A coil is connected to a 100v d.c. supply and takes a current of 10A. Calculate the value of the resistance of the coil

Answers

Answer 1

Answer: Resistance = (voltage) divided by (current)

Resistance = (100 volts) / (10 Amperes) = 10 ohms

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List the following items in order of decreasing speed, from greatest to least: (i) A wind-up toy car that moves 0.15 m in 2.5 s. (ii) A soccer ball that rolls 2.3 m in 0.55 s. (iii) A bicycle that travels 0.60 m in 0.075 s. (iv) A cat that runs 8.0 m in 2.0 s. Knight, Randall D., (Professor Emeritus). College Physics (p. 28). Pearson Education. Kindle Edition.

Answers

Answer:

(iii) > (ii) > (iv) > (i)

Explanation:

Part (i):

$\textrm{Speed of the wind-up toy} = \frac{\textrm{distance traveled}}{\textrm{Time taken}}\n\Rightarrow v_1=(0.15\ m)/(2.5\ s)\n\Rightarrow v_1 = 0.06\ m/s$

Part (ii):

$\textrm{Speed of the soccer ball} = \frac{\textrm{distance traveled}}{\textrm{Time taken}}\n\Rightarrow v_2=(2.3\ m)/(0.55\ s)\n\Rightarrow v_2 = 4.18\ m/s$

Part (iii):

$\textrm{Speed of the bicycle} = \frac{\textrm{distance traveled}}{\textrm{Time taken}}\n\Rightarrow v_3=(0.66\ m)/(0.075\ s)\n\Rightarrow v_3 = 8.8\ m/s$

Part (iv):

$\textrm{Speed of the cat} = \frac{\textrm{distance traveled}}{\textrm{Time taken}}\n\Rightarrow v_4=(8.0\ m)/(2.0\ s)\n\Rightarrow v_4 = 4.0\ m/s$

From the above calculations, we have

$v_3>v_2>v_4>v_1$

So, the speed in the parts mentioned arranged in decreasing order as follow:

(iii) > (ii) > (iv) > (i)

A 1kg object loses 20 j of gpe as it falls how far does it fall

Answers

Gravitational potential energy (GPE) is energy within an object with respect to its height. The equation of gpe is:

GPE = mgh

where:
m = mass of object
g = gravitational constant, 9.81 m/s^2
h = height

For a given gpe of 20 J, the height can be calculated as follows:
*Remember to be consistent with units. Since Joule is derived from SI units, make sure to use SI units for the other variables

GPE = 20 J = 1 (9.81) (h)
h = 2.04 meters

The height of the Empire State Building is 318.00 meters. If a stone is dropped from the top of the building, what is the stone's velocity just before it strikes the ground?

Answers

This is a free-fall problem. This can be answered using one of the free-fall equations:

V^2 = 2gh or V = √(2gh)

Where V = velocity ; h = total height (given as 318m) ; g = acceleration due to gravity (as this is on Earth, let us use 9.8 m/s^2)

With the given values, we can substitute it into the equation directly like so:

V = √(2gh)
V = √(2 x 9.8 x 318)
V = √(6232.8)
V = 78.94808 or approximately 78.95 m/s

Therefore the stone's velocity just before hitting the ground is 78.95 m/s.

A metal object is suspended from a spring scale. The scale reads 930 N when the object is suspended in air, and 731 N when the object is completely submerged in water. Find the volume of the object. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m3 .

Answers

Answer:

The volume of the object = 0.0203 m³

Explanation:

From Archimedes principle,

Upthrust = lost in weight = amount of water displaced.

U = W₁ - W₂

Where U = upthrust, W₁ = Weight in air, W₂ = weight in water.

U = 930- 731

U = 199 N.

but mass of water displaced,

m = U/g where g = 9.8 m/s²

m = 199/9.8

m = 20.31 kg.

Recall,

Density = mass/volume.

Density of water = mass of water displaced/ volume of water displaced

D = m/V

V = m/D......................................... Equation 1

Where V = volume of water displaced, m = 20.31 kg, D = 1000 kg/m³

Substitute into equation 1

V = 20.31/1000

V = 0.0203 m³

the volume of water displaced = 0.0203 m³

Note: That when an object is immersed in water, the volume of water it displaced is equal to it's volume.

Hence, Volume of water displaced = volume of the object.

Hence the volume of the object = 0.0203 m³

Which of the following is not a unit of pressure? a. atmosphere b. psi c. N/m^2 d. mm of mercury e. pascal f. They are all units of pressure.

Answers

Answer:

(A) Atmosphere.

Explanation:

The atmosphere is a thing, not a unit of measurement. (this is the simplified version)

Pls mark brianlist

Which particles are not affected by the strong force?

Answers

The particles which are not affected by the strong force are Electrons.

What are electrons?

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

Atom/Molecules undergo electrostatic force between the electrons present in them. These forces are not broken by the very strong force even like nuclear forces.

Thus, the particles which are not affected by the strong force are Electrons.

Learn more about electrons.

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Answer:

The answer is an Electron

Explanation:

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