Not sure what to do here? Naomi has 50 red beads and white beads. The number of red beads is 1 more than 6 times the number of white beads. How many red beads does Naomi have?

Answers

Answer 1
Answer:


Naomi has 43 red beads. 7 white beads times 6 equals 42. 42 plus 1 equals 43. Sometimes you just need to guess and check using common sense. Otherwise an equation would be x+(6x+1)=50, which would be 7x+1+50. Then you simplify to 7x=49 and get x=7. Then multiply by 6 and add 1 to get 43


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A football team loses 2 yards every 5 minutes. How many yards did the team lose after 15 minutes?

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Answer:

6 yards

Step-by-step explanation:

Indicate in standard form the equation of the line passing through the given point and having the given slope. D(5, -2) m = 2/5

Answers

Hello,

y+2=2/5(x-5)
==>5y+10=2x-10
==>2x-5y=20

Answer:

2x-5y=20

Step-by-step explanation:

How would I solve 16x^4-41x^2+25=0 ???

Answers

16{ x }^( 4 )-41{ x }^( 2 )+25=0

{ x }^( 4 )={ ({ x }^( 2 )) }^( 2 )\n \n 16{ ({ x }^( 2 )) }^( 2 )-41{ x }^( 2 )+25=0



First of all to make our equation simpler, we'll equal x^(2) to a variable like 'a'.

So,

{ x }^( 2 )=a

Now let's plug x^(2) 's value (a) into the equation.

16{ ({ x }^( 2 )) }^( 2 )-41{ x }^( 2 )+25=0\n \n { x }^( 2 )=a\n \n 16{ (a) }^( 2 )-41{ a }+25=0

Now we turned our equation into a quadratic equation.

(The variable 'a' will have a solution set of two solutions, but 'x' , which is the variable of our first equation will have a solution set of four solutions since it is a quartic equation (fourth-degree equation) )

Let's solve for a.

The formula used to solve quadratic equations ;

\frac { -b\pm \sqrt { { b }^( 2 )-4\cdot t\cdot c }  }{ 2\cdot t }

The formula is used in an equation formed like this :

t{ x }^( 2 )+bx+c=0

In our equation,

t=16 , b=-41 and c=25

Let's plug the values in the formula to solve.

t=16\quad b=-41\quad c=25\n \n \frac { -(-41)\pm \sqrt { -(41)^( 2 )-4\cdot 16\cdot 25 }  }{ 2\cdot 16 } \n \n \frac { 41\pm \sqrt { 1681-1600 }  }{ 32 } \n \n \frac { 41\pm \sqrt { 81 }  }{ 32 } \n \n \frac { 41\pm 9 }{ 32 }

So the solution set :

\frac { 41+9 }{ 32 } =\frac { 50 }{ 32 } \n \n \frac { 41-9 }{ 32 } =\frac { 32 }{ 32 } =1\n \n a\quad =\quad \left\{ \frac { 50 }{ 32 } ,\quad 1 \right\}

We found a's value.

Remember,

{ x }^( 2 )=a

So after we found a's solution set, that means.

{ x }^( 2 )=\frac { 50 }{ 32 }

and

{ x }^( 2 )=1

We'll also solve this equations to find x's solution set :)

{ x }^( 2 )=\frac { 50 }{ 32 } \n \n \frac { 50 }{ 32 } =\frac { 25 }{ 16 } \n \n { x }^( 2 )=\frac { 25 }{ 16 } \n \n \sqrt { { x }^( 2 ) } =\sqrt { \frac { 25 }{ 16 }  } \n \n x=\quad \pm \frac { 5 }{ 4 }

{ x }^( 2 )=1\n \n \sqrt { { x }^( 2 ) } =\sqrt { 1 } \n \n x=\quad \pm 1

So the values x has are :

\frac { 5 }{ 4 } , -\frac { 5 }{ 4 } , 1 and -1

Solution set :

x=\quad \left\{ \frac { 5 }{ 4 } \quad ,\quad -\frac { 5 }{ 4 } \quad ,\quad 1\quad ,\quad -1 \right\}

I hope this was clear enough. If not please ask :)



16x⁴ - 41x² + 25 = 0
16x⁴ - 16x² - 25x² + 25 = 0
16x²(x²) - 16x²(1) - 25(x²) + 25(1) = 0
16(x² - 1) - 25(x² - 1) = 0
(16x² - 25)(x² - 1) = 0
(16x² + 20x - 20x - 25)(x² - x + x - 1) = 0
(4x(4x) + 4x(5) - 5(4x) - 5(5))(x(x) - x(1) + 1(x) - 1(1)) = 0
(4x(4x + 5) - 5(4x + 5))(x(x - 1) + 1(x - 1)) = 0
(4x - 5)(4x + 5)(x + 1)(x - 1) = 0
4x - 5 = 0  or  4x + 5 = 0  or  x + 1 = 0  or  x - 1 = 0
    + 5 + 5             - 5  - 5          - 1  - 1          + 1 + 1
     4x = 5              4x = -5          x = -1             x = 1
      4     4               4      4
       x = 1¹/₄            x = -1¹/₄

The solution set is equal to {(1¹/₄, -1¹/₄, -1, 1)}.

When you divide a number by 1/2, the result is A) half the original number.
B) twice the original number.
C) 50% of the original number.
D) 100% of the original number.

Answers

Let us analyze the following situation: The number we want to divide by 1/2 is X. We can write:
X/(1/2)=(X/1)/(1/2)=(X*2)/(1*1)= X*2,
which means that the number that is divided with 1/2 is multiplied by 2 (twice the original number).
When you divide a number by 1/2, the result is twice the original number . Answer:B
When you divide a number by 1/2, the result is twice the original number . Answer:B

How many prime numbers are there between 56 and 100?

Answers

9.

They are: 59, 61, 67, 71, 73, 79, 83, 89 & 97.

there are nine prime numbers between 56 and hundred

How do you know which operation to perform first when solving an equation?

Answers

u use PEMDAS which means:

P= parenthesis
E= exponents
M= multiplication
D=divide
A=add
S=subtract

THis is in order
can I have brainliest