Calculate the number of moles 3.16 g of KMnO4 32.33 g of K2CrO4 100 g of KHCO3

Answers

Answer 1

Answer: The number of moles:
3.16g of $KMnO_(4)$
1 mole of $KMnO_(4)$ - 158g.
x moles of $KMnO_(4)$ - 3.16g.
$x=(1\ mole*3.16g)/(158g)=(3.16)/(158)=0.02\ mole$

The number of moles:
32.33g of $K_(2)CrO_(4)$
1 mole of $K_(2)CrO_(4)$ - 194g.
x moles of $K_(2)CrO_(4)$ - 32.33g.
$x=(1\ mole*32.33g)/(194g)=(32.33)/(194)=0.17\ mole$

The number of moles:
100g of $KHCO_(3)$
1 mole of $KHCO_(3)$ - 100.1g.
x moles of $KHCO_(3)$ - 100g.
$x=(1\ mole*100g)/(100.1g)=(100)/(100.1)=0.999\ mole$

Greetings,
n00nst00p :)

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Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and the density of the gas is 0.710 g/cm3, how many kilograms of fuel are contained in one canister?

Answers

The number of kilograms of fuel that are contained in one canister is 1.03 Kilograms

calculation

mass = density x volume

Density= 0.710 g/cm³

volume = 1.45 L

convert 1.45 l into cm³ to make the units uniform

that is 1 L= 1000 cm³

1.45 L= cm³

by cross multiplication

= (1.45 L x 1000 cm³) / 1 L = 1450 cm³

mass is therefore = 0.710g/cm³ x 1450 cm³ =1029.5 grams

convert grams to Kg

1 kg = 1000 grams

? kg =1029.5 grams

by cross multiplication

= (1 kg x 1029.5 grams) /1000 grams = 1.0295 Kg ≅1.03 kg

the canister contains a gas used to fuel a burner

the volume of the white gas to be used is - 1.45 L

density of white gas is 0.710 g/cm³

density is defined as the mass per unit volume

the mass of 1 cm³ of white gas is - 0.710 g

1 cm³ is equivalent to 0.001 L

the volume given is in Litres

so if 0.001 L has a mass of 0.710 g

then 1.45 L have a mass of - 0.710 g / 0.001 L x 1.45 L = 1030 g

since 1000 g is equivalent to 1 kg

mass of white fuel is - 1030 g/1000 g/kg = 1.03 kg

theres 1.03 kg of fuel in one canister

Which celestial object is found in the Kuiper Belt?

Answers

Beyond the planet Neptune is found a region filled with icy bodies. This region is known as the Kuiper Belt. This holds trillions of objects which is said to be remnants of the early solar system. The region contains comets and dwarf planets.

The smallest particle of an element that retains the chemical identity of that element is a/an A. atom.
B. compound.
C. molecule.
D. mixture.

Answers

The answer is A. atom. An atom has nucleus and electrons and its own characteristics. While compound and molecule are consists of different atoms. And mixture is consists of different compounds.

A. ATOM is the correc answer

Amines, amides, and amino acids are organic compounds containing the element:

Answers

they all contain the same element

They contain Carbon, Nitrogen, Hydrogen, Oxygen, and Sulfur

Which of these factors are experienced by a space shuttle in orbit? Check all that apply. A. gravity
B. air resistance
C. friction
D. inertia
E. centripetal force

Answers

Answer:

Gravity, inertia, centripetal force

Explanation:

Gravity: A space shuttle in orbit experiences gravity not just from the planet it is orbiting but from other celestial bodies too

Air resistance: There is no atmosphere in space so the shuttle experiences no air resistance

Friction: There is no atmosphere or surface that it is moving on so the shuttle experiences no friction

Inertia: Any body that is moving or stationary experiences inertia, the resistance to change in velocity whether it is moving or stationary

Centripetal force: The shuttle is in orbit, what keeps it in orbit is the centripetal force towards the center of the body it is orbiting

A. gravity (of any planet/star/celestial body around )

D. Inertia

E. Centripetal force

Calculate the mass of copper if 2653.8 J of copper is cooled from 155 oC to 23 oC. The specific heat of copper is 0.385 J/g*oC.

Answers

Answer:

The answer to your question is m = 52.22 g

Explanation:

Data

mass of Cu = ?

Energy = 2653.8 J

temperature 1 = 155°C

temperature 2 = 23°C

Specific heat = 0.385 J/g°C

To calculate the mass of Copper, use the formula of specific heat and solve it for mass.

Formula

Q = mC(Temperature 2 - Temperature 1)

Solve for m

m = Q / C (Temperature 2 - Temperature 1)

Substitution

m = 2653.8 / 0.385(23 - 155)

Simplification

m = 2653.8 / 0.385(132)

m = 2653.8 / 50.82

Result

m = 52.22 g

Answer:

The mass of the copper is 53.22 grams

Explanation:

Step 1: Data given

Energy = 2653.8 J

Initial temperature = 155 °C

Final temperature = 23°C

Specific heat of copper = 0.385 J/ g°C

Step 2: Calculate mass of copper

Q = m*c*ΔT

⇒ with Q = the energy = 2653.8 J

⇒ with m = the mass of copper = TO BE DETERMINED

⇒ with c= The specific heat of copper = 0.385 J/g°C

⇒ΔT = The difference in temperature = T2 - T1 = 23 - 155 = -132°C

2653.8 J = m * 0.385 J/g°C * 132 °C

m = 2653.8 / (0.385*132)

mass of copper = 52.22 grams

The mass of the copper is 53.22 grams

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