One plant from the garden is randomly selected. There is a 30% chance that the plant was purchased this year, and there is a 6% chance that the plant was purchased this year and produces berries. What is the probability that the chosen plant does NOT produce berries, given that the plant was purchased this year? Write the probability as a percent. Round to the nearest tenth if needed. ____________%

Answers

Answer 1

Answer: Answer and workings in the attachment below. Also, do me one big favour. Let me know if it's the answer your teacher or text book ends up giving you. That would give me some satisfaction.

Answer: 80%

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I need helps please and ty

There is a closed carton of eggs in Mai's refrigerator. The carton contains "e" eggs and it can hold 12 eggs. What are some possible values of e that will make both e < 12 and e > 0 true?

Answers

Answer:

1,2,3,4,5,6,7,8,9,10,11

Step-by-step explanation:

Any integer greater than 0 and less than 12

The would have to be whole numbers since we don't have parts of eggs in an egg carton

1,2,3,4,5,6,7,8,9,10,11

Answer:

A couple of solutions:

-Any numbers from 1-11

-E can also equal 12, or can equal zero (≤ or ≥)

Step-by-step explanation:

The first value is true because 0 and 12 aren't an option because the two equations incudes 0 and 12, but. 12 is greater and 0 is fewer/less than e. This means that it can be around any number from 1-11, so any of those numbers are possible.

The next value can also be a solution because e can equal any number in that batch. This is possible because it can be greater than zero, less than twelve, or it can be equal to any of those.

I hope this helps :)

-EarthGirl

A bill of $424 was paid with $5 bills and $2 bills. A total of 128 bills were used. Howmany of them were fives?

Answers

Answer: 56

Step-by-step explanation:

Let the number of $5 be x

Let the number of $2 be y.

Based on the information given, we can form an equation as:

x + y = 128 ........ i

5x + 2y = 424 ....... ii

Multiply equation i by 2

Multiply equation ii by 1

2x + 2y = 256 ...... iii

5x + 2y = 424 ....... iv

Subtract iii from iv

3x = 168

x = 168/3

x = 56.

Therefore, there were 56 $5 bills.

A 20m ladder and a 15m ladder were leaned against a building. The bottom of the longer ladder was 7m farther from the building than the bottom of the shorter ladder, but both ladders reached the same distance up the building. Find this distance.6m

12m

10m

9m

Answers

Answer:

The correct answer is: d=9m

Step-by-step explanation:

Ok, the ladders leaned against a building make two right triangles with same the same height, which we will call h. For the 20m ladder, its leg is (7+d) and for the 15m ladder, its leg is d, and the two hypotenuses are 20 and 15 respectively.

Then, using the Pythagorean Theorem we have:

20m ladder:

20^2 = h^2 + (d+7)^2 (Eq. 1)

400 = h^2 + d^2 + 2*7*d + 7^2 (expanding the theorem)

400 = (h^2 + d^2) + 14*d + 49 (Eq. 2)

15m ladder:

15^2 = h^2 + (d)^2 (Eq. 3)

Since h^2 + (d)^2 is equal to 15^2, we can substitute (2) into (3):

400 = (15^2) + 14*d + 49

400 = 225 + 14*d + 49

14*d = 400 - 225 - 49 (clearing the variable d)

14*d = 126