When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energy of the system after the collision?

Answers

Answer 1
Answer: I can say that the kinetic energy after the collision is less than it was before the collision.  I can say this with confidence because you've said that some energy was used to deform the car, plus there was energy lost from the system in the form of heat.
Answer 2
Answer:

Answer:

B. The kinetic energy of the system is partially used for deforming the car.

Explanation:

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Which alternative energy source would be expected to be the least dependent upon the weather?a. wind power
b. solar power
c. geothermal power
d. none of the above

Answers

Answer;

C. geothermal power

Explanation;

Geothermal power is considered to be a sustainable, renewable source of energy because the heat extraction is small compared with the Earth's heat content. It depends the least on weather.

Geothermal energy is the heat from the Earth. It's clean and sustainable. Resources of geothermal energy range from the shallow ground to hot water and hot rock found a few miles beneath the Earth's surface, and down even deeper to the extremely high temperatures of molten rock called magma.

Of the three sources listed, geothermal energy
is the least dependent on the weather.
(Once it's installed and running, that is.)

Which describes the changes in visible light moving from red to violet?

Answers


As you move from red to violet, the wavelength of the light waves
gets shorter, and the frequency gets higher.  Also, each photon
carries more energy as you move in that direction.  One photon
of violet light carries roughly twice as much energy as one photon
of red light does.

An object traveling in a straight line accelerates. What will definitely happen due to the acceleration?

Answers

"Acceleration" means any change in speed or direction of motion. 
If the object is known to be accelerating even though it's traveling
in a straight line, then we know that its speed must be changing.

Sehidy the given figure and calculate the load distance. Given: 325 N, 40 cm Unknown: 650 N, ?

Answers

the load distance is approximately 0.2 meters or 20 cm. To calculate the load distance in this scenario, we can use the principle of moments, which states that the sum of clockwise moments about a point is equal to the sum of counterclockwise moments about the same point when an object is in equilibrium.

In this case, we have two forces:

1. A known force of 325 N applied at a distance of 40 cm (0.4 meters) from the point of interest.

2. An unknown force of 650 N applied at an unknown distance, which we need to find.

Let's assume the unknown distance is "d" meters.

Using the principle of moments:

Clockwise Moment = Counterclockwise Moment

(325 N) * (0.4 m) = (650 N) * (d m)

Solving for "d":

d = (325 N * 0.4 m) / 650 N

d ≈ 0.2 meters

So, the load distance is approximately 0.2 meters or 20 cm.

To know more about moments:

brainly.com/question/33127998

#SPJ1

A slingshot is used to launch a stone horizontally from the top of a 20.0 meter cliff. The stone lands 36.0 meters away.a. At what speed was the stone launched?
b. What is the speed and angle of impact?

Answers

As per the question a stone is projected horizontally  from the top of a 20 meter  cliff.

Hence the height [h] of the cliff = 20 m.

The stone lands 36.0 m away.

Hence horizontal distance R] = 36 m.

First we are asked to calculate the launching speed of the stone.

Let it be denoted as u.

The motion of particle is the force of gravity only.Hence it is a projectile motion.

The total time taken by a projectile when it is fired horizontally at a height h from the ground is -

                        T=\sqrt{(2h)/(g) }   [ where g is the acceleration due to gravity = 9.8 m/s^2 or 10 m/s^2]

                                =\sqrt{(2*20)/(10) } s

                                 = 2 s

The range of the projectile will be-

                                               R= \ horizontal\ speed*\ total\ time\ of\ flight

The horizontal speed for a projectile is uniform through out the motion of the projectile as long as gravity is constant.

In this  situation the horizontal velocity is equal to the initial projected speed i.e u.

Hence horizontal distance R = u ×T

Putting the value or R and T in the above formula we get-

                             R=u*\sqrt{(2h)/(g) }

                             36 = u*\sqrt{(2*20)/(10) }

                             36 = u*2

                             u =(36)/(2)

                             u =18 m/s

Now we are asked to calculate the angle of impact.

Initially the vertical velocity of the particle is 0. The path of the trajectory of the particle will be parabolic due to the force of gravity.At any instant of time  the horizontal component of the instantaneous velocity of the of the particle will be constant .

Let the horizontal component is denoted as V_(x) \ where \ V_(x) = u

The vertical component is calculated as follows-

We know that   v = u +at  

Here v is the final velocity, u is the initial speed, a is the acceleration and t is the instantaneous time.

For vertically downward motion under gravity u = 0 and a = -g

Let the vertical velocity at any instant is denoted as V_(y)

Hence

            V_(y) = 0 -gt

            V_(y) = gt   [Here we are taking only the magnitude]

Let the resultant velocity makes an angle α with the horizontal when it strikes the ground.

The horizontal and vertical component is denoted in the diagram below-

From the figure we see that -

                                      tan\alpha =(V_(y) )/(V_(x) )

                                      tan\alpha =(gt)/(u)

                                      tan\alpha =(10*2)/(18)

                                      tan\alpha =1.11111

                                      \alpha =48.01^0    [ans]

Hence the angle of impact is close to 48 .1 degree .


A) 

     It is a launch oblique, therefore the initial velocity in the vertical direction is zero. Space Hourly Equation in vertical, we have:

S=S_(o)+v_(o)t+ (at^2)/(2) \n 20= (10t^2)/(2) \n t=2s
 
     Through Definition of Velocity, comes:

\Delta v=  (\Delta S)/(\Delta t)  \n v_x= (36)/(2)  \n \boxed {v_(x)=18m/s}


B)
 
     Using the Velocity Hourly Equation in vertical direction, we have:

v_(y)=v_{y_(o)}+gt \n v_(y)=10*2 \n \boxed {v_(y)=20m/s}
  
     The angle of impact is given by:

cos(\theta) =(v_(x))/(v_(y))  \n cos(\theta) = (18)/(20)  \n cos(\theta) =0.9 \n arccos(0.9)=\theta \n \boxed {\theta \approx 25.84}


If you notice any mistake in my english, please let me know, because i am not native.

Atoms may be bonded together by losing, gaining, or sharing _____________. Question 1 options: A, photons
B. energy
C. electrons
D. neutrons
E. protons

Answers

Answer: Option (C) is the correct answer.

Explanation:

An atom consists of three subatomic particles which are protons, neutrons and electrons.

The protons and neutrons are present inside the nucleus. Whereas electrons revolve around the nucleus.

Whenever there is a bond formed by loss, gain or sharing between any two atoms then it is due to the electrons.

Hence, we can conclude that atoms may be bonded together by losing, gaining, or sharing electrons.

D. neutrons , is fit....