles in a triangle add up to 180°.
m \angle D + m \angle E + m \angle F=180^\circ \n54^\circ + m \angle E + 32^\circ = 180^\circ \nm \angle E=180^\circ - 54^\circ - 32^\circ \nm \angle E=94^\circ

According to the law of sines, the ratio of the length of a side of atriangle to the sine of the angle opposite to this side is the same for all sides.
So, the ratio of DF to sin m∠E is the same as the ratio of ED to sin m∠F.
(18)/(\sin 94^\circ)=(x)/(\sin 32^\circ) \n \n(18)/(\sin 94^\circ) * \sin 32^\circ= x \n \n(18)/(0.9976) * 0.5299 \approx x \n \nx \approx 9.56

The answer is C.

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Answers

First, we have write down, in the language of mathematics that M is the midpoint of AB. This means that AB will have two parts, each of them ending with (or beginning with) M. This is how we do it: 

c) AB=AM+MB


The correct answer is AM+AM=AB I know what test this is.

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Answers

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A &B share the cost in a ratio of 3:2 A pays £125 how much dose B pay

Answers

Hi There! :)

A &B share the cost in a ratio of 3:2 A pays £125 how much dose B pay

Let the common multiple be x 
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How might you prove your observations in Question 2 using algebra and x and y-coordinates? Briefly outline an approach using what you know about a midpoint and the slope of a line.

Answers

Answer:

I can use variables to represent the coordinates of the vertices for a general triangle, ∆ABC. Then I can calculate the midpoints of the sides in terms of those variables. Using the point-slope formula for the equation of a straight line, I can build the symbolic equations for the three medians, AE, BF, and CD. I can solve for the point of intersection for two of the medians, AE and BF, for example. Finally, I can prove the lines (i.e., medians) concurrent if the point I found also satisfies the equation of the line for CD.

Step-by-step explanation:

Here is the answer from Plato! Hope this helps :)

Answer:

I can use variables to represent the coordinates of the vertices for a general triangle, ∆ABC. Then I can calculate the midpoints of the sides in terms of those variables. Using the point-slope formula for the equation of a straight line, I can build the symbolic equations for the three medians, AE, BF, and CD. I can solve for the point of intersection for two of the medians, AE and BF, for example. Finally, I can prove the lines (i.e., medians) concurrent if the point I found also satisfies the equation of the line for CD.

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Answers

Answer:

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Step-by-step explanation:

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Answers

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The answer to your question would be true since the permutations would deal with how many different ways the medals could possibly be distributed.