Please can some one explaine fore me What is work done

Answers

Answer 1
Answer: In Physics, 'work' has a very clear definition:

It's (strength of a force) times (distance through which the force acts).

'Work' has the units of Energy.

If you push against a shopping cart with 30 newtons of force, and
you keep pushing while the cart moves 4 meters, then you have
done (30 x 4) = 120 newton-meters of work = 120 "Joules". 

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The function ​f(x)equalsnegative 0.25 (x minus 2 )squared plus 8 models the path of a volleyball when the player is 2 feet from the net. The height of the net is 7 ft comma 4 in. Will the ball go over the​ net? What if the player moves back so she is 4 feet from the​ net? Explain.

Answers

Answer:

The ball will go over the net when she's standing 2 feet away from the net, but not at 4 ft from the net

Explanation:

Suppose f(x) = -0.25(x-2)^2 + 8 then when the player is 2ft from the net, we can plug in x = 2:

f(2) = -0.25(2-2)^2 + 8 = 0 + 8ft

As 8 feet > 7 ft 4 in, the ball will go over the net

If the player moves back so that she's 4 feet from the net, plug in x = 4:

f(4) = -0.25(4 - 2)^2 + 8 = -1 + 8 = 7 ft

As 7 ft < 7 ft 4 in, this time the ball will NOT go over the net

Final answer:

The function ​models the path of a volleyball when the player is 2 feet from the net and will the ball go over the net at different distances.

Explanation:

The function f(x) = -0.25(x-2)^2 + 8 models the path of a volleyball when the player is 2 feet from the net. To determine if the ball will go over the net, we need to compare the height of the ball's path with the height of the net.

First, let's convert the height of the net to feet. The height, 7 ft 4 in, is equivalent to 7.33 feet. Now, substitute x = 2 into the function to find the height of the ball when the player is 2 feet from the net. f(2) = -0.25(2-2)^2 + 8 = 8 ft.

The ball will go over the net because the height of the ball, 8 feet, is greater than the height of the net, 7.33 feet.

If the player moves back so she is 4 feet from the net, substitute x = 4 into the function: f(4) = -0.25(4-2)^2 + 8 = 10 ft. The ball would still go over the net, as the height of the ball, 10 feet, is greater than the net's height.

Learn more about volleyball here:

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What is your rate in miles/hour if you tun at a speed of 2.2 miles in 20 minutes

Answers

you need to convert minutes to hours so 
(2.2 mi)/(20 min) x  (60 min)/(1 hr) =  (6.6 mi)/(1 hr)

A crate with a mass of 3.00 kg starts from rest at the top of a 27.0∘ incline and slides 2.00 m down the incline in 1.60 s. (a) What is the magnitude of the acceleration of the crate (in m/s² )? (b) What is the frictional force (in N) acting on the crate? (Enter the magnitude.) (c) What is the coefficient of kinetic friction between the crate and the incline? (d) What is the speed of the crate (in m/s ) after it has slid 2.00 m ?

Answers

Answer:

2.00 m/s. Brainliest appreciated, you’re welcome

Wave A has a long fetch. Wave B has a short fetch. Which of the following statements is true? Wave A is more powerful than Waveb. Wave B is more powerful than Wave
a. Both waves are equally powerful.

Answers

Answer

Correct answer is

wave A is more powerful than wave B

Explanation

Fetch  of a wave is the length of water over which a wind blow. It is clear that the wave which has longer fetch will have higher energy level. And higher energy level wave will be more powerful that wave which has short fetch. hence wave A which has longer fetch than wave B will be more powerful that wave B.

The following statement that is true is : wave A is more powerful than wave B

Longer Fetch tend to create a higher energy level, which make the wave with longer fetch is stronger than the one with shorter fetch

A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50 m × 0.15 m. The elevator is moving upward with an acceleration of magnitude 1.6 m/s2. What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

Answers

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

F=m*a\n

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

F=m*g+m*a=m*(g+a)

F=205.2N

We know that the pressure is given by:

P=(F)/(A)\nP=(205.2N)/((0.50m)*(0.15m))\nP=2736N/m^2=2736Pa

If a force does not act parallel to the resulting displacement, what is the effect on the work done by the force?

Answers

Then only the component of the force that's parallel to the displacement
is used to calculate the work.  The component of force that's perpendicular
to the displacement  doesn't move through any distance at all, so its contribution
to the total work is zero.