on january 1,1999,the price of gasoline was$1.39 per gallon .if the price of gasoline increased by 0.5%per month ,what was the was the cost of one gallon of gasoline,to the nearest cent,on january 1 one year later?

Answers

Answer 1

Answer: $P(t)=1.39.(1.005)^t \ \ \ \ where t \ is \ time \ in \ months\n \n P(1)=1.39.(1.005)^1\n \n P(1)=1.39*1.005\n \n P(1)=\$ \ 1.40$

Answer 2

Answer:

Answer:

$1.40

Step-by-step explanation:

plug into formula

if plugged in right, plug into calculator.

You then should get the total of $1.40. :D

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The table shows the population of a small town over time. The function P = 10,550(1.1)x models the population x years after the year 2000. The function P = 10,550(1.1)x models the population x years after the year 2000. For which year would this model most likely be sufficient to make a prediction of the population? 1950 2005 2025 2050

Multiply and simplify the product.(8 – 5i)2
Select the product.

a. 39

b. 89

c. 39-80i

d. 89-80i

Answers

Simplifying the square of a complex binomial is done similarly to a purely real binomial, except that one was to remember the relation i² = -1.

Solving the equation (8 – 5i)² is done below:

Rewriting (8 – 5i)²:

(8 - 5i)(8 - 5i) = 64 - 40i - 40i + 25i²

Simplifying and applying i² = -1:
64 - 80i + 25(-1)
64 - 80i - 25
39 - 80i

From the choices, the answer is C.

Answer:

39 – 80i

Step-by-step explanation:

Please help I've been stuck on this question for a while now. How do I solve (1/2)^4 (1/2)^-2? It has to do with Multiplying and Dividing Expressions with Exponents. Please show work so I may figure it out on my own.

Answers

The value of the expression is $0.25$

Explanation:

The expression is $\left((1)/(2)\right)^(4)\left((1)/(2)\right)^(-2)$

Since, the base of the expression is the same. Then, by "product rule", when multiplying two powers that have the same base, you can add the exponents.

Thus, we have,

$\left((1)/(2)\right)^(4)\left((1)/(2)\right)^(-2)=\left((1)/(2)\right)^(4-2)$

Adding the exponents, we have,

$\left((1)/(2)\right)^(4)\left((1)/(2)\right)^(-2)=\left((1)/(2)\right)^(2)$

Applying exponent rule, $\left((a)/(b)\right)^(c)=(a^(c))/(b^(c))$ , we have,

$\left((1)/(2)\right)^(2)=(1^(2))/(2^(2))$

Simplifying, we get,

$(1)/(4)$

Dividing, we have,

$0.25$

Thus, the value of the expression is $0.25$

if the range of the function f(x)=x/4 is {28,30,32,34,36}, what is its domain?a. {112, 120, 128, 136, 144}b. {118, 122, 124, 132, 145}c. {110, 118, 122, 124, 137}d. {111, 124, 128, 132, 146}

Answers

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Answers

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Answers

1/2<3/4
.......................

Answer: Is 1/2 greater than 3/4

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