Which of the following is a correct equilibrium expression?
A.
`"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`
B.
`"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`
C.
`"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`
D.
`"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`
Answer:
Answer is option D
Explanation:
The explanation is embedded in the word document attached
Answer:
Keq= [KOH]^4 [O2]^3/[[KO2]^4
Explanation:
4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)
Looking at the equation, the correct equilibrium expression is shown in the answer. The equilibrium constant for a reaction is given by the active masses of species involved in the reaction. The relative molar coefficients of species are raised to the power of their molar concentrations to give the active mass of each specie. This active mass now goes into the equilibrium equation.
Water is not included in the equilibrium equation because, as a solvent, it is present in large excess.
Metal is most likely to be correct
Answer:
The sand has a higher specific heat
Explanation:
The answer is that the sand would have a higher specific heat than water because water requires a lot of heat to raise its temperature while sand needs less heat to change it as water has a high heat capacity that allows it to maintain its temperature within a range.