How are distant regions of the universe similar to space near earth

Answers

Answer 1

Answer: The distant regions of the Universe look older than the space near the Earth. The more distant are, the older is. But the information we can have is lesser due to the distance.

Related Questions

TruE or faults the size of. The population increases if the number of individuals. Attend to population is equal to the number of individuals leaving
You place ice cubes into a glass of lemonade what happens to make the lemonade to get cold
Can wind energy be used in transportation
How many electrons in 0-2?
What are hydrocarbon?

Which one could be the answer

Answers

b would be my answer

If a solution A has twice as much solute as solution B. Is it possible for the solutions to have the same concentration?

Answers

Yes, if solution B has double the mass of solution A.

√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√√v√√√√√√

Are the following physical or chemical changes.1.Lighting a match
2.Cooking waffles
3.Baking a cake

Answers

They are all chemical changes. Think of a chemical change as you can never get something back to the way it was. (A lit match can't be turned back into a new one, waffles can't be turned back into waffle mix, and a cake can't be turned back into cake batter.)

Physical change would be something like slicing cheese or evaporating water. (The sliced cheese is still cheese, and the water turns into steam which can then be turned back into a liquid and it's still water - just in the air.)

chemical reactions because the chemical formula is changed in the reaction

How can friction be helpful when riding a bicycle and how can it be harmful

Answers

Friction can be beneficial because it helps stop a bicycle. It could be harmful when their is too much friction because it can burn the wheel.

1.00 L of gas at a standard temperature and pressure is compressed to 473mL. What is the new pressure of the gas?

Answers

Answer:

The pressure of the gas is 2.11 atm.

Explanation:

From the given,

$V_(1)=1.00\,L$

$P_(1)=1\,atm$

$P_(2)=?$

$V_(2)=473\,ml=0.473\,L$

$P_(1)V_(1)=P_(2)V_(2)$

$(1)(1)=(0.473)(P_(2))$

$P_(2)=((1)(1))/(0.473)=2.11$

Therefore, The pressure of the gas is 2.11 atm.

Final answer:

Boyle's law is used to find the new pressure after the gas is compressed from 1.00 L to 0.473 L. The original pressure is 1 atm at Standard Temperature and Pressure (STP). After the compression, the new pressure is approximately 2.12 atm.

Explanation:

The question relates to gas laws, specifically Boyle's law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and amount of gas are held constant. At Standard Temperature and Pressure (STP; 273.15 K and 1 atm), one mole of an ideal gas occupancies a volume of about 22.4 L. In this case, the initial conditions are at STP, with a gas volume of 1.00 L, equating to a pressure of 1 atm. When this volume is compressed to 473 mL (or 0.473 L), the pressure can be determined using Boyle's law, i.e., P1V1 = P2V2. After substituting the values, we can solve for the new pressure (P2) which will be approximately 2.12 atm.

Learn more about Boyle's Law here:

brainly.com/question/21184611

#SPJ3

When the ocean washes farther up shore

Answers

high tide is when the ocean rises

Other Questions

What happens to the rock along the ridge when new molten material erupts?

Isaac read 32% of oeople owned dogs what fraction of people owned dogs

Does chocolate milk come from brown cows?

C. If 62.9 g of lead (II) chloride is produced, how many grams of lead (II) nitrate werereacted?