Solve allgebraically for x: log base 27 (2x-1)=4/3

Answers

Answer 1

Answer: $log_(27)(2x-1)=(4)/(3);\ \ \ \ D:2x-1 > 0\to x > (1)/(2)\n\nlog_(27)(2x-1)=log_(27)27^(4)/(3)\iff 2x-1=27^(4)/(3)\n\n2x-1=\left(\sqrt[3]{27}\right)^4\n\n2x-1=3^4\n\n2x-1=81\ \ \ /+1\n\n2x=82\ \ \ \ /:2\n\nx=41\in D$

Related Questions

Guy decides to get in shape by running. The first day, he runs 1 mile in 12 minutes. Two months later he has decreased his mile time by 25%. What is his mile time now?
Consider two events such that P(A) = 1/3, P(B) = 4/5, and P(A ∩ B) = 4/15. Are events A and B independent events?Yes, they are independent because P(A) ⋅ P(B) ≠ P(A ∩ B) No, they are dependent because P(A) ⋅ P(B) = P(A ∩ B) Yes, they are independent because P(A) ⋅ P(B) = P(A ∩ B) No, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)
If you buy three pairs of j and for $35.95 each and get a fourth pair for free. What is your cost per pair of jeans
During cooking chicken loses 10% of its weight due to water loss. in order to obtain 1170 grams of cooked chicken,how many grams of uncooked chicken must be used.?
Record 3 2/25 as a decimal. Please help!!!!!

The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

Answers

Area of Circle= $\pi$ $r^(2)$
= $(22)/(7)$ x $( (25cm)/(2)) ^(2)$
= 490.87 $cm^(2)$

Area of Oven tray= 60cm x 50cm
= 3000 $cm^(2)$

: . # tin that can hold on bake tray= 3000 $cm^(2)$ / 490.87 $cm^(2)$ = 6.11
Thus making it logically 6.....

A cylindrical water bottle with a height of 20 cm and diameter of 5.5 cm is filled with water until it is full. Vincent wants to transfer the water in the bottle into a cubic container. State the minimum length of a side of the cube. Can anyone help to explain this question for me?

Answers

Step-by-step explanation:

the volume of a cylinder is

ground area × height

the ground area is a circle, and the area of a circle is

pi×r²

with r being the radius, which is always half of the diameter.

so, in our case

r = 5.5/2 = 2.75 cm

height = 20 cm

so, the volume of the cylinder is

pi×2.75² × 20 = pi×7.5625×20 = 475.1658889... cm³

the volume of a cube is

(side length)³

and the side length of a cube is therefore the cubic root of the volume.

now the volume of the cube has to be at least a large as the volume of the cylinder to be able to contain all the water from the cylinder.

so, the side length has to be at least the cubic root of that volume (475.1658889... cm³).

which is 7.803361957... cm.

PLEASE HELP Use the squared identities to simplify 2cos2x cos2x.

Answers

The correct option is option D as 2cos²(x)cos²(x) simplifies as follows:

2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4

Simplification:

The given expression is : 2cos²(x)cos²(x)

The square identity for cosine is given by:

2cos²(x) -1 = cos(2x)

Thus,

2cos²(x) = {cos(2x) +1}

simplifying again,

cos²(x) = {cos(2x) +1}/2

Simplifying the above using squared identities:

2cos²(x)cos²(x) = {cos(2x) +1}cos²x

= {cos(2x) +1} {{cos(2x) +1}/2}

$= \frac{\{cos(2x) +1\}^2}{2}\n\n=(cos^2(2x)+2cos(2x)+1)/(2)\n\n=((cos(4x)+1)/(2)+2cos(2x)+1)/(2)\n\n=(3+4cos(2x)+cos(4x))/(4)$

so,

2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4

Hence option D is correct.

Learn more about squared identities:

brainly.com/question/14613683?referrer=searchResults

Answer:

Step-by-step explanation:

Stephanie is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd} and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∩ B.{1,3,5,7,9,11}
{1,3,9}
{3,9}
{3,9,12}

Answers

The outcomes of rolling two cubes are shown in the table below (the outcomes is added up). The members of A are circled while the members of B are boxed. The members of A that also members of B is both circled and boxed.

P(A) = {3, 5, 7, 9, 11}
P(B) = {3, 6, 9, 12}
P(A∩B) = {3,9}

The intersection between the sets are the values that are common to both sets that is {3, 9}