sophia exerts a steady 40n horizontal force on a 8kg resting on a lab bench. the box slides against a horizontal friction of 24n. show that the box accelerates at 2m/s 2

Answers

Answer 1

Answer: Force = 40 - 24 = 16N

Force = mass / acceleration

Acceleration = Force / mass

Acceleration = 16 / 8

Acceleration = 2 m/s^2

Answer 2

Answer: Force = 40 - 24
= 16N.

Thus, Force = 16N.

By deducing Newton's second law of motion,

F = MA

16 = 8A

Thus, A = 16/8 = 2 m/s²

Thus, the object accelerates at 2m/s²

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The question didnt fit in the are provided

If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of the bodyA-17 m/s
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If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, the average velocity of the body is 21.5 m/s. the answer is letter D. Velocity is a vector quantity and average velocity can be defined as the sum of the initial and final velocity divided by 2 at constant acceleration.

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Answers

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