How many moles of ca(oh)2 are in 25ml of 1.5 M solution?

Answers

Answer 1
Answer: Molar concentration is

C=(\eta)/(V)

[V]=Liters

[\eta]=mol

\eta=C*V

V=25~mL=0.025~L

\eta=1.5*0.025

\boxed{\boxed{\eta=0.0375~moles}}

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Balance the following oxidation-reduction reaction: Fe(s)+Na+(aq)→Fe2+(aq)+Na(s) Express the coefficients as integers separated by commas (e.g., 4,1,3,2, where 1 indicates the absence of a coefficient).

Answers

Answer:

The answer to your question is: 1, 2, 1, 2

Explanation:

                       1 Fe(s)  + 2 Na⁺(aq)  → 1 Fe²⁺(aq)  + 2 Na(s)

                             Fe⁰   -   2e⁻       ⇒           Fe⁺²        Oxidases

                             Na⁺   +  1 e⁻       ⇒           Na⁰         Reduces

                      1 x ( 1 Fe⁰      ⇒         1 Fe⁺²)      Interchange number of

                      2 x ( 2Na⁺       ⇒       2 Na⁰ )      electrons

Final answer:

To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), follow these steps: balance atoms other than hydrogen and oxygen, balance hydrogen atoms, balance oxygen atoms, verify charges

Explanation:

To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), we need to balance the number of atoms for each element and the total charge on both sides of the reaction. Here's the step-by-step process:

  1. First, balance the atoms other than hydrogen and oxygen. There is only one atom of Fe on each side, so this is already balanced.
  2. Next, balance the hydrogen atoms. We have no hydrogen on the left side and one hydrogen on the right side, so we need to add a coefficient of 2 in front of Na(s): 2Na(s).
  3. Now, balance the oxygen atoms. We have no oxygen on the left side and one oxygen in Fe2+(aq), so we need to add a coefficient of 2 in front of Fe2+(aq): 2Fe2+(aq).
  4. Finally, verify that the charges are balanced. The charge on the left side is 1+ (from Na+) and the charge on the right side is 0 (from Na). To balance the charges, we need to add a coefficient of 2 in front of Na+: 2Na+(aq).

So, the balanced oxidation-reduction reaction is: Fe(s) + 2Na+(aq) → 2Fe2+(aq) + Na(s).

Learn more about Balancing oxidation-reduction reactions here:

brainly.com/question/31991118

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When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion? A.
+2

B.
-1

C.
+1

D.
-2

Answers

D. 2- youre adding two negative charges to a neutral element

The electrical charge of the oxygen ion is -2.

Hydrogen has three isotopes, 1H, 2H, and 3H. What is the difference between these three isotopes?A. The number of protons ranges from 1 to 3.
B. The number of electrons ranges from 1 to 3.
C. The number of neutrons ranges from 0 to 2.
D. The number of protons ranges from 0 to 2.

Answers

The correct answer is C.

A substance is said to exhibit isotopy if the number of proton and neutron in the nucleus of the atom differs, whille the number of proton and electron are the same. Hydrogen has three isotopes and each of the isotopes has different number of neutron. Hydrogen 1 has no neutron but have 1 proton, hydrogen 2 has 1 neutron and 1 proton and hydrogen 3 has 1 proton and 2 neutrons.

C... The number of neutrons ranges from 1H with 0 neutron, 2H with 1 neutron and 3H with 2 neutrons.

Which solution has the lowest freezing point

Answers

bc KI has a lower freezing point than water. this means that the higher ratio of KI to water you have, the lower the freezing point will be. since 3 has the highest ratio of KI to water, it will have the lowest freezing point

A sample of gas at 25ºc has a volume of 11 l and exerts a pressure of 660 mm hg. how many moles of gas are in the sample?

Answers

  The  moles of  the gas    in the sample  is 0.391  moles

    calculation
by use  of  ideal  gas  equation, that  is Pv=nRT
where  n  is number  of moles
           P(pressure)= 660  mmhg
           R(gas  constant)  =  62.364 l.mmhg/mol.K
           T(temperature)= 25 +273 =   298 k

by  making  n  the subject of the  formula

n= Pv/ RT

n is therefore=   (660mm hg  x11 L)/(  62.364 L.mmhg/mol.k  x298 K)  = 0.391  moles

Which is the best metal to use in an alloy to increase its electrical conductivity?Aluminum (Al)
Silver (Ag)
Zinc (Zn)
Antimony (Sb)

Answers

Answer:

Its Silver!

Explanation:

I took a quiz, and i got it right!