For non-zero denominators, simplify: (3a^3-75a)/(a(a+5)(a+5))

Answers

Answer 1
Answer: (3a^3-75a)/(a(a+5)(a+5))=(3a(a^2-25) )/(a(a+5)(a+5))=(3a(a - 5)(a+5) )/(a(a+5)(a+5)) =(3 (a - 5) )/( (a+5) )



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Find the value of 2 in this equation.

33- (8t) = 15

Answers


33 - 8t = 15
-8t = 15 - 33
-8t = -18
t = -18 / -8
t = 2.25
33-8t=15
33-15=8t
18=8t
18/8=t
t=2.25

Question 4 cjenfjejcjebxjdb

Answers

Answer:

y=1/2x+1

Step-by-step explanation:

slope is 1/2

intercept is 1

Slope is 1/2 and y intercept is 1!

A rectangular box is twice as long as it is wide. The height of the box is 3 feet less than the width. If the box is x feet wide, what polynomial represents its volume in cubic feet?a. b.
c. d.
What is the common difference in the sequence 8, 16, 24, 32, . . .?
a. 24
b. 16
c. –8
d. 8
The floor of a rectangular room will be tiled with square tiles that measure 3 inches on each side. The room is 109 inches long and 103 inches wide. ...

Answers

Hello,

1)
 x= the width
2x=the length
x-3= the height

V=x*2x*(x-3)=2x^3-6x²

2)
16-8=8
24-16=8
32-28=8
difference=8
answer D

3)
a) if you put the squares side by side horizontaly you will need 37*34=1258 squares (for a perfect job)
b) or 109*103/9≈1248 squares (cutting squares)




L is 2 times width
L=2W
heigt is 3 less than width
H=W-3

if W=x

V=??
V=LWH
W=x
L=2x
H=x-3
V=(2x)(x)(x-3)
V=(2x^2)(x-3)
V=2x^3-6x^2




common difference is the nth term minus the n-1 term
basically a term minus the one before it
16-8=8
common differnce is 8




how many tiles
find area of room
area of room=109*103=11227
area of tile=3^2 since it is  asquare or 9
areaof1tile times how many tiles=areaofroom
9*howmany=11227
divide both sids by 9
how many=1247.44444
round up so you have enough (since you can't buy 0.4444 tiles)
how many=1248

1248 tiles

Tommy is drawing a triangle with angles measuring 41° and 123°, and the included side measures 6 cm. What is the measurement of the third angle of the triangle? A) 16°

B) 57°

C) 139°

D) 196°

Answers

Sum of angles in a triangle is 180°. Third angle = 180 - 41 - 123 = 16°

Answer:

A) 16°  Is the right answer

Step-by-step explanation:

Let f(x) = 16x5 – 48x4 – 8x3 and g(x) = 8x2. Find f of x over g of x. a) 2x2 + 6x + 1 b)2x2 – 6x – 1 c)2x3 + 6x2 + x d)2x3 – 6x2 – x

Answers

The answer is d)2x3 – 6x2 – x.

It is given:
f(x)=16 x^(5)-48 x^(4) -8 x^(3)
g(x)=8 x^(2)

We should find:
f( (f(x))/(g(x)) )

So, we just need to replace it in the equation:
f( (f(x))/(g(x)) )= (16 x^(5)-48 x^(4) -8 x^(3))/(8 x^(2))

Let's now separate each member of equation:
f( (f(x))/(g(x)) )= (16 x^(5))/(8 x^(2)) - (48 x^(4))/(8 x^(2)) - (8 x^(3))/(8 x^(2)) = (16)/(8) x^(5-2) -(48)/(8) x^(4-2) -(8)/(8) x^(3-2)

f( (f(x))/(g(x)) )=2 x^(3) -6 x^(2) -x

Answer:

\boxed{\boxed{(f(x))/(g(x))=2x^3-6x^2-x}}

Step-by-step explanation:

Here given that,

f(x) = 16x^5-48x^4-8x^3\n\ng(x) = 8x^2

So (f(x))/(g(x)) will be,

(f(x))/(g(x))=(16x^5-48x^4-8x^3)/(8x^2)

Applying single division,

(16x^5-48x^4-8x^3)/(8x^2)=(16x^5)/(8x^2)-(48x^4)/(8x^2)-(8x^3)/(8x^2)

Simplifying further,

(16x^5)/(8x^2)-(48x^4)/(8x^2)-(8x^3)/(8x^2)=2x^3-6x^2-x

Savvas Realize Tonya’s dog-walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. Beth does not charge a monthly fee for her dog-walking service, but she charges $5 per mile that each dog is walked.


Part A

Choose the equation that can be used to find the number of miles m for which Tonya and Beth would charge the same amount.

A. 20 + 3m = 5m

B. 20 = 3m + 5m

C. 20 + 5m = 3m

D. 20 + m = 8m

Part B

m = _____ miles

Answers

Answer:

A 10 miles

Step-by-step explanation:

If I'm not mistaking I'm pretty sure we can write the two problems with an equal sign between as we're trying to find the same amount.

Using this information, we know that we Automatically have a +20 charge with a 3 dollar charge for every mile walked. Now we have 20+3x=

Now we plug in the 5x to get 20+3x=5x

From here you subtract 3x and you get 20=2x. Now divide!

10=x

Hope this helps! (Side Note: You should probably get some sleep as I'm sure it's pretty late where ever you live. Also, keep trying even if you feel like giving up!) :)